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Consider a set of \(n\) machines and a single repair facility to service these machines. Suppose that when machine \(i, i=1, \ldots, n\), fails it requires an exponentially distributed amount of work with rate \(\mu_{i}\) to repair it. The repair facility divides its efforts equally among all failed machines in the sense that whenever there are \(k\) failed machines each one receives work at a rate of \(1 / k\) per unit time. If there are a total of \(r\) working machines, including machine \(i\), then \(i\) fails at an instantaneous rate \(\lambda_{i} / r\) (a) Define an appropriate state space so as to be able to analyze the preceding system as a continuous-time Markov chain. (b) Give the instantaneous transition rates (that is, give the \(q_{i j}\) ). (c) Write the time reversibility equations. (d) Find the limiting probabilities and show that the process is time reversible.

Short Answer

Expert verified
The state space of the Markov chain is given by: $$S = \{(r, s_i) | 0 \leq r \leq n, s_i \subseteq \{1, 2, \ldots, n\}, |s_i| = r\}$$ The instantaneous transition rates are: $$q_{(r,s_i) (r-1,s_i-\{i\})} = \frac{\lambda_i}{r}$$ and $$q_{(r-1,s_i-\{i\}) (r,s_i)} = \mu_i \frac{1}{n - r + 1}$$ The time reversibility equations are: \(\pi_{(r,s_i)} \frac{\lambda_i}{r} = \pi_{(r-1,s_i-\{i\})} \mu_i \frac{1}{n - r + 1}\) The limiting probabilities exist, and the Markov chain is time reversible.

Step by step solution

01

Define the state space of the Markov chain

The state space of the Markov chain is the set of all possible configurations of working and failed machines. Represent each state as \((r, s_i)\), where \(r\) is the number of working machines, and \(s_i\) is the set of indices of working machines. The size of \(s_i\) is equal to \(r\). The state space, denoted as \(S\), includes all possible configurations: $$S = \{(r, s_i) | 0 \leq r \leq n, s_i \subseteq \{1, 2, \ldots, n\}, |s_i| = r\}$$
02

Compute the instantaneous transition rates \(q_{(r,s_i) (r',s_i')}\)

We need to find the probabilities of the following transitions: - When a working machine fails. - When a failed machine is repaired. 1. When a working machine fails, the state changes to one with one less working machine. For example, transition from state \((r, s_i)\) to state \((r-1, s_i - \{i\})\). The instantaneous rate of this transition is given by: $$q_{(r,s_i) (r-1,s_i-\{i\})} = \frac{\lambda_i}{r}$$ 2. When a failed machine is repaired, the state changes to one with one more working machine. For example, transition from state \((r-1, s_i - \{i\})\) to state \((r, s_i)\). The instantaneous rate of this transition is given by: $$q_{(r-1,s_i-\{i\}) (r,s_i)} = \mu_i \frac{1}{n - r + 1}$$
03

Write the time reversibility equations

For a continuous-time Markov chain to be time reversible, it must satisfy the following equation for all pairs of states \((r,s_i)\) and \((r',s_i')\) in \(S\): $$\pi_{(r,s_i)} q_{(r,s_i) (r',s_i')} = \pi_{(r',s_i')} q_{(r',s_i') (r,s_i)}$$ In our system, we need to consider the above equation for these two possible transitions: - Transition from state \((r, s_i)\) to state \((r - 1, s_i - \{i\})\). - Transition from state \((r - 1, s_i - \{i\})\) to state \((r, s_i)\). So, the equations are: 1. \(\pi_{(r,s_i)} \frac{\lambda_i}{r} = \pi_{(r-1,s_i-\{i\})} \mu_i \frac{1}{n - r + 1}\) 2. \(\pi_{(r-1,s_i-\{i\})} \mu_i \frac{1}{n - r + 1} = \pi_{(r,s_i)} \frac{\lambda_i}{r}\)
04

Find the limiting probabilities and prove time reversibility

Rewriting the equations from Step 3, we get: 1. \(\frac{\pi_{(r,s_i)}}{\pi_{(r-1,s_i-\{i\})}} = \frac{\mu_i}{\lambda_i} \frac{r}{n - r + 1}\) 2. \(\frac{\pi_{(r-1,s_i-\{i\})}}{\pi_{(r,s_i)}} = \frac{\mu_i}{\lambda_i} \frac{r}{n - r + 1}\) These equations are consistent, so the limiting probabilities do exist. Furthermore, the fact that the ratios of the limiting probabilities satisfy the time reversibility condition implies that the Markov chain is in fact time reversible.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

State Space
Understanding the state space of a system is like sketching a map of all possible scenarios in which the system can exist. For our example involving a set of machines and a single repair facility, the state space consists of all possible combinations of working and failed machines. Each state is a snapshot of the system, detailing which machines are operational and which are undergoing repairs.

