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In Exercise 2 , if the coin is assumed fair, then, for \(n=2\), what are the probabilities associated with the values that \(X\) can take on?

Short Answer

Expert verified
For a fair coin with \(n=2\), the probabilities associated with the values that \(X\) can take on are: P(X=0) = 1/4, P(X=1) = 1/2, and P(X=2) = 1/4.

Step by step solution

01

Identify possible outcomes and corresponding probabilities for a single flip

Since the coins is fair, the only two outcomes from a single coin flip are: - A head (H) with a probability of P(H) = 1/2 - A tail (T) with a probability of P(T) = 1/2
02

Determine possible outcomes for flipping the coin twice

Considering all the combinations from two flips, we have: - HH: P(HH) = P(H) × P(H) = (1/2) × (1/2) = 1/4 - HT: P(HT) = P(H) × P(T) = (1/2) × (1/2) = 1/4 - TH: P(TH) = P(T) × P(H) = (1/2) × (1/2) = 1/4 - TT: P(TT) = P(T) × P(T) = (1/2) × (1/2) = 1/4
03

Calculate the probability for each possible value of \(X\)

Now, we calculate probabilities for each possible value of \(X\): - X = 0: 0 heads; only outcome is TT. P(X=0) = P(TT) = 1/4 - X = 1: 1 head; outcomes are HT and TH. P(X=1) = P(HT) + P(TH) = 1/4 + 1/4 = 1/2 - X = 2: 2 heads; only outcome is HH. P(X=2) = P(HH) = 1/4
04

Summarize the probabilities for each possible value of \(X\)

The probabilities associated with the values that \(X\) can take on when flipping a fair coin twice are: - P(X=0) = 1/4 - P(X=1) = 1/2 - P(X=2) = 1/4

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Most popular questions from this chapter

A coin, having probability \(p\) of landing heads, is flipped until head appears for the \(r\) th time. Let \(N\) denote the number of flips required. Calculate \(E[N]\). Hint: There is an easy way of doing this. It involves writing \(N\) as the sum of \(r\) geometric random variables.

Let \(X\) represent the difference between the number of heads and the number of tails obtained when a coin is tossed \(n\) times. What are the possible values of \(X ?\)

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