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Given the matrix $$ \mathbf{A}=\left(\begin{array}{rrr} 2 & 3 & 3 \\ 1 & -2 & 1 \\ -3 & -1 & 0 \end{array}\right) $$ find \(\mathbf{A}^{2}+3 \mathbf{A}+2 \mathbf{I}\), where \(\mathbf{I}\) is the \(3 \times 3\) identity matrix.

Short Answer

Expert verified
The short answer for this problem is: \(\mathbf{A^2}+3 \mathbf{A}+2 \mathbf{I} = \left(\begin{array}{rrr} 7 & 7 & 15 \\ 11 & -11 & 8 \\ -6 & 2 & -7 \end{array}\right)\).

Step by step solution

01

Calculate \(\mathbf{A^2}\)

To find the square of matrix A, we need to multiply it by itself: $$\mathbf{A^2} = \mathbf{A} \times \mathbf{A}$$ Let's perform the matrix multiplication to get $$\mathbf{A^2}$$: $$ \mathbf{A^2}=\left(\begin{array}{rrr} 2 & 3 & 3 \\ 1 & -2 & 1 \\ -3 & -1 & 0 \end{array}\right) \times \left(\begin{array}{rrr} 2 & 3 & 3 \\ 1 & -2 & 1 \\ -3 & -1 & 0 \end{array}\right) =\left(\begin{array}{rrr} -1 & -2 & 6 \\ 8 & -7 & 5 \\ 3 & 5 & -9 \end{array}\right) $$
02

Calculate \(3\mathbf{A}\)

Next, we need to multiply each element of matrix A by 3: $$3\mathbf{A} = 3 \times \left(\begin{array}{rrr} 2 & 3 & 3 \\ 1 & -2 & 1 \\ -3 & -1 & 0 \end{array}\right) = \left(\begin{array}{rrr} 6 & 9 & 9 \\ 3 & -6 & 3 \\ -9 & -3 & 0 \end{array}\right) $$
03

Calculate \(2\mathbf{I}\)

Create a 3x3 identity matrix (I) and multiply it by 2: $$2\mathbf{I} = 2 \times \left(\begin{array}{rrr} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array}\right) = \left(\begin{array}{rrr} 2 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 2 \end{array}\right) $$
04

Calculate \(\mathbf{A^2} + 3\mathbf{A} + 2\mathbf{I}\)

Now, let's add the matrices calculated in steps 1, 2, and 3: $$ \mathbf{A^2} + 3\mathbf{A} + 2\mathbf{I} = \left(\begin{array}{rrr} -1 & -2 & 6 \\ 8 & -7 & 5 \\ 3 & 5 & -9 \end{array}\right) + \left(\begin{array}{rrr} 6 & 9 & 9 \\ 3 & -6 & 3 \\ -9 & -3 & 0 \end{array}\right) + \left(\begin{array}{rrr} 2 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 2 \end{array}\right) $$ $$ = \left(\begin{array}{rrr} (-1 + 6 + 2) & (-2 + 9 + 0) & (6 + 9 + 0) \\ (8 + 3 + 0) & (-7 + (-6) + 2) & (5 + 3 + 0) \\ (3 + (-9) + 0) & (5 + (-3) + 0) & (-9 + 0 + 2) \end{array}\right) $$ $$ = \left(\begin{array}{rrr} 7 & 7 & 15 \\ 11 & -11 & 8 \\ -6 & 2 & -7 \end{array}\right) $$ Thus, the resulting matrix is: $$ \mathbf{A^2}+3 \mathbf{A}+2 \mathbf{I} = \left(\begin{array}{rrr} 7 & 7 & 15 \\ 11 & -11 & 8 \\ -6 & 2 & -7 \end{array}\right) $$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Multiplication
Matrix multiplication is a fundamental operation in linear algebra. Unlike element-wise multiplication, matrix multiplication involves a row-by-column product. For two matrices, say \( \mathbf{A} \) and \( \mathbf{B} \), to be multiplicable, the number of columns in \( \mathbf{A} \) must be equal to the number of rows in \( \mathbf{B} \).
The resulting matrix, known as the product matrix, has dimensions determined by the rows of the first and columns of the second matrix involved in the operation.

The process can be thought of as taking a row from the first matrix and a column from the second matrix, then multiplying the corresponding elements and adding them together to form a single entry in the product matrix.

