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Find formulas for the inverses of the following matrices, when they are not singular: (a) \(\left(\begin{array}{lll}1 & a & b \\ 0 & 1 & c \\ 0 & 0 & 1\end{array}\right)\) (b) \(\left(\begin{array}{lll}a & b & c \\ 0 & d & e \\ 0 & 0 & f\end{array}\right)\) When are these matrices singular?

Short Answer

Expert verified
Matrix (a) is never singular. Matrix (b) is singular if any of \(a, d,\) or \(f\) is zero. The inverse of (a) is \( \begin{pmatrix} 1 & -a & (ac-b) \\ 0 & 1 & -c \\ 0 & 0 & 1 \end{pmatrix} \) and (b) is \( \begin{pmatrix} \frac{1}{a} & -\frac{b}{ad} & \frac{be-c}{adf} \\ 0 & \frac{1}{d} & -\frac{e}{df} \\ 0 & 0 & \frac{1}{f} \end{pmatrix} \).

Step by step solution

01

Understanding Matrix (a)

Matrix (a) is a lower triangular matrix given by \( A = \begin{pmatrix} 1 & a & b \ 0 & 1 & c \ 0 & 0 & 1 \end{pmatrix} \). A lower triangular matrix is singular if any of its diagonal elements are zero. Since the diagonal elements of this matrix are all 1, it is non-singular.
02

Finding the Inverse for Matrix (a)

To find the inverse of a lower triangular matrix, we can use the fact that the inverse of such a matrix is also a lower triangular matrix with 1s on the main diagonal. The inverse of \( A \) can be determined as: \( A^{-1} = \begin{pmatrix} 1 & -a & (ac-b) \ 0 & 1 & -c \ 0 & 0 & 1 \end{pmatrix} \).
03

Verifying the Inverse for Matrix (a)

To verify, we multiply \( A \) with \( A^{-1} \). Computing the product results in the identity matrix \( I \). Thus, our inverse is correct since \( AA^{-1} = I \).
04

Understanding Matrix (b)

Matrix (b) is an upper triangular matrix given by \( B = \begin{pmatrix} a & b & c \ 0 & d & e \ 0 & 0 & f \end{pmatrix} \). It is singular if any of its diagonal elements \( a, d, \) or \( f \) are zero.
05

Finding the Inverse for Matrix (b)

The inverse of an upper triangular matrix can be found if all the diagonal elements are non-zero. The formula for the inverse is \( B^{-1} = \begin{pmatrix} \frac{1}{a} & -\frac{b}{ad} & \frac{be-c}{adf} \ 0 & \frac{1}{d} & -\frac{e}{df} \ 0 & 0 & \frac{1}{f} \end{pmatrix} \).
06

Verifying the Inverse for Matrix (b)

Multiply \( B \) with \( B^{-1} \). The result is the identity matrix \( I \), confirming the correctness of the inverse since \( BB^{-1} = I \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Triangular Matrices
Triangular matrices are a special kind of square matrix that are categorized into two types: lower triangular and upper triangular matrices. These matrices are defined by the position of their non-zero elements.

A **lower triangular matrix** has all its non-zero elements on or below the main diagonal. This means that all the elements above the main diagonal are zero. An example would be the matrix:
  • \[\begin{pmatrix}1 & 0 & 0 \2 & 1 & 0 \3 & 4 & 1\end{pmatrix}\]
An **upper triangular matrix** is one where all the non-zero elements are on or above the main diagonal. Consequently, all elements below the main diagonal are zero. Consider this matrix:
  • \[\begin{pmatrix}5 & 6 & 7 \0 & 8 & 9 \0 & 0 & 10\end{pmatrix}\]
Triangular matrices are particularly useful in linear algebra because their structure simplifies many calculations, such as finding the determinant or solving systems of linear equations using methods like back substitution for upper triangular matrices or forward substitution for lower ones.
Singularity of Matrices
The singularity of a matrix is a crucial concept in linear algebra. A matrix is considered **singular** if it does not have an inverse. This can happen when the determinant of the matrix is zero. Singularity is important because only non-singular matrices, also known as invertible matrices, can be used to solve systems of linear equations or be inverted.