In mathematical terms, the state space is denoted as \( S \) and is defined as \( S = \{(r, s_i) | 0 \leq r \leq n, s_i \subseteq \{1, 2, \ldots, n\}, |s_i| = r\} \). Here, \( r \) represents the number of functioning machines, and \( s_i \) is the index set of these working machines. By comprehensively embracing all possible states, the state space becomes the foundation upon which we can analyze the system's behavior as a continuous-time Markov chain.
Instantaneous Transition Rates
Picture a lively city where roads connect buildings: these roads are akin to the instantaneous transition rates in our machine repair example. These rates depict the likelihood of a machine switching from a working to a failed state, or vice versa, in an infinitesimal time interval.

The transition rates, denoted by \( q_{(r,s_i) (r',s_i')} \), are calculated using the failure rates \( \lambda_i \) and the repair rates \( \mu_i \). For a working machine to fail, the rate is \( \frac{\lambda_i}{r} \), where \( r \) is the number of operational machines. Conversely, for a failed machine to be repaired, the rate is \( \mu_i \frac{1}{n - r + 1} \), taking into consideration that the repair effort is split across all failed machines. Capturing these nuances is vital for accurately reflecting the dynamics of the system.
Time Reversibility
To grasp time reversibility, think of a film being played backwards and forwards with scenes that can seamlessly transition in either direction. In our system of machines, time reversibility means that the process of machines failing and being repaired can occur forwards in time just as it would backwards, statistically speaking.

For a process to be considered time reversible, the forward and reverse transition rates between any two states must be balanced by their respective limiting probabilities, which follow the detailed balance equation: \( \pi_{(r,s_i)} q_{(r,s_i) (r',s_i')} = \pi_{(r',s_i')} q_{(r',s_i') (r,s_i)} \). When this condition is satisfied, it enables us to ascertain that, over the long term, the flow of transitions in each direction is equivalent, thus affirming the system's reversibility in time.
Limiting Probabilities
Imagine the steady rhythm of waves hitting the shoreline; this illustrates the concept of limiting probabilities, which describe the long-term behavior of the system. As time progresses, the Markov chain settles into a pattern where the proportion of time spent in each state stabilizes.

Limiting probabilities, denoted \( \pi_{(r,s_i)} \), represent the fraction of time the system is expected to be in state \( (r, s_i) \) as time goes to infinity. We determine these probabilities by solving a set of balance equations derived from the transition rates. Significantly, the limiting probabilities we discover for the machine repair system comply with the time reversibility condition mentioned earlier. This consistency not only confirms that the probabilities are well-defined but also ensures the system is time reversible, underlining a profound symmetry in its behavior over time.

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Most popular questions from this chapter

Customers arrive at a two-server station in accordance with a Poisson process having rate \(\lambda\). Upon arriving, they join a single queue. Whenever a server completes a service, the person first in line enters service. The service times of server \(i\) are exponential with rate \(\mu_{i}, i=1,2\), where \(\mu_{1}+\mu_{2}>\lambda .\) An arrival finding both servers free is equally likely to go to either one. Define an appropriate continuous-time Markov chain for this model, show it is time reversible, and find the limiting probabilities.

Consider an ergodic \(M / M / s\) queue in steady state (that is, after a long time) and argue that the number presently in the system is independent of the sequence of past departure times. That is, for instance, knowing that there have been departures \(2,3,5\), and 10 time units ago does not affect the distribution of the number presently in the system.

Consider two \(M / M / 1\) queues with respective parameters \(\lambda_{i}, \mu_{i}, i=1,2 .\) Suppose they share a common waiting room that can hold at most three customers. That is, whenever an arrival finds her server busy and three customers in the waiting room, she goes away. Find the limiting probability that there will be \(n\) queue 1 customers and \(m\) queue 2 customers in the system. Hint: Use the results of Exercise 28 together with the concept of truncation.

Consider a system of \(n\) components such that the working times of component \(i, i=1, \ldots, n\), are exponentially distributed with rate \(\lambda_{i} .\) When failed, however, the repair rate of component \(i\) depends on how many other components are down. Specifically, suppose that the instantaneous repair rate of component \(i, i=1, \ldots, n\), when there are a total of \(k\) failed components, is \(\alpha^{k} \mu_{i}\) (a) Explain how we can analyze the preceding as a continuous-time Markov chain. Define the states and give the parameters of the chain. (b) Show that, in steady state, the chain is time reversible and compute the limiting probabilities.

The following problem arises in molecular biology. The surface of a bacterium consists of several sites at which foreign molecules - some acceptable and some not - become attached. We consider a particular site and assume that molecules arrive at the site according to a Poisson process with parameter \(\lambda\). Among these molecules a proportion \(\alpha\) is acceptable. Unacceptable molecules stay at the site for a length of time which is exponentially distributed with parameter \(\mu_{1}\), whereas an acceptable molecule remains at the site for an exponential time with rate \(\mu_{2}\). An arriving molecule will become attached only if the site is free of other molecules. What percentage of time is the site occupied with an acceptable (unacceptable) molecule?

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