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According to the Fundamental Theorem of linear programming, if either a linear program or its dual has no feasible point, then the other one has no solution. Illustrate this assertion with an example.

Short Answer

Expert verified
We constructed a linear program (LP) and its dual linear program (DLP). After analyzing the LP, we found it has no feasible region, as no point satisfies all three constraints simultaneously. According to the Fundamental Theorem of linear programming, if the LP has no feasible point, then its DLP must have no solution. True to the theorem, we found that there is no combination for y_1, y_2, and y_3 that satisfy all DLP constraints simultaneously, proving the assertion.

Step by step solution

01

Create a linear program

: Let's create a linear program (LP). Maximize: \(z = 2x_1 + 3x_2\) Subject to: \(x_1 + x_2 ≤ 1\) \(x_1 - x_2 ≥ 3\) \(-2x_1 + 3x_2 ≤ 1\) \(x_1, x_2 \geq 0\)
02

Create the dual of the linear program

: Now, let's construct the dual linear program (DLP) for the given LP. Minimize: \(w = y_1 + 3y_2 + y_3\) Subject to: \(y_1 + y_2 - 2y_3 ≥ 2\) \(y_1 - y_3 + 3y_3 ≥ 3\) \(y_1, y_2, y_3\geq 0\)
03

Check for feasible region in the linear program

: Now, let's check whether the given LP has a feasible region (in which an optimal solution could exist) by finding the intersection of the constraints. Plot the constraints: \(x_1 + x_2 = 1\), \(x_1 - x_2 = 3\), and \(-2x_1 + 3x_2 = 1\). Upon analyzing the plots, we can see that no point satisfies all three constraints simultaneously, indicating that the LP does not have a feasible region.
04

Check the dual linear program for a solution

: According to the Fundamental Theorem of linear programming, since the given LP has no feasible point, its DLP should have no solution: Check the DLP constraints: \(y_1 + y_2 - 2y_3 = 2\), \(y_1 - y_3 + 3y_3 =3\), and \(y_1, y_2, y_3\geq 0\). Upon attempting to solve the DLP constraints, we find that there is no combination of values for y_1, y_2, and y_3 that satisfy all constraints simultaneously. Therefore, the DLP does not have a solution. Thus, the given example illustrates the Fundamental Theorem of linear programming asserting that if either a linear program or its dual has no feasible point, the other one also has no solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Program
A linear program (LP) is a set of mathematical methods aimed at finding the best outcome—often maximizing profit or minimizing cost—in a model whose requirements are represented by linear relationships. It's a method of taking a series of linear inequalities, known as constraints, and determining the best possible solution to a linear function known as the objective function.

In our example, the objective function to maximize was given as \( z = 2x_1 + 3x_2 \). The constraints were inequalities that included \( x_1 + x_2 \leq 1 \), \( x_1 - x_2 \geq 3 \), and \( -2x_1 + 3x_2 \leq 1 \), along with non-negativity restrictions \( x_1, x_2 \geq 0 \). Each constraint represents a linear equation once the 'inequality' component is removed, defining a boundary in the space where solutions exist.
Dual Linear Program
Associated with every linear program is another LP known as its dual. The dual linear program (DLP) has a different objective function and set of constraints but is directly related to the original or 'primal' linear program.

While the primal seeks to maximize (or minimize) the objective function within its constraints, the dual program does the opposite—minimizing (or maximizing) based on related constraints. Constraints of the dual are derived from the primal's objective function and vice versa. In the exercise, the DLP aimed to minimize \( w = y_1 + 3y_2 + y_3 \) subject to its own set of constraints derived from the primal. Creating a DLP essentially translates the original problem into a new perspective, which for certain analyses may be more efficient to solve.
Feasible Region
The feasible region in a linear programming problem is the set of all possible points that satisfy all the given constraints. It represents the range of values that the variables of the LP can take while adhering to the limitations. This region is crucial because it contains the solution to the LP—if one exists.

The feasible region is typically a convex shape (such as a polygon in two dimensions), and its vertices are often where the optimal solution lies. In the provided example, plotting the constraints showed that there was no common area meeting all conditions, thus signaling the absence of a feasible region. It means there are no values for \( x_1 \) and \( x_2 \) that can simultaneously meet all constraints, and hence, there is no solution to this LP.
Optimization Constraints
In linear programming, optimization constraints are the equations or inequalities that define the conditions a solution must satisfy. They form the boundaries of the feasible region and are fundamental in determining the scope of the problem.

Constraints typically represent limitations such as resource capacity, budget, time, or other requirements specific to the problem at hand. In our exercise, we evaluated inequalities representing these constraints. For the primal LP, the constraints included relationships between \( x_1 \) and \( x_2 \), ensuring the solutions are within certain bounds, along with the condition \( x_1, x_2 \geq 0 \) to maintain non-negativity.

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