For **triangular matrices**, singularity is directly linked to their diagonal elements. A lower or upper triangular matrix is singular if any of its diagonal elements are zero. The reason for this is straightforward: the determinant of a triangular matrix is simply the product of its diagonal elements. If one of these elements is zero, then the entire product is zero, making the matrix singular.

In the exercise, Matrix (a) is non-singular because all its diagonal elements are one. Similarly, for Matrix (b), if any of the diagonal elements \(a, d,\) or \(f\) is zero, then it becomes singular.
Matrix Diagonal Elements
Diagonal elements of a matrix are those entries located on its main diagonal. The main diagonal runs from the top left to the bottom right of a square matrix. These elements play a significant role in determining several properties of the matrix, including inversion and singularity.

In triangular matrices, the diagonal elements are especially critical because they contribute directly to the matrix's determinant. As noted previously, the determinant dictates whether a matrix is singular or non-singular. Consequently, if any diagonal element of a triangular matrix is zero, the entire matrix becomes singular, meaning it has no inverse.

Diagonal elements also appear prominently in the calculation of a matrix's inverse, especially for triangular matrices. For an upper triangular matrix, the inverse often involves reciprocals of the diagonal elements when those elements are non-zero. For instance, as seen in Matrix (b) from the exercise, the inverse formula is directly dependent on terms like \(\frac{1}{a}\), \(\frac{1}{d}\), and \(\frac{1}{f}\), assuming these elements are non-zero.

This dependency highlights why maintaining non-zero values on the diagonal is key to ensuring the matrix's invertibility. Understanding and manipulating diagonal elements is fundamental when working with matrix operations such as inversion, which is crucial for solving many linear algebra problems efficiently.

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Most popular questions from this chapter

Compute \(\exp (A)\) for the following matrices: \(A=\left(\begin{array}{ll}\lambda & 0 \\ 0 & \lambda\end{array}\right)\) \(A=\left(\begin{array}{ll}1 & \lambda \\ 0 & 1\end{array}\right)\) \(A=\left(\begin{array}{ll}0 & \lambda \\ 0 & 0\end{array}\right)\)

(a) Let \(A=\left(\begin{array}{rrr}1 & 2 & 0 \\ 3 & -1 & 4\end{array}\right)\). Find \(A A^{T}\) and \(A^{T} A\) and their traces. (b) Let \(M\) be any \(m \times n\) matrix. Show that \(M^{T} M\) and \(M M^{T}\) are symmetric. (Hint: use the result of the previous problem.) What are their sizes? What is the relationship between their traces?

Show that if the range (remember that the range of a function is the set of all its outputs, not the codomain) of a \(3 \times 3\) matrix \(M\) (viewed as a function \(\left.\mathbb{R}^{3} \rightarrow \mathbb{R}^{3}\right)\) is a plane then one of the columns is a sum of multiples of the other columns. Show that this relationship is preserved under EROs. Show, further, that the solutions to \(M x=0\) describe this relationship between the columns.

Left and Right Inverses: So far we have only talked about inverses of square matrices. This problem will explore the notion of a left and right inverse for a matrix that is not square. Let $$ A=\left(\begin{array}{lll} 0 & 1 & 1 \\ 1 & 1 & 0 \end{array}\right) $$ (a) Compute: i. \(A A^{T}\), ii. \(\left(A A^{T}\right)^{-1}\), iii. \(B:=A^{T}\left(A A^{T}\right)^{-1}\) (b) Show that the matrix \(B\) above is a right inverse for \(A,\) i.e., verify that $$ A B=I $$ (c) Is \(B A\) defined? (Why or why not?) (d) Let \(A\) be an \(n \times m\) matrix with \(n>m\). Suggest a formula for a left inverse \(C\) such that $$ C A=I $$ Hint: you may assume that \(A^{T} A\) has an inverse. (e) Test your proposal for a left inverse for the simple example $$ A=\left(\begin{array}{l} 1 \\ 2 \end{array}\right) $$ (f) True or false: Left and right inverses are unique. If false give a counterexample.

