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Let \(\mathrm{P}\) be the transition probability matrix of a Markov chain. Argue that if for some positive integer \(r, \mathbf{P}^{r}\) has all positive entries, then so does \(\mathbf{P}^{n}\), for all integers \(n \geqslant r\).

Short Answer

Expert verified
Given that the transition probability matrix, 饾悘, of a Markov chain has all positive entries when raised to the 饾憻-th power, we can prove that 饾悘^n also has all positive entries for all integers 饾憶鈮ヰ潙. We show this by taking 饾悘^r and multiplying it by 饾悘^(n-r), using the matrix multiplication rule. Since the entries of both 饾悘^r and 饾悘^(n-r) are non-negative, their product 饾悘^n will have all positive entries. Thus, the statement holds for all integers 饾憶鈮ヰ潙.

Step by step solution

01

Recall Transition Probability Matrix properties

A transition probability matrix, 饾悘, is a square matrix representing the transition probabilities of a Markov chain. Each row sums to 1.
02

Recall matrix multiplication rule

For matrices 饾悁 and 饾悂, (饾悁饾悂)饾憱饾憲 = 危(饾悁饾憱饾憳 * 饾悂饾憳饾憲) for k=0 to n, where 饾悁 is n * n and 饾悂 is m * m.
03

Calculate 饾悘^r

Multiply the 饾悘 matrix r times, we get all positive entries in 饾悘^r.
04

Show that 饾悘^r * 饾悘^n-r has positive entries

We need to show that 饾悘^(饾憻+饾憶-饾憻) has positive entries, where n is an integer greater than or equal to r. Given 饾悘^r has all positive entries: apply the matrix multiplication rule to multiply 饾悘^r by 饾悘^(n-r). Since the entries of 饾悘^r are positive, and the entries of 饾悘^(n-r) are non-negative, the result of 饾悘^n = 饾悘^r * 饾悘^(n-r) will have all positive entries.
05

Conclude the proof

We've shown that if 饾悘^r has all positive entries for some positive integer 饾憻, then 饾悘^n = 饾悘^r * 饾悘^(n-r) has all positive entries for all integers 饾憶鈮ヰ潙. Therefore, the statement is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transition Probability Matrix
A Transition Probability Matrix is a fundamental concept in the study of Markov chains, which are mathematical systems that hop from one 'state' (a situation or configuration) to another. This matrix, usually denoted as \( \mathbf{P} \), is a square matrix where each entry \( p_{ij} \) represents the probability of moving from state \(i\) to state \(j\) within one time step. The key characteristics of this matrix are:
  • It is a stochastic matrix, meaning the entries are non-negative, and each row sums up to 1.
  • The size of the matrix is determined by the number of states in the Markov chain.
  • The matrix is used to describe the transition behavior of the system over time.

When analyzing the convergence of a Markov chain using its Transition Probability Matrix, one of your goals might be to determine whether, after a sufficient number of steps, the probabilities settle into a steady state. If given enough time, the Markov chain reaches a point where the probabilities do not change much; this is referred to as convergence. Understanding this concept lays the groundwork for grasping how \( \mathbf{P}^{r} \) with all positive entries affects the behavior of the Markov chain at subsequent steps.
Matrix Multiplication
Matrix multiplication is a critical operation when dealing with the Transition Probability Matrix in Markov chains. To multiply two matrices, such as \( \mathbf{A} \) and \( \mathbf{B} \) to obtain the matrix \( \mathbf{AB} \), you calculate the entries of the resulting matrix by summing the products of the corresponding entries of the rows of \( \mathbf{A} \) and the columns of \( \mathbf{B} \). The entry in row \(i\) and column \(j\) of \( \mathbf{AB} \) is given by:
  • \[ (\mathbf{AB})_{ij} = \Sigma (\mathbf{A}_{ik} * \mathbf{B}_{kj}) \] where \(k\) spans all the columns of \( \mathbf{A} \) and the rows of \( \mathbf{B} \).
  • To conduct matrix multiplication, the number of columns in the first matrix must equal the number of rows in the second matrix.