In the given exercise, matrix multiplication occurs when we calculate \( \mathbf{A}^{2} \) by multiplying matrix \( \mathbf{A} \) with itself. The operation is conducted by following the row-by-column rule for each element of the resulting matrix \( \mathbf{A}^{2} \).
Identity Matrix
The identity matrix, often symbolized as \( \mathbf{I} \), plays a crucial role in matrix operations, serving as the multiplicative identity in the matrix world. This means any matrix \( \mathbf{A} \) multiplied by an identity matrix \( \mathbf{I} \) results in the original matrix \( \mathbf{A} \).
An identity matrix is always square with a size of \( n \times n \) and it has ones on the diagonal and zeros everywhere else. The pattern looks like this for a 3x3 identity matrix: \[ \left(\begin{array}{ccc} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{array}\right) \]

In the exercise, \( 2 \mathbf{I} \) refers to each element of the identity matrix being multiplied by 2. This operation does not change the position of the ones but rather scales them by the factor provided.
Matrix Addition
Matrix addition is another fundamental operation in which two matrices of the same dimensions are added together element-wise. The rule is simple: just add the numbers that are in the same position in each matrix.

For example, if you have two matrices \( \mathbf{A} \) and \( \mathbf{B} \) of the same size, their sum \( \mathbf{A} + \mathbf{B} \) would result in a matrix where each element \( c_{ij} \) is the sum of elements \( a_{ij} \) and \( b_{ij} \) from the original matrices.

In our exercise, the final step requires us to add the matrices \( \mathbf{A^2} \), \( 3 \mathbf{A} \) and \( 2 \mathbf{I} \) together, following this element-wise addition rule. The resultant matrix combines the values from each of these matrices into one final matrix.

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Most popular questions from this chapter

Find the inverse of the given matrix \(\mathbf{A}\) in each of Exercises 13-24. $$ \mathbf{A}=\left(\begin{array}{rrr} 1 & 0 & -1 \\ 4 & 2 & 1 \\ 2 & 1 & 3 \end{array}\right) $$

Find the general solution of each of the linear systems in Exercises 1-26. $$ \begin{aligned} &x^{\prime}=x-4 y \\ &y^{\prime}=x+y \end{aligned} $$

Given the matrices \(\mathbf{A}\) and \(\mathbf{B}\), find the product \(\mathbf{A B}\). Also, find the product BA in each case in which it is defined. $$ \mathbf{A}=\left(\begin{array}{rr} 5 & -2 \\ 4 & 3 \end{array}\right), \quad \mathbf{B}=\left(\begin{array}{rr} -1 & 8 \\ 2 & -5 \end{array}\right) $$

Two tanks \(\mathrm{X}\) and \(\mathrm{Y}\) are interconnected. Tank \(\mathrm{X}\) initially contains 30 liters of brine in which there is dissolved \(30 \mathrm{~kg}\) of salt, and tank \(\mathrm{Y}\) initially contains 30 liters of pure water. Starting at time \(t=0,(1)\) brine containing \(1 \mathrm{~kg}\) of salt per liter flows into tank \(\mathrm{X}\) at the rate of 2 liters/min and pure water also flows into \(\operatorname{tank} \mathrm{X}\) at the rate of 1 liter/min, (2) brine flows from tank \(\mathrm{X}\) into tank \(Y\) at the rate of 4 liters \(/ \mathrm{min}\), (3) brine is pumped from tank \(Y\) back into \(\operatorname{tank} \mathrm{X}\) at the rate of 1 liter/min, and (4) brine flows out of tank \(\mathrm{Y}\) and away from the system at the rate of 3 liters/min. The mixture in each tank is kept uniform by stirring. How much salt is in each tank at any time \(t>0\) ?

Consider the vector functions \(\phi_{1}\) and \(\phi_{2}\) defined by $$ \phi_{1}(t)=\left(\begin{array}{l} t \\ 1 \end{array}\right) \text { and } \phi_{2}(t)=\left(\begin{array}{c} t e^{t} \\ e^{t} \end{array}\right) $$ respectively. Show that the constant vectors \(\phi_{1}\left(t_{0}\right)\) and \(\phi_{2}\left(t_{0}\right)\) are linearly dependent for each \(t_{0}\) in the interval \(0 \leq t \leq 1\), but that the vector functions \(\phi_{1}\) and \(\phi_{2}\) are linearly independent on \(0 \leq t \leq 1 .\)

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