Chapter 3: Problem 21
Find the polynomial in \(P_{2}\) whose coordinate vector relative to the ordered basis \(B=\) \(\left(x+x^{2}, x-x^{2}, 1+x\right)\) is \([3,1,2]\).
Short Answer
Expert verified
The polynomial is \( p(x) = 2x^2 + 6x + 2 \).
Step by step solution
01
Understanding the Problem
We need to express a polynomial in the basis \( B = \left(x+x^{2}, x-x^{2}, 1+x\right) \) as a linear combination of the basis polynomials. The coordinate vector \([3,1,2]\) gives the coefficients of these polynomials in their order in the basis.
02
Express Polynomial as Linear Combination
Write the polynomial as a linear combination of the basis vectors: \[ p(x) = 3(x+x^2) + 1(x-x^2) + 2(1+x) \]
03
Distribute the Scalar Multiplication
Apply the scalars from the coordinate vector to the corresponding basis vectors:\[ p(x) = 3x + 3x^2 + x - x^2 + 2 + 2x \]
04
Combine Like Terms
Simplify \( p(x) \) by combining like terms:- Combine the \(x^2\) terms: \(3x^2 - x^2 = 2x^2\)- Combine the \(x\) terms: \(3x + x + 2x = 6x\)- The constant term is \(2\).Thus, \[ p(x) = 2x^2 + 6x + 2 \]
05
Verify the Solution
Check that the polynomial forms the specified coordinate vector over the basis:- The coefficient of \(x+x^2\) is 3.- The coefficient of \(x-x^2\) is 1.- The coefficient of \(1+x\) is 2.All conditions match the coordinate vector \([3, 1, 2]\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Basis
In mathematics, particularly in linear algebra, the concept of a polynomial basis is fundamental for understanding polynomial expressions in vector spaces. A polynomial basis is essentially a set of polynomials that can be used to express any polynomial in a given space uniquely. For example, in our exercise, the basis
- \(B = \{x+x^2, x-x^2, 1+x\}\)
Linear Combination
A linear combination involves expressing a polynomial as a sum where each term is a product of a coefficient and a basis polynomial. In this exercise, the polynomial is expressed as the linear combination:
\( p(x) = 3(x+x^2) + 1(x-x^2) + 2(1+x) \)
Each coefficient corresponds to the respective polynomial in the basis. Here:
\( p(x) = 3(x+x^2) + 1(x-x^2) + 2(1+x) \)
Each coefficient corresponds to the respective polynomial in the basis. Here:
- \(3\) multiplies \(x+x^2\)
- \(1\) multiplies \(x-x^2\)
- \(2\) multiplies \(1+x\)
Coordinate Vector
The coordinate vector in the context of a polynomial basis represents the weights, or coefficients, used in forming the linear combination of the basis polynomials. For the exercise, the coordinate vector
\([3, 1, 2]\)
indicates how each basis polynomial contributes to the total polynomial.
\([3, 1, 2]\)
indicates how each basis polynomial contributes to the total polynomial.
- The first coefficient \(3\) shows the contribution from the polynomial \(x+x^2\).
- The second coefficient \(1\) affects the polynomial \(x-x^2\).
- The third coefficient \(2\) acts on \(1+x\).
Polynomial Simplification
Simplifying a polynomial refers to the process of combining like terms and reducing the polynomial to its simplest form. In our exercise, after expressing the polynomial as a linear combination and distributing the scalars, we have:
\( p(x) = 3x + 3x^2 + x - x^2 + 2 + 2x \)
To simplify, we combine like terms:
\( p(x) = 2x^2 + 6x + 2 \)
Simplification is crucial for obtaining accurate and reduced forms of polynomials, which are easier to work with and analyze in both mathematical and applied contexts.
\( p(x) = 3x + 3x^2 + x - x^2 + 2 + 2x \)
To simplify, we combine like terms:
- Combine the quadratic terms: \(3x^2 - x^2 = 2x^2\)
- Add the linear terms: \(3x + x + 2x = 6x\)
- The constant term remains \(2\).
\( p(x) = 2x^2 + 6x + 2 \)
Simplification is crucial for obtaining accurate and reduced forms of polynomials, which are easier to work with and analyze in both mathematical and applied contexts.