This operation is not commutative, meaning that \( \mathbf{AB} \) is not necessarily equal to \( \mathbf{BA} \). In the case of the Transition Probability Matrix \( \mathbf{P} \) for a Markov chain, raising \( \mathbf{P} \) to some power鈥攕uch as \( \mathbf{P}^{r} \)鈥攃an be viewed as performing matrix multiplication repetitively to model the transitions over multiple steps.
Positive Entries in Markov Chain Matrix
When discussing the convergence of Markov chains, the presence of positive entries in the Markov Chain Matrix after raising the transition matrix \( \mathbf{P} \) to a certain power \( r \) holds particular importance. It suggests that there is a positive probability of transitioning from any state to any other state in \( r \) steps. This can be summarized as follows:
  • If \( \mathbf{P}^{r} \) has all positive entries, it indicates that the Markov chain is irreducible and aperiodic after \( r \) steps, which are conditions for convergence to a steady state.
  • If \( \mathbf{P}^{r} \) is positive, then for all \( n \geqslant r \), \( \mathbf{P}^{n} \) will also have all positive entries. The proof follows from the understanding that multiplying \( \mathbf{P}^{r} \) by any subsequent matrix \( \mathbf{P}^{n-r} \) (where \( n > r \) by assumption) will yield a matrix with all positive entries due to the property of matrix multiplication where positive times non-negative yields positive.

This property assures us that not only does the process have a chance to move between any two states in a certain number of steps, but it also allows for the prediction of long-term behavior and the potential for reaching a steady-state distribution across the states.

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Most popular questions from this chapter

Consider the Ehrenfest urn model in which \(M\) molecules are distributed among two urns, and at each time point one of the molecules is chosen at random and is then removed from its urn and placed in the other one. Let \(X_{n}\) denote the number of molecules in urn 1 after the \(n\) th switch and let \(\mu_{n}=E\left[X_{n}\right]\). Show that (i) \(\mu_{n+1}=1+(1-2 / M) \mu_{n}\) (ii) Use (i) to prove that $$ \mu_{n}=\frac{M}{2}+\left(\frac{M-2}{M}\right)^{n}\left(E\left[X_{0}\right]-\frac{M}{2}\right) $$

(a) Show that the limiting probabilities of the reversed Markov chain are the same as for the forward chain by showing that they satisfy the equations $$ \pi_{j}=\sum_{i} \pi_{i} Q_{i j} $$ (b) Give an intuitive explanation for the result of part (a).

44\. Suppose that a population consists of a fixed number, say, \(m\), of genes in any generation. Each gene is one of two possible genetic types. If any generation Consider an irreducible finite Markov chain with states \(0,1, \ldots, N\). (a) Starting in state \(i\), what is the probability the process will ever visit state \(j\) ? Explaia! (b) Let \(x_{i}=P\) \\{visit state \(N\) before state 0|start in \(\left.i\right\\}\). Compute a set of linear equations which the \(x_{i}\) satisfy, \(i=0,1, \ldots, N\). (c) If \(\sum_{j} j P_{i j}=i\) for \(i=1, \ldots, N-1\), show that \(x_{i}=i / N\) is a solution to the equations in part (b).

A Markov chain is said to be a tree process if (i) \(P_{i j}>0\) whenever \(P_{j i}>0\). (ii) for every pair of states \(i\) and \(j, i \neq j\), there is a unique sequence of distinct states \(i=i_{0}, i_{1}, \ldots, i_{n-1}, i_{n}=j\) such that $$ P_{i_{k}, i_{k+1}}>0, \quad k=0,1, \ldots, n-1 $$ In other words, a Markov chain is a tree process if for every pair of distinct states \(i\) and \(j\) there is a unique way for the process to go from \(i\) to \(j\) without reentering a state (and this path is the reverse of the unique path from \(j\) to \(i\) ). Argue that an ergodic tree process is time reversible.

Consider three urns, one colored red, one white, and one blue. The red urn contains 1 red and 4 blue balls; the white urn contains 3 white balls, 2 red balls, and 2 blue balls; the blue urn contains 4 white balls, 3 red balls, and 2 blue balls. At the initial stage, a ball is randomly selected from the red urn and then returned to that urn. At every subsequent stage, a ball is randomly selected from the urn whose color is the same as that of the ball previously selected and is then returned to that urn. In the long run, what proportion of the selected balls are red? What proportion are white? What proportion are blue?

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