/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 Let \(F\) be a rotation through ... [FREE SOLUTION] | 91影视

91影视

Let \(F\) be a rotation through an angle \(\theta .\) Show that for any vector \(X\) in \(\mathbf{R}^{2}\) we have \(\|X\|=\|F(X)\|\) (i.e. \(F\) preserves norms).

Short Answer

Expert verified
We start by writing the rotation matrix \( F \) given by an angle \( \theta \) as \[ F = \begin{bmatrix} \cos(\theta) & -\sin(\theta) \\ \sin(\theta) & \cos(\theta) \end{bmatrix} \] We then multiply this matrix with an arbitrary vector \( X = \begin{bmatrix} x鈧 \\ x鈧 \end{bmatrix} \) to get \( F(X) = \begin{bmatrix} x鈧乗cos(\theta) - x鈧俓sin(\theta) \\ x鈧乗sin(\theta) + x鈧俓cos(\theta) \end{bmatrix} \). Following this, we compute the norms of \( X \) and \( F(X) \). The norm of \( X \) is given by \( \|X\|=\sqrt{x鈧乛2+x鈧俕2} \), while the norm of \( F(X) \) is given by \[ \|F(X)\| = \sqrt{(x鈧乗cos(\theta) - x鈧俓sin(\theta))^2 + (x鈧乗sin(\theta) + x鈧俓cos(\theta))^2} \] Lastly, we show that the norms of \( X \) and \( F(X) \) are equal. We simplify the expression for \( \|F(X)\| \) by recognizing that \( \cos^2(\theta) + \sin^2(\theta) = 1 \). This simplification leads to \( \|F(X)\| = \sqrt{x鈧乛2 + x鈧俕2} \), which is identical to the original norm of \( X \), thereby demonstrating that the norms are preserved under rotation, i.e., \( \|X\| = \|F(X)\| \).

Step by step solution

01

Establish the rotation matrix F

Given a rotation angle 胃, the rotation matrix F, in 2 dimensions, can be written as \[F = \begin{bmatrix} \cos(\theta) & -\sin(\theta) \\ \sin(\theta) & \cos(\theta) \end{bmatrix}\]
02

Multiply F by X to get F(X)

Now let's multiply the matrix F with an arbitrary vector X (with components x鈧 and x鈧) to get F(X) as follows: \[ F(X) = \begin{bmatrix} \cos(\theta) & -\sin(\theta) \\ \sin(\theta) & \cos(\theta) \end{bmatrix} \begin{bmatrix} x鈧 \\ x鈧 \end{bmatrix} = \begin{bmatrix} x鈧乗cos(\theta) - x鈧俓sin(\theta) \\ x鈧乗sin(\theta) + x鈧俓cos(\theta) \end{bmatrix}\]
03

Compute the norm of X and F(X)

Next, we find the norm of the vector X and the vector F(X): - Norm of X: \(\|X\|=\sqrt{x鈧乛2+x鈧俕2}\) - Norm of F(X): \(\|F(X)\| = \sqrt{(x鈧乗cos(\theta) - x鈧俓sin(\theta))^2 + (x鈧乗sin(\theta) + x鈧俓cos(\theta))^2}\)
04

