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Let \(p_{0}=P\\{X=0\\}\) and suppose that \(0

Short Answer

Expert verified
The short version of the answer is: (a) \(E[X \mid X \neq 0] = \frac{\mu}{1 - p_0}\) (b) \(\operatorname{Var}(X \mid X \neq 0) = \frac{\sigma^2(1 - p_0)}{(1 - p_0)^2}\)

Step by step solution

01

Part (a): Calculate the Conditional Expectation

To find the conditional expectation, we can use the following formula: \[E[X \mid X \neq 0] = \frac{E[X \cdot 1_{\{X \neq 0\}}]}{P(X \neq 0)}\] First, we need to find the probability that X is not equal to 0, which can be calculated using the complement rule, so we have \(P(X \neq 0) = 1 - P(X=0) = 1 - p_0\). Next, we need to find the expected value of X times the indicator function, which is: \[E[X \cdot 1_{\{X \neq 0\}}] = E[X] - E[X \cdot 1_{\{X = 0\}}]\] Since the indicator function is 1 when X is not equal to 0 and 0 otherwise, we have: \[ E[X \cdot 1_{\{X \neq 0\}}] = E[X] - E[X \cdot 1_{\{X = 0\}}] = E[X] - 0 * P(X=0) = E[X] = \mu \] Now, we can calculate the conditional expectation: \[ E[X \mid X \neq 0] = \frac{E[X \cdot 1_{\{X \neq 0\}}]}{P(X \neq 0)} = \frac{\mu}{1 - p_0} \]
02

Part (b): Calculate the Conditional Variance

We can find the conditional variance of X given that X is not equal to 0 using the following formula: \[ \operatorname{Var}(X \mid X \neq 0) = E[X^2 \mid X \neq 0] - \left(E[X \mid X \neq 0]\right)^2 \] First, let's find the conditional expectation of \(X^2\), similar to how we found the conditional expectation of X in part (a): \[ E[X^2 \mid X \neq 0] = \frac{E[X^2 \cdot 1_{\{X \neq 0\}}]}{P(X \neq 0)} = \frac{E[X^2] - E[X^2 \cdot 1_{\{X = 0\}}]}{1 - p_0} \] Since \(E[X^2 \cdot 1_{\{X = 0\}}] = 0 * P(X=0) = 0\), we have: \[ E[X^2 \mid X \neq 0] = \frac{E[X^2]}{1 - p_0} \] Using the variance of X, we know that \(\sigma^2 = E[X^2] - \mu^2\), so we can rewrite the conditional expectation of \(X^2\) as: \[ E[X^2 \mid X \neq 0] = \frac{\sigma^2 + \mu^2}{1 - p_0} \] Now, we can calculate the conditional variance: \[ \operatorname{Var}(X \mid X \neq 0) = E[X^2 \mid X \neq 0] - \left(E[X \mid X \neq 0]\right)^2 = \frac{\sigma^2 + \mu^2}{1 - p_0} - \left(\frac{\mu}{1 - p_0}\right)^2 \] To make it look more appealing, we may rewrite it as: \[ \operatorname{Var}(X \mid X \neq 0) = \frac{\sigma^2(1 - p_0) + \mu^2 - \mu^2}{(1 - p_0)^2} = \frac{\sigma^2(1 - p_0)}{(1 - p_0)^2} \] So, the conditional variance of X given that X is not equal to 0 is: \[ \operatorname{Var}(X \mid X \neq 0) = \frac{\sigma^2(1 - p_0)}{(1 - p_0)^2} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a measure that quantifies the likelihood of certain events occurring, ranging from 0 (impossible event) to 1 (certain event). In this exercise, we focus on the probability of a random variable, \( X \), not being zero. Using the complementary probability, this is calculated as \( P(X eq 0) = 1 - P(X = 0) = 1 - p_0 \).

This approach is crucial as it helps simplify the steps in calculating conditional measures like expected value and variance, based on certain conditions or events. By understanding probability, you are equipped to delve deeper into more complex statistical concepts.
Expected Value
Expected value represents the average value or mean of a random variable. It shows the long-term result of a random process if repeated many times. For a random variable \( X \), the expected value is denoted as \( E[X] \) or \( \mu \).

In this task, our aim was to find the conditional expected value of \( X \) given \( X eq 0 \). This is calculated by the formula: \[ E[X \mid X eq 0] = \frac{E[X \cdot 1_{\{X eq 0\}}]}{P(X eq 0)} \] By substituting \( E[X \cdot 1_{\{X eq 0\}}] \) with \( E[X] \) since \( E[X \cdot 1_{\{X = 0\}}] = 0 \), and using the probability of \( X eq 0 \), we have: \[ E[X \mid X eq 0] = \frac{\mu}{1 - p_0} \] This provides insight into how an average outcome of \( X \) shifts when zeroes are excluded.

Understanding expected value is key in probability and statistics as it forms the basis for further concepts such as variance and Kurtosis.
Variance
Variance measures the spread or dispersion of a set of values. It's defined as the expectation of the squared deviation of a random variable from its mean. For \( X \), variance is denoted as \( \operatorname{Var}(X) = \sigma^2 \). It's a key concept that tells us how spread out or dispersed the values of \( X \) are from the average value \( \mu \).

In our exercise, to find the conditional variance of \( X \) when \( X eq 0 \), we use: \[ \operatorname{Var}(X \mid X eq 0) = E[X^2 \mid X eq 0] - \left(E[X \mid X eq 0]\right)^2 \] The expected value of \( X^2 \) was derived as: \[ E[X^2 \mid X eq 0] = \frac{E[X^2]}{1 - p_0} \] where \( E[X^2] = \sigma^2 + \mu^2 \).

The term is simplified to: \[ \operatorname{Var}(X \mid X eq 0) = \frac{\sigma^2(1 - p_0)}{(1 - p_0)^2} \]

Variance is a fundamental statistical measure used to understand the variability within a dataset.
Indicator Function
The indicator function is a simple yet powerful mathematical tool used to indicate when certain conditions are met. In this context, it is represented as \( 1_{\{X eq 0\}} \), which equals 1 when \( X eq 0 \) and 0 otherwise.

It acts like a switch to "turn on" certain values in computations only when the specified condition holds true. This property makes indicator functions extremely valuable in conditional probability and expectations.

It's because of this function that we can rewrite the expected value and variance formulas conditionally, applying them only to the subset of the sample space where our conditions hold. Mastering this concept opens the door to efficiently handling complex problems involving conditions, such as in our exercise when determining conditional outcomes.

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