91Ó°ÊÓ

We are given:

$86.5\%$commute through various modes of transport

$84.6\%$drive alone

$15.4\%$drive in carpool

$3.9\%$walk to work

$5.3\%$take public transport

Probability of an event is defined as:$P=\frac{Numberoffavorableoutcomes}{totalnumberofpossibleoutcomes}$

The table representation is as follow:

The probability of an event $E$is calculated as:

$P=\frac{Numberoffavorableoutcomes}{totalnumberofpossibleoutcomes}$

From the table represented in step 2, we have alone travellers $=0.7318,$and walking travellers total is$0.0390$

The probability of all commuters that travel alone to work is as follows:

$$\begin{gathered} 0.7318+0.0390 \\ =0.7708 \\ =77.08\% \end{gathered}$$

The probability of an event $E$is,

$P=\frac{Numberoffavorableoutcomes}{totalnumberofpossibleoutcomes}$

From the table we have

The probability of all commuters travelling alone to work $=0.7708$

Total number of workers $1000$

Thus a number of workers who would want to travel alone to work is calculated as:

$$\begin{gathered} 0.7708×1000 \\ =770.8 \\ =771 \end{gathered}$$

Probability of an event $E$is

$P=\frac{Numberoffavorableoutcomes}{totalnumberofpossibleoutcomes}$

The probability of all commuters driving in carpool is$0.1332$

Total number of workers $1000$

Thus, number of workers who would travel in carpool is

$$\begin{gathered} 0.1332×1000 \\ =133.2 \\ =133 \end{gathered}$$