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Chapter 6: Q.39 (page 386)

About what percent of xvalues lie between the first and second standard deviations from the mean (both sides)?

Short Answer

Expert verified

About 27% of the x values from normal distribution will lie between first and second standard deviation.

Step by step solution

01

Given information

Given in the question that, We have to find the percent of xvalues lie between the first and second standard deviations from the mean (both sides)

02

Explanation

According to the empirical rule of normal distribution, within one standard deviation of the mean, there are approximately 68%values of xlies and within two standard deviations of the mean, there are approximately95%values of xlies. So, the percent of the xvalues from normal distribution lie between first and second standard deviation from the mean will be:

=95%鈭�68%

=27%

Therefore, about 27% of the x values from normal distribution will lie between first and second standard deviation.

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Most popular questions from this chapter

The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.3days and a standard deviation of 2.1days.

The 90thpercentile for recovery times is

a. 8.89

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d. 4.32

Terri Vogel, an amateur motorcycle racer, averages 129.71seconds per 2.5mile lap (in a seven-lap race) with a standard deviation of 2.28seconds. The distribution of her race times is normally distributed. We are interested in one of her randomly selected laps.

a. In words, define the random variable X.

b. X~,

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The life of Sunshine CD players is normally distributed with a mean of 4.1years and a standard deviation of 1.3years. A CD player is guaranteed for three years. We are interested in the length of time a CD player lasts. Find the probability that a CD player will break down during the guarantee period.

a. Sketch the situation. Label and scale the axes. Shade the region corresponding to the probability.

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If the area to the left of xin a normal distribution is 0.123, what is the area to the right of x?

X~N(1,2)

蟽=
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