Chapter 2: Problem 2
Let \(X\) represent the difference between the number of heads and the number of tails obtained when a coin is tossed \(n\) times. What are the possible values of \(X\) ?
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Chapter 2: Problem 2
Let \(X\) represent the difference between the number of heads and the number of tails obtained when a coin is tossed \(n\) times. What are the possible values of \(X\) ?
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Let \(X_{1}, X_{2}, \ldots, X_{10}\) be independent Poisson random variables with mean \(1 .\) (a) Use the Markov inequality to get a bound on \(P\left\\{X_{1}+\cdots+X_{10} \geq 15\right\\}\). (b) Use the central limit theorem to approximate \(P\left(X_{1}+\cdots+X_{10} \geq 15\right\\}\).
Let \(X\) and \(W\) be the working and subsequent repair times of a certain
machine. Let \(Y=X+W\) and suppose that the joint probability density of \(X\) and
\(Y\) is
$$
f_{X, Y}(x, y)=\lambda^{2} e^{-\lambda y}, \quad 0
The density of \(X\) is given by $$ f(x)=\left\\{\begin{array}{ll} 10 / x^{2}, & \text { for } x>10 \\ 0, & \text { for } x \leq 10 \end{array}\right. $$ What is the distribution of \(X ?\) Find \(P[X>20\\}\).
The random variable \(X\) has the following probability mass function: $$ p(1)=\frac{1}{2}, \quad p(2)=\frac{1}{3}, \quad p(24)=\frac{1}{6} $$ Calculate \(E[X]\)
Suppose that we want to generate a random variable \(X\) that is equally likely to be either 0 or 1 , and that all we have at our disposal is a biased coin that, when flipped, lands on heads with some (unknown) probability \(p\). Consider the following procedure: 1\. Flip the coin, and let \(0_{1}\), either heads or tails, be the result. 2\. Flip the coin again, and let \(0_{2}\) be the result. 3\. If \(0_{1}\) and \(0_{2}\) are the same, return to step 1 . 4\. If \(0_{2}\) is heads, set \(X=0\), otherwise set \(X=1\). (a) Show that the random variable \(X\) generated by this procedure is equally likely to be either 0 or 1 . (b) Could we use a simpler procedure that continues to flip the coin until the last two flips are different, and then sets \(X=0\) if the final flip is a head, and sets \(X=1\) if it is a tail?
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