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Compare the \(M / G / 1\) system for first-come, first-served queue discipline with one of last-come, first-served (for instance, in which units for service are taken from the top of a stack). Would you think that the queue size, waiting time, and busy-period distribution differ? What about their means? What if the queue discipline was always to choose at random among those waiting? Intuitively which discipline would result in the smallest variance in the waiting time distribution?

Short Answer

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In summary, FCFS, LCFS, and Random queue disciplines in the \(M / G / 1\) queue system will have different impacts on queue size, waiting time, and busy-period distribution. LCFS generally has a smaller mean waiting time and may lead to a higher variance in waiting time distribution. Meanwhile, FCFS maintains fairness in service and considers arrival order, resulting in a lower variance in waiting time distribution compared to the other two disciplines. The Random discipline has waiting time distribution variances falling somewhere between those of FCFS and LCFS, as it gives equal weightage to both first and last arrivals. Intuitively, the FCFS discipline is likely to result in the smallest variance in the waiting time distribution.

Step by step solution

01

Understanding the M/G/1 Queue System

The M/G/1 queuing system is a single-server queue with random arrivals and generally distributed service times. \(M\) denotes Markovian or exponential inter-arrival times, and \(G\) represents generally distributed service times. The notation \(1\) indicates a single server in the system.
02

Comparing Queue Disciplines - Queue Size, Waiting Time, and Busy-Period Distribution

For an M/G/1 queue system, the queue size, waiting time, and busy-period distribution will depend on the particular queue discipline employed. As the analysis for each discipline is quite involved and beyond the scope of a high school level explanation, we will instead focus on the general differences for the queue disciplines mentioned. 1. FCFS (First-come, first-served): In this discipline, customers are served in the order of their arrival. It is fair and respects the order in which the customers arrive in the queue. 2. LCFS (Last-come, first served): In this discipline, customers are served according to the most recent arrival, often referred to as a Stack or LIFO (Last-In, First-Out). This is a non-preemptive priority service with less fairness than FCFS, resulting in shorter waiting times for the most recent arrivals and potentially longer wait times for customers who have been in the queue for a while. 3. Random: In this discipline, the server randomly selects customers from the queue. As a result, there is no preference to any arrival time, creating an unpredictable environment for service.
03

Comparing Queue Disciplines - Means

When comparing these disciplines' means, FCFS and LCFS will generally have different mean waiting times and queue sizes. LCFS has a smaller mean waiting time as it tends to serve more recent arrivals first. On the other hand, FCFS respects the order of arrival for the customers. In general, the mean waiting time and queue size for Random discipline will lie somewhere between those of FCFS and LCFS. This is because there is no preference for either first arrival or last arrival, giving equal weightage for both.
04

Comparing Queue Disciplines - Variance in Waiting Time Distribution

To intuitively determine which queue discipline would result in the smallest variance in the waiting time distribution, we can reason as follows: 1. FCFS: Due to the inherent fairness in the FCFS discipline, we can expect that the waiting time distribution would generally have less variation than those for the other disciplines. This is because the customers are served in the order in which they arrive, so there are no anomalies or surprises. 2. LCFS: This discipline does not respect the order of arrival, and the service time is uncertain. This non-preemptive priority service based on recent arrivals can cause wide fluctuations in waiting time, which may lead to a higher variance in the waiting time distribution. 3. Random: The random discipline introduces uncertainty in service ordering, making it harder to predict waiting times. However, the variance for this discipline will likely be lower than LCFS but higher than FCFS, as servers are not biased towards any specific customer or position in the queue. Given this reasoning, it can be inferred that the smallest variance in the waiting time distribution would likely occur for the FCFS discipline, followed by the Random discipline, and finally the LCFS discipline.

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Most popular questions from this chapter

Consider the \(M / M / 1\) system in which customers arrive at rate \(\lambda\) and the server serves at rate \(\mu .\) However, suppose that in any interval of length \(h\) in which the server is busy there is a probability \(\alpha h+o(h)\) that the server will experience a breakdown, which causes the system to shut down. All customers that are in the system depart, and no additional arrivals are allowed to enter until the breakdown is fixed. The time to fix a breakdown is exponentially distributed with rate \(\beta\). (a) Define appropriate states. (b) Give the balance equations. In terms of the long-run probabilities, (c) what is the average amount of time that an entering customer spends in the system? (d) what proportion of entering customers complete their service? (e) what proportion of customers arrive during a breakdown?

Consider a single-server queue with Poisson arrivals and exponential service times having the following variation: Whenever a service is completed a departure occurs only with probability \(\alpha .\) With probability \(1-\alpha\) the customer, instead of leaving, joins the end of the queue. Note that a customer may be serviced more than once. (a) Set up the balance equations and solve for the steady-state probabilities, stating conditions for it to exist. (b) Find the expected waiting time of a customer from the time he arrives until he enters service for the first time. (c) What is the probability that a customer enters service exactly \(n\) times, \(n=\) \(1,2, \ldots ?\) (d) What is the expected amount of time that a customer spends in service (which does not include the time he spends waiting in line)? Hint: Use part (c). (e) What is the distribution of the total length of time a customer spends being served? Hint: Is it memoryless?

Consider a single-server exponential system in which ordinary customers arrive at a rate \(\lambda\) and have service rate \(\mu .\) In addition, there is a special customer who has a service rate \(\mu_{1}\). Whenever this special customer arrives, she goes directly into service (if anyone else is in service, then this person is bumped back into queue). When the special customer is not being serviced, she spends an exponential amount of time (with mean \(1 / \theta\) ) out of the system. (a) What is the average arrival rate of the special customer? (b) Define an appropriate state space and set up balance equations. (c) Find the probability that an ordinary customer is bumped \(n\) times.

Consider an \(M / G / 1\) system in which the first customer in a busy period has the service distribution \(G_{1}\) and all others have distribution \(G_{2}\). Let \(C\) denote the number of customers in a busy period, and let \(S\) denote the service time of a customer chosen at random. Argue that (a) \(a_{0}=P_{0}=1-\lambda E[S]\). (b) \(E[S]=a_{0} E\left[S_{1}\right]+\left(1-a_{0}\right) E\left[S_{2}\right]\) where \(S_{i}\) has distribution \(G_{i}\) (c) Use (a) and (b) to show that \(E[B]\), the expected length of a busy period, is given by $$ E[B]=\frac{E\left[S_{1}\right]}{1-\lambda E\left[S_{2}\right]} $$ (d) Find \(E[C]\).

Customers arrive at a two-server system at a Poisson rate \(\lambda\). An arrival finding the system empty is equally likely to enter service with either server. An arrival finding one customer in the system will enter service with the idle server. An arrival finding two others in the system will wait in line for the first free server. An arrival finding three in the system will not enter. All service times are exponential with rate \(\mu\), and once a customer is served (by either server), he departs the system. (a) Define the states. (b) Find the long-run probabilities. (c) Suppose a customer arrives and finds two others in the system. What is the expected times he spends in the system? (d) What proportion of customers enter the system? (e) What is the average time an entering customer spends in the system?

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