Chapter 1: Problem 10
Compute the given linear combination of \(\mathbf{u}=[1,2,1,0], \mathbf{v}=[-2,0,1,6]\), and \(\mathbf{w}=[3,-5,1,-2]\). $$3 \mathrm{u}+\mathrm{v}-\mathrm{w}$$
Short Answer
Expert verified
The result of the linear combination is \([-2, 11, 3, 8]\).
Step by step solution
01
Distribute Scalar to Vector \( \mathbf{u} \)
Multiply each component of vector \( \mathbf{u} = [1, 2, 1, 0]\) by the scalar 3. \(3 \mathbf{u} = 3 \times [1, 2, 1, 0] = [3, 6, 3, 0]\)
02
Multiply Vector \( \mathbf{v} \) by 1
Since the expression \( +\mathbf{v} \) is equivalent to multiplying \( \mathbf{v} \) by 1, simply keep vector \( \mathbf{v} \) unchanged. \( \mathbf{v} = [-2, 0, 1, 6]\)
03
Calculate Negative of Vector \( \mathbf{w} \)
Multiply each component of vector \( \mathbf{w} = [3, -5, 1, -2]\) by -1 to find \( -\mathbf{w} \). \(-\mathbf{w} = -1 \times [3, -5, 1, -2] = [-3, 5, -1, 2]\)
04
Add the Vectors Together
Add the results from Steps 1, 2, and 3 component-wise: \[3 \mathbf{u} + \mathbf{v} - \mathbf{w} = [3, 6, 3, 0] + [-2, 0, 1, 6] + [-3, 5, -1, 2].\]Add each corresponding component: - \((3) + (-2) + (-3) = -2\)- \((6) + (0) + (5) = 11\)- \((3) + (1) + (-1) = 3\)- \((0) + (6) + (2) = 8\)
05
Final Step: Write the Result
Combine the sums from Step 4 into a single vector: \([-2, 11, 3, 8]\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Addition
Vector addition is a fundamental concept in linear algebra, where we combine two or more vectors to produce a new vector. This process involves adding each pair of corresponding components from the vectors. Imagine you have two vectors, \( \mathbf{a} = [a_1, a_2, a_3] \) and \( \mathbf{b} = [b_1, b_2, b_3] \). To add these vectors, you perform the addition component-wise:
- First component: \( a_1 + b_1 \)
- Second component: \( a_2 + b_2 \)
- Third component: \( a_3 + b_3 \)
Scalar Multiplication
Scalar multiplication involves stretching or compressing a vector by a scalar (a single number). Think of a vector \( \mathbf{v} = [v_1, v_2, v_3] \). When you multiply it by a scalar \( k \), you multiply each component of the vector by \( k \), resulting in a new vector:
- First component: \( k \times v_1 \)
- Second component: \( k \times v_2 \)
- Third component: \( k \times v_3 \)
Linear Algebra Problem
Linear algebra problems often involve operations like vector addition and scalar multiplication. These operations are used to solve a range of problems including systems of equations, projections, and transformations. In a typical linear algebra problem, such as computing a linear combination of vectors, you might need to work with expressions like \( 3\mathbf{u} + \mathbf{v} - \mathbf{w} \). To solve such problems, break down each term into simpler operations:
- Apply scalar multiplication: Scale vectors by appropriate scalars.
- Use vector addition/subtraction: Add or subtract vectors component-wise.
Coordinate Calculation
Coordinate calculation involves determining the specific components of a vector as a result of linear algebra operations. In our example problem, we are computing \( 3\mathbf{u} + \mathbf{v} - \mathbf{w} \). Each vector has components represented as coordinates which need to be precisely calculated to determine the final vector:
- Step 1: Calculate \( 3\mathbf{u} \), multiplying each component by 3.
- Step 2: Consider \( \mathbf{v} \), which remains unchanged.
- Step 3: Find \(-\mathbf{w} \) by reversing the sign of each component.
- Step 4: Add results for each component from the previous steps to find the final coordinates.