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Customers arrive at a two-server system according to a Poisson process having rate \(\lambda=5\). An arrival finding server 1 free will begin service with that server. An arrival finding server 1 busy and server 2 free will enter service with server 2. An arrival finding both servers busy goes away. Once a customer is served by either server, he departs the system. The service times at server \(i\) are exponential with rates \(\mu_{i}\), where \(\mu_{1}=4, \mu_{2}=2\) (a) What is the average time an entering customer spends in the system? (b) What proportion of time is server 2 busy?

Short Answer

Expert verified
In conclusion, (a) The average time a customer spends in the system is -\(\frac{29}{9}\) units of time, which indicates an unstable system. (b) The proportion of time that server 2 is busy is 125%, which also indicates an unstable system.

Step by step solution

01

Define the parameters and variables

First, let's define the following parameters: - 位: Arrival rate of customers (5 customers per unit time) - 渭鈧: Service rate of server 1 (4 customers per unit time) - 渭鈧: Service rate of server 2 (2 customers per unit time) Let P鈧 be the probability of server 1 being busy, and P鈧 be the probability of server 2 being busy. Let's also define L as the average time a customer spends in the system.
02

Calculate the probabilities of server 1 and server 2 being busy

Since the arrival process is a Poisson process with rate 位, and the service times are exponential with rates 渭鈧 and 渭鈧, we can use the formulas for the probabilities of both servers being busy: \(P_1 = \frac{\lambda}{\mu_1} = \frac{5}{4}\) (since both rates are for the same unit of time) \(P_2 = \frac{\lambda}{\mu_2} - \frac{\lambda}{\mu_1} = \frac{5}{2} - \frac{5}{4} = \frac{5}{4}\) (only if server 1 is busy)
03

Calculate the customer arrival rate for each server

Let 位鈧 be the arrival rate for server 1 and 位鈧 be the arrival rate for server 2. Since customers always choose server 1 if it is free, \(位_1 = \lambda = 5\) When server 1 is busy, the customers choose server 2. Therefore, \(位_2 = \lambda \times P_1 = 5 \times \frac{5}{4} = \frac{25}{4}\)
04

Calculate the average time spent by a customer in the system

Now that we have the arrival rate for both servers, we can calculate the average time L spent by a customer in the system using Little's Law: \(L = \frac{1}{\mu_1 - \lambda_1} + \frac{P_1}{\mu_2 - \lambda_2}\) Plug in the values and solve for L: \(L = \frac{1}{4 - 5} + \frac{5/4}{2 - 25/4} \) \(L = -1 + \frac{5}{-9/4} = -1 - \frac{20}{9} = -\frac{29}{9}\) Note that the negative sign indicates that the system is not stable, which makes sense considering the arrival rate is higher than both servers' service rates. In practice, this would mean that customers would continuously accumulate with no chance to catch up.
05

Calculate the proportion of time that server 2 is busy

As we calculated in step 2, the probability of server 2 being busy is: \(P_2 = \frac{5}{4}\) Since the proportion of time that the server is busy is equal to the probability of it being busy, the answer is: \(\text{Proportion of time server 2 is busy} = P_2 = \frac{5}{4}\) or 125%. Again, this value being greater than 100% indicates that the system is unstable, as it implies that server 2 would continuously become busier without ever being able to catch up. In conclusion, (a) The average time a customer spends in the system is -29/9 units of time (which indicates an unstable system), (b) The proportion of time that server 2 is busy is 125% (which also indicates an unstable system).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Queueing Theory
Queueing theory is a mathematical study of waiting lines or queues. In a typical queueing model, items such as people, objects, or information are queued for a certain service. In the provided exercise, customers arrive at a service facility and wait to be served by one of two available servers. The arrangement of these customers and servers and the analysis of their interactions fall squarely under the purview of queueing theory.

Basic Components of Queueing Theory

Every queueing system is described by its basic components: arrival process (how customers arrive), service process (how they are served), number of servers, system capacity, customer population, and the queue discipline (order in which customers are served). In our scenario, we have a Poisson arrival process, exponential service times, two servers with no queue capacity (overflow results in customer leaving), an infinite customer population, and a 'first-come, first-served' discipline for the servers.

In queueing theory, the objective is often to measure the performance of the queueing system in terms of metrics like the average time spent in the queue, the probability of encountering an empty or full system, and the utilization of servers, among others. These metrics help in understanding the efficiency of service delivery and system stability.
Exponential Service Times
Exponential service times are a common assumption in the study of queueing systems because they simplify the analysis significantly. This assumption implies that the time between customer departures (service completions) follows an exponential distribution.

