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91Ó°ÊÓ

Complete the distributions.

a.X~ _____(_____,_____)

b. role="math" localid="1648618952256" X¯~_____(_____,_____)

Short Answer

Expert verified

(a)X~N(4,1.2)

(b)x¯~N4,0.3

Step by step solution

01

Given information (part a)

Given in the question that, Yoonie is a personnel manager in a large corporation. Each month she must review 16 of the employees. From past experience, she has found that the reviews take her approximately four hours each to do with a population standard deviation of 1.2 hours. Let Χ be the random variable representing the time it takes her to complete one review. Assume Χ is normally distributed. Let role="math" localid="1648619084184" x¯{"x":[[4,22,36],[6,35],[-3.9209055258786822,-3.05105441584673,-2.181203305814778,-0.44150108575087355,1.2982011343130309,2.1680522443449832,3.9077544644088875,4.777605574440839,5.647456684472792,7.3871589045366965,9.1268611246006,11.736414454696456,12.606265564728409,14.345967784792315,16.08567000485622,16.95552111488817,18.695223334952075,19.565074444984027,20.43492555501598,21.30477666504793,23.044478885111836,23.914329995143788,24.78418110517574,25.654032215207693,26.523883325239645,28.26358554530355,29.1334366553355,30.873138875399405,31.742989985431358,32.61284109546331,33.48269220549526,34.352543315527214,35.222394425559166,36.09224553559112,36.96209664562307,37.83194775565502,38.701798865686975,39.57164997571893]],"y":[[9,59,116],[115,9],[-7.957939912588121,-7.957939912588121,-7.957939912588121,-7.957939912588121,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-8.827791022620074,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-10.567493242683978,-10.567493242683978,-10.567493242683978,-10.567493242683978,-10.567493242683978]],"t":[[0,0,0],[0,0],[1648619081077,1648619081316,1648619081333,1648619081348,1648619081365,1648619081382,1648619081399,1648619081416,1648619081432,1648619081449,1648619081466,1648619081483,1648619081499,1648619081515,1648619081533,1648619081549,1648619081565,1648619081582,1648619081599,1648619081616,1648619081633,1648619081649,1648619081666,1648619081682,1648619081699,1648619081717,1648619081747,1648619081765,1648619081782,1648619081801,1648619081815,1648619081832,1648619081849,1648619081885,1648619081905,1648619081949,1648619081967,1648619082015]],"version":"2.0.0"}be the random variable representing the mean time to complete the re16views. Assume that the16reviews represent a random set of reviews.

02

Explanation(part a)

According to the provided details, the time for each review (X)is normally distributed, the meantime for each review is 4hours and the standard deviation is 1.2hours and the sample size is 16employees.

The normal distribution with mean (μ)and standard deviation (σ)is given as:

X~N(μ,σ)

So, the distribution time for each review (X)is given as below:

X~N(4,1.2)

03

Final answer(part a)

X~N(4,1.2)

04

Given information(part b)

Given in the question that, Yoonie is a personnel manager in a large corporation. Each month she must review 16of the employees. From past experience, she has found that the reviews take her approximately four hours each to do with a population standard deviation of1.2hours. LetΧbe the random variable representing the time it takes her to complete one review. Assume Χis normally distributed. Let x¯{"x":[[4,22,36],[6,35],[3.9077544644088875,5.647456684472792,8.257010014568648,10.866563344664504,12.606265564728409,14.345967784792315,16.08567000485622,18.695223334952075,21.30477666504793,23.044478885111836,23.914329995143788,24.78418110517574,26.523883325239645,27.393734435271597,29.1334366553355,30.003287765367453,30.873138875399405,31.742989985431358,32.61284109546331,33.48269220549526,34.352543315527214,35.222394425559166,36.09224553559112]],"y":[[9,59,116],[115,9],[-8.827791022620074,-8.827791022620074,-8.827791022620074,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026,-9.697642132652026]],"t":[[0,0,0],[0,0],[1648622070284,1648622070510,1648622070527,1648622070546,1648622070560,1648622070576,1648622070594,1648622070610,1648622070626,1648622070645,1648622070663,1648622070677,1648622070693,1648622070709,1648622070727,1648622070746,1648622070763,1648622070777,1648622070809,1648622070847,1648622070893,1648622070943,1648622070984]],"version":"2.0.0"}be the random variable representing the mean time to complete the 16reviews. Assume that the 16reviews represent a random set of reviews.

05

Explanation(part b)

According to the provided details, the time for each review(X)is normally distributed, the meantime for each review is 4hours and the standard deviation is 1.2hours and the sample size is 16employees.

The distribution for the sample mean (X¯)is given as below:

role="math" localid="1648622435181" X¯~Nμx,σxn

role="math" localid="1648622812034" X¯~N4,1.216

x¯~N4,0.3

06

Final answer(part b)

x¯~N4,0.3

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Most popular questions from this chapter

Find the sum that is 1.5 standard deviations below the mean of the sums.

Determine which of the following are true and which are false. Then, in complete sentences, justify your answers.

a. When the sample size is large, the mean of X¯is approximately equal to the mean of X.

b. When the sample size is large, X¯is approximately normally distributed.

c. When the sample size is large, the standard deviation of X¯is approximately the same as the standard deviation of X.

Yoonie is a personnel manager in a large corporation. Each month she must review 16of the employees. From past experience, she has found that the reviews take her approximately four hours each to do with a population standard deviation of 1.2hours. Let Χ be the random variable representing the time it takes her to complete one review. Assume Χ is normally distributed. Let x-be the random variable representing the meantime to complete the 16reviews. Assume that the 16reviews represent a random set of reviews.

Find the probability that one review will take Yoonie from 3.5to 4.25hours. Sketch the graph, labeling and scaling the horizontal axis. Shade the region corresponding to the probability

b. P(________ <x< ________) = _______

In a city, 46percent of the population favor the incumbent, Dawn Morgan, for mayor. A simple random sample of500is taken. Using the continuity correction factor, find the probability that at least 250 favor Dawn Morgan for mayor.

The distribution of income in some Third World countries is considered wedge shaped (many very poor people, very few middle income people, and even fewer wealthy people). Suppose we pick a country with a wedge shaped distribution. Let the average salary be \(2,000per year with a standard deviation of \)8,000. We randomly survey 1,000residents of that country.

a. In words,Χ=_____________

b. In words,X=_____________

c.X¯~_____(_____,_____)

d. How is it possible for the standard deviation to be greater than the average?

e. Why is it more likely that the average of the 1,000residents will be from \(2,000to \)2,100than from \(2,100to\)2,200?

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