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The mean number of minutes for app engagement by a table use is 8.2 minutes. Suppose the standard deviation is one minute. Take a sample size of 70.

a. What is the probability that the sum of the sample is between seven hours and ten hours? What does this mean in context of the problem?

b. Find the 84thand 16thpercentiles for the sum of the sample. Interpret these values in context.

Short Answer

Expert verified

(a)The probability that the sum of samples lies between7hours and 10hours is 0.9991.

(b)84thand 16thpercentile for the sums of sample are respectively 582.31and 565.68minutes.

Step by step solution

01

Given information (part a)

Given in the question that, The mean number of minutes for app engagement by a table use is8.2 minutes. Suppose the standard deviation is one minute. Take a sample size of70.

02

Explanation(part a)

According to the provided facts, the mean number of minutes for app engagement by a tablet user is 8.2minutes, the standard deviation is 1minute and the sample size is70.

The mean and standard deviation will follow the normal distribution. So, the distribution of sum of ages of tablet users is given as:

ΣX~NnμX,nσX

∑X~N(70×8.2,70×1)

∑X~N(574,8.366)

03

Probability

Consider 7hours as 420minutes and the 10hours as 600minutes. To find the probability that the sum of samples lies between 7hours and10hours, use the Ti-83 calculator. For this, click on 2nd, then DISTR, and then scroll down to the normcdf option and enter the provided details. After this, click on ENTER button on the calculator to have the desired result. The screenshot is given below:

Therefore, the probability that the sum of samples lies between7hours and10hours is0.9991.

04

Final answer(part a)

The probability that the sum of samples lies between 7hours and 10hours is0.9991.

05

Given information(part b)

Given in the question that, The mean number of minutes for app engagement by a table use is8.2minutes. Suppose the standard deviation is one minute. Take a sample size of 70.

06

Explanation(part b)

According to the provided details, the mean number of minutes for app engagement by a tablet user is 8.2minutes, standard deviation is 1minute and the sample size is 70.

The mean and standard deviation will follow the normal distribution. So, the distribution of sum of ages of tablet users is given as:

∑X−NnμX,nσX

∑X~N(70×8.2,70×1)

∑X~N(574,8.366)

07

Calculate 84th  and 16th  percentile for the sums of sample.

To calculate 84thand 16thpercentile for the sums of sample, use Ti-83 calculator. For this, click on 2nd, then DISTR, and then scroll down to the invnorm option and enter the provided details. After this, click on ENTER button on the calculator to have the desired result. The screenshot is given below:

Therefore,84thand 16th percentile for the sums of sample are respectively 582.31 and 565.68 minutes.

08

Final answer(part b)

84th and 16th percentile for the sums of sample are respectively 582.31 and 565.68 minutes.

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