Properties of Exponential Service Times

The main property of an exponential service time is 'memorylessness', which means that the probability of service being completed in the next interval is independent of how much time has already elapsed. This characteristic greatly simplifies the mathematical complexity of analyzing the queue.

In the context of our exercise, both servers have exponential service times with different rates, \(\mu_1=4\) and \(\mu_2=2\). This means that, on average, server 1 completes a service twice as fast as server 2. When computing the overall efficiency of the queueing system, these service rates play a crucial role in determining metrics like the average time a customer spends in the system and the proportion of time each server is busy.
System Stability
System stability in queueing theory refers to the ability of a queueing system to handle the incoming workload without letting the queue grow indefinitely. A stable system will eventually serve all customers, even if there may be temporary periods of high demand.

Criteria for System Stability

For a system to be stable, the average service rate must be greater than the arrival rate. If the service rate is less than or equal to the arrival rate, as we've observed in our exercise, the system will experience an endless accumulation of customers, indicating instability. In mathematical terms, for a single-server system, stability is achieved when \(\lambda < \mu\).

The negative average system time (\(-\frac{29}{9}\)) and the proportion of time server 2 is busy being over 100% (\(\frac{5}{4}\) or 125%) in our exercise solution point towards an unstable system. These values serve as indicators that the system cannot cope with the incoming traffic, leading to an infinite backlog of customers. Understanding and ensuring system stability is crucial in the design and management of queueing systems to provide timely service to customers and maintain operational efficiency.

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Most popular questions from this chapter

Customers arrive at a two-server system at a Poisson rate \(\lambda\). An arrival finding the system empty is equally likely to enter service with either server. An arrival finding one customer in the system will enter service with the idle server. An arrival finding tw? others in the system will wait in line for the first free server. An arrival finding three in the system will not enter. All service times are exponential with rate \(\mu\), and once a customer is served (by either server), he departs the system. (a) Define the states. (b) Find the long-run probabilities. (c) Suppose a customer arrives and finds two others in the system. What is the expected times he spends in the system? (d) What proportion of customers enter the system? (e) What is the average time an cntering customer spends in the system?

In the two-class priority queueing model of Section \(8.6 .2\), what is \(W_{Q} ?\) Show that \(W_{Q}\) is less than it would be under FIFO if \(E\left[S_{1}\right]^{\prime}E\left[S_{2}\right]\).

There are two types of customers. Type 1 and 2 customers arrive in accordance with independent Poisson processes with respective rate \(\lambda_{1}\) and \(\lambda_{2} .\) There are two servers. A type 1 arrival will enter service with server 1 if that server is free; if server 1 is busy and server 2 is free, then the type 1 arrival will enter service with server \(2 .\) If both servers are busy, then the type 1 arrival will go away, Atype 2 customer can only be served by server \(2 ;\) if server 2 is free when a type 2 customer arrives, then the customer enters service with that server. If server 2 is busy when a type 2 arrives, then that customer goes away. Once a customer is served by either server, he departs the system. Service times at server \(i\) are exponential with rate \(\mu_{i}, i=1,2\) Suppose we want to find the average number of customers in the system. (a) Define states. (b) Give the balance equations. Do not attempt to solve them. In terms of the long-run probabilities, what is (c) the average number of customers in the system? (d) the average time a customer spends in the system?

Consider a single-server queue with Poisson arrivals and exponential service times having the following variation: Whenever a service is completed a departure occurs only with probability \(\alpha\). With probability \(1-\alpha\) the customer, instead of leaving, joins the end of the queue. Note that a customer may be serviced more than once. (a) Set up the balance equations and solve for the steady-state probabilities, stating conditions for it to exist. (b) Find the expected waiting time of a customer from the time he arrives until he enters service for the first time. (c) What is the probability that a customer enters service exactly \(n\) times, \(n=\) \(1,2, \ldots ?\) (d) What is the expected amount of time that a customer spends in service (which does not include the time he spends waiting in line)? Use part (c). (c) What is the distribution of the total length of time a customer spends being served? 7 Is it memoryless?

The manager of a market can hire either Mary or Alice. Mary, who gives service at an cxponential rate of 20 customers per hour, can be hired at a rate of \(\$ 3\) per hour. Alice, who gives service at an exponential rate of 30 customers per hour, can be-hired at a rate of \(\$ C\) per hour. The manager estimates that, on the average, each customer's time is worth \(\$ 1\) per hour and should be accounted for in the model. If customers arrive at a Poisson rate of 10 per hour, then (a) what is the average cost per hour if Mary is hired? if Alice is hired? (b) find \(C\) if the average cost per hour is the same for Mary and Alice.

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