Show that \|X\| = \|F(X)\|

Now, let's show that the norm of X is equal to the norm of F(X). Starting with the norm of F(X), we do some algebraic simplification: \(\|F(X)\| = \sqrt{(x鈧乗cos(\theta) - x鈧俓sin(\theta))^2 + (x鈧乗sin(\theta) + x鈧俓cos(\theta))^2}\) Expanding this expression, \(\|F(X)\| = \sqrt{x鈧乛2\cos^2(\theta) - 2x鈧亁鈧俓cos(\theta)\sin(\theta) + x鈧俕2\sin^2(\theta) + x鈧乛2\sin^2(\theta) + 2x鈧亁鈧俓sin(\theta)\cos(\theta) + x鈧俕2\cos^2(\theta)}\) Now, observe that we can simplify terms: \(\|F(X)\| = \sqrt{x鈧乛2(\cos^2(\theta) + \sin^2(\theta)) + x鈧俕2(\sin^2(\theta) + \cos^2(\theta))}\) Since \(\cos^2(\theta) + \sin^2(\theta) = 1\), we get \(\|F(X)\| = \sqrt{x鈧乛2 + x鈧俕2}\) This is the same as the norm of X, so we have proven that \(\|X\| = \|F(X)\|\), meaning the rotation matrix F preserves the norms of the vectors it rotates.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Norm
In mathematics, especially linear algebra, the concept of vector norm is essential. The vector norm provides a measure of a vector's length or magnitude. For a vector in two-dimensional space, such as \(X = \begin{bmatrix} x_1 \ x_2 \end{bmatrix}\),the norm, often denoted as \(||X||\), is computed using the Pythagorean theorem.
Here, the length of the vector X is calculated as \(||X|| = \sqrt{x_1^2 + x_2^2}\). This expression sums the squares of the components and takes the square root of the result. It gives us a non-negative scalar value that represents the vector's distance from the origin.
Understanding vector norms is crucial when examining transformations like rotations, where the aim is often to ascertain whether these transformations alter the vector's magnitude. Answering such questions helps us determine properties such as whether a transformation is an isometry, meaning it preserves distances and angles.
Linear Transformation
A linear transformation refers to a function between two vector spaces that respects vector addition and scalar multiplication. In simpler terms, transforming a vector through a linear transformation results in another vector that is a linear combination of the original vectors.
One common example is a rotation matrix in two dimensions, which is particularly relevant here.
The rotation matrix \(F\) for an angle \( \theta \) is given by:\[F = \begin{bmatrix} \cos(\theta) & -\sin(\theta) \ \sin(\theta) & \cos(\theta) \end{bmatrix}\]This matrix rotates any vector it is multiplied with by an angle \( \theta \) in the counter-clockwise direction.
  • It maps a vector to a new position while keeping the origin fixed.
  • It is an orthogonal matrix, meaning its rows and columns are orthogonal unit vectors.
  • Such a transformation preserves vector norms, hence is distance-preserving or an isometry.
These transformations are fundamental to understanding movements and orientations in physics, engineering, and computer graphics.
Trigonometric Identity
Trigonometric identities are vital tools in simplifying mathematical equations involving trigonometric functions. One of the most crucial identities used in transformations such as rotations is:\[\cos^2(\theta) + \sin^2(\theta) = 1\]This identity states that the sum of the squares of sine and cosine for any angle \( \theta \) will always equal one. This relationship is grounded in the Pythagorean theorem, as it reflects the properties of a unit circle.
When dealing with rotation matrices, this identity ensures that the columns of the matrix remain orthogonal and unit length. It plays a critical role when demonstrating that a transformation such as rotation does not alter the vector norm.
During the solution of the problem, we expanded and combined terms involving \(\cos^2(\theta)\) and \(\sin^2(\theta)\). By directly referencing this identity, the complexity of the equation reduces, leading to a clear conclusion that the vector's length remains unchanged post-rotation. Employing such identities proficiently allows for elegance and simplicity in mathematical proofs and calculations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In each one of the following cases, find \(M_{\mathbb{G}^{\prime}}^{\mathbb{B}}(i d)\). The vector space in each case is \(\mathbf{R}^{3}\). (a) \(\mathbb{B}=\\{(1,1,0),(-1,1,1),(0,1,2)\\}\) \(B^{\prime}=\\{(2,1,1),(0,0,1),(-1,1,1)\\}\) (b) \(B=\\{(3,2,1),(0,-2,5),(1,1,2)\\}\) \(\mathbb{B}^{\prime}=\\{(1,1,0),(-1,2,4),(2,-1,1)\\}\)

In each case, find the vector \(L_{A}(X)\). (a) \(A=\left(\begin{array}{ll}2 & 1 \\ 1 & 0\end{array}\right), X=\left(\begin{array}{r}3 \\ -1\end{array}\right)\) (b) \(A=\left(\begin{array}{ll}1 & 0 \\ 0 & 0\end{array}\right), X=\left(\begin{array}{l}5 \\ 1\end{array}\right)\) (c) \(A=\left(\begin{array}{ll}1 & 1 \\ 0 & 1\end{array}\right), X=\left(\begin{array}{l}4 \\ 1\end{array}\right)\) (d) \(A=\left(\begin{array}{ll}0 & 0 \\ 0 & 1\end{array}\right), X=\left(\begin{array}{r}7 \\ -3\end{array}\right)\)

In each of the following cases, let \(D=d / d t\) be the derivative. We give \(a\) set of linearly independent functions B. These generate a vector space \(V\), and \(D\) is a linear may from \(V\) into itself. Find the matrix associated with \(D\) relative to the base ' \(B\), B. (a) \(\left\\{t, e^{-\ell}\right\\}\) (b) \(\\{1, t\\}\) (c) \(\left\\{e^{t}, t e^{l}\right\\}\) (d) \(\left\\{1, t, t^{2}\right\\}\) (e) \(\left\\{1, t, e^{t}, e^{2 t}, t e^{2 \ell}\right\\}\) (f) \(\\{\sin t, \cos t\\}\)

For each real number \(\theta_{1}\) let \(F_{0}: \mathbf{R}^{2} \rightarrow \mathbf{R}^{2}\) be the linear map represented by the matrix $$ \left(\begin{array}{rr} \cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{array}\right) . $$ 8how that if \(\theta, \theta^{\prime}\) are real numbers, then \(F_{0} F_{0}^{\prime}=P_{t+4^{\prime}}\). (You must use the addition formula for sine and cosine.) Also show that \(F_{t}^{-1}=F_{-6}\)

Let \(c\) be a number, and let \(L: \mathbf{R}^{n} \rightarrow \mathbf{R}^{n}\) be the linear map such that \(L(X)=C X\). What is the matrix associated with this linear map?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.