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Chapter 3: Q3.12 (page 187)

Mark is deciding which route to take to work. His choices are I = the Interstate and F = Fifth Street.

鈥�P(I)=0.44andP(F)=0.56

鈥� role="math" localid="1652098516712" P(I鈭�F)=0because Mark will take only one route to work.

What is the probability of P(IORF)?

Short Answer

Expert verified

P(IorF)=1

Step by step solution

01

Basic Concept

Probability is the likelihood of an event.

As per probability rule,

P(AUB)=P(A)+P(B)-P(A鈭�B)

02

Explanation 

It is given that Mark takes Interstate or fifth street route to work, withPr(I)andPr(F)=0.44and0.56 respectively.

As he can take only one route & both routes can never be taken together, so these events are mutually exclusive, represented by disjoint sets whose intersection i.e.P(I&F)=P(I鈭�F)=0

So,P(IorF)=P(IUF)=P(I)+P(F)-P(I鈭�F)

P(IorF)=0.44+0.56=1

This shows - it is certain that Mark will take either route to work

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