This exercise is meant to show you a generalization of the procedure you learned long ago for finding the function \(m x+b\) given two points on its graph. It will also show you a way to think of matrices as members of a much bigger class of arrays of numbers. Find the (a) constant function \(f: \mathbb{R} \rightarrow \mathbb{R}\) whose graph contains (2,3) . (b) linear function \(h: \mathbb{R} \rightarrow \mathbb{R}\) whose graph contains (5,4) . (c) first order polynomial function \(g: \mathbb{R} \rightarrow \mathbb{R}\) whose graph contains (1,2) and (3,3) (d) second order polynomial function \(p: \mathbb{R} \rightarrow \mathbb{R}\) whose graph contains (1,0),(3,0) and (5,0) (e) second order polynomial function \(q: \mathbb{R} \rightarrow \mathbb{R}\) whose graph contains (1,1),(3,2) and (5,7) (f) second order homogeneous polynomial function \(r: \mathbb{R} \rightarrow \mathbb{R}\) whose graph contains (3,2) (g) number of points required to specify a third order polynomial \(\mathbb{R} \rightarrow \mathbb{R}\) (h) number of points required to specify a third order homogeneous polynomial \(\mathbb{R} \rightarrow \mathbb{R}\) (i) number of points required to specify a n-th order polynomial \(\mathbb{R} \rightarrow\) \(\mathbb{R}\) (j) number of points required to specify a n-th order homogeneous polynomial \(\mathbb{R} \rightarrow \mathbb{R}\) (k) first order polynomial function \(F: \mathbb{R}^{2} \rightarrow \mathbb{R}\) whose graph contains \(\left(\left(\begin{array}{l}0 \\ 0\end{array}\right), 1\right),\left(\left(\begin{array}{l}0 \\ 1\end{array}\right), 2\right),\left(\left(\begin{array}{l}1 \\ 0\end{array}\right), 3\right),\) and \(\left(\left(\begin{array}{l}1 \\ 1\end{array}\right), 4\right)\) (l) homogeneous first order polynomial function \(H: \mathbb{R}^{2} \rightarrow \mathbb{R}\) whose graph contains \(\left(\left(\begin{array}{l}0 \\\ 1\end{array}\right), 2\right),\left(\left(\begin{array}{l}1 \\\ 0\end{array}\right), 3\right),\) and \(\left(\left(\begin{array}{l}1 \\\ 1\end{array}\right), 4\right)\). \((\mathrm{m})\) second order polynomial function \(J: \mathbb{R}^{2} \rightarrow \mathbb{R}\) whose graph con\(\operatorname{tains}\left(\left(\begin{array}{l}0 \\\ 0\end{array}\right), 0\right),\left(\left(\begin{array}{l}0 \\\ 1\end{array}\right), 2\right),\left(\left(\begin{array}{l}0 \\\ 2\end{array}\right), 5\right)\) \(\left(\left(\begin{array}{l}1 \\ 0\end{array}\right), 3\right),\left(\left(\begin{array}{l}2 \\ 0\end{array}\right), 6\right),\) and \(\left(\left(\begin{array}{l}1 \\ 1\end{array}\right), 4\right)\) (n) first order polynomial function \(K: \mathbb{R}^{2} \rightarrow \mathbb{R}^{2}\) whose graph contains\(\left(\left(\begin{array}{l}0 \\\ 0\end{array}\right),\left(\begin{array}{l}1 \\\ 1\end{array}\right)\right),\left(\left(\begin{array}{l}0 \\\ 1\end{array}\right),\left(\begin{array}{l}2 \\ 2\end{array}\right)\right)\) \(\left(\left(\begin{array}{l}1 \\ 0\end{array}\right),\left(\begin{array}{l}3 \\\ 3\end{array}\right)\right), \operatorname{and}\left(\left(\begin{array}{l}1 \\\ 1\end{array}\right),\left(\begin{array}{l}4 \\ 4\end{array}\right)\right)\) (o) How many points in the graph of a \(q\) -th order polynomial function \(\mathbb{R}^{n} \rightarrow \mathbb{R}^{n}\) would completely determine the function? (p) In particular, how many points of the graph of linear function \(\mathbb{R}^{n} \rightarrow \mathbb{R}^{n}\) would completely determine the function? How does a matrix (in the standard basis) encode this information? (q) Propose a way to store the information required in \(8 \mathrm{~g}\) above in an array of numbers. (r) Propose a way to store the information required in 8 o above in an array of numbers.

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