Chapter 10: Problem 8
(a) Let \(T: \mathbb{R}^{2} \rightarrow \mathbb{R}^{2}\) be defined by \(T(x, y)=(2 x+3 y+4,5 x-y)\). Show that \(T\) is not linear. (b) Let \(p(x)\) be a fixed polynomial in \(\mathbb{R}[x]\). Define \(T: \mathbb{R}[x] \rightarrow \mathbb{R}[x]\) by: for each polynomial \(q(x) \in \mathbb{R}[x], T(q(x))=p(x) q(x)\). Is \(T\) a linear map?
Short Answer
Step by step solution
Understand the Definition of Linearity
Investigate Linearity of T(x, y)
Confirm T is Not Linear Using Linearity Properties
Analyze the Second Transformation Definition
Apply Linearity Properties to Polynomial T
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linearity Properties
For vectors \( \mathbf{u}, \mathbf{v} \) in a vector space and any scalar \( c \), a transformation \( T \) is linear if:
- Additivity: \( T(\mathbf{u} + \mathbf{v}) = T(\mathbf{u}) + T(\mathbf{v}) \)
- Scalar multiplication: \( T(c \cdot \mathbf{u}) = c \cdot T(\mathbf{u}) \)
This understanding of linearity helps differentiate between linear and non-linear transformations.
Polynomial Transformation
Such transformations can be checked for linearity by examining:
- Additivity: \( T(q_1(x) + q_2(x)) = T(q_1(x)) + T(q_2(x)) \) holds because multiplying by \( p(x) \) distributes over addition.
- Scalar multiplication: \( T(c \cdot q(x)) = c \cdot T(q(x)) \) is satisfied as scalar constants can be factored out.
Vector Space Mapping
A map, such as \( T(x, y) = (2x + 3y + 4, 5x - y) \), explores how elements from one vector space relate to another. For a transformation to be deemed linear, every combination of scaling and addition must result in predictable outputs. This requires the map to send zero elements to zero, without deviating into non-linear outputs or transformations.
In simple terms, a linear vector space mapping maintains consistent proportional relationships among vectors, ensuring predictable spatial transformations.
Non-linear Transformation
Consider the transformation \( T(x, y) = (2x + 3y + 4, 5x - y) \). Here, the constant term \( +4 \) disrupts the additivity property, as it alters the expected outcome of the transformation. When tested with the zero vector, it does not return the zero vector, a clear indication of non-linearity.
Non-linear transformations often introduce complexity, altering shapes, directions, and more within vector spaces. Unlike linear transformations, which maintain proportional relations and predictable outcomes, non-linear transformations may have fluctuating scales and directions, providing a more varied mapping landscape.