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Find the sum that is one standard deviation above the mean of the sums.

Short Answer

Expert verified

The required sum is∑X=7326.49.

Step by step solution

01

Given Information

A sample size (n)=40.

The mean of population μX=180.

z=1.

A standard deviation σX=20.

02

Explanation

To find the sum that is one standard deviation above the mean of the sums :

∑X=(n)μX+(z)(n)σX

Calculating, we have:

∑X=40×180+1×40×20

∑X=7326.49

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