91影视

G and H are mutually exclusive events.$P\left(G\right)=0.5\text{and}P\left(H\right)=0.3$

Given that $P\left(G\right)=0.5\text{and}P\left(H\right)=0.3$

We need to calculate $P\left(H|G\right)$

$$\begin{gathered} P\left(GandH\right)=P\left(G|H\right)脳P\left(H\right) \\ P\left(G|H\right)=\frac{P\left(GandH\right)}{P\left(H\right)} \end{gathered}$$

Also, G and H are mutually exclusive events,

$P\left(GandH\right)=0$

Thus, we have

localid="1649420858160" $$\begin{gathered} P\left(G|H\right)=\frac{0}{0.3} \\ P\left(G|H\right)=0 \end{gathered}$$

G and H are mutually events.$P\left(G\right)=0.5\text{and}P\left(H\right)=0.3$

$P\left(G\right)=0.5\text{and}P\left(H\right)=0.3$

Also, GandH are mutually exclusive events,

$P\left(G\text{and}H\right)=0$

Thus, $P\left(H\text{or}G\right)$is calculated as

$$\begin{gathered} P\left(HorG\right)=P\left(H\right)+P\left(G\right)-P\left(H\text{and}G\right) \\ P\left(HorG\right)=0.3+0.5-0 \\ P\left(HorG\right)=0.8 \end{gathered}$$

G and H are mutually exclusive events.$P\left(G\right)=0.5\text{and}P\left(H\right)=0.3$

Given that G and H are mutually exclusive events,

$P\left(G\text{and}H\right)=0$

The information that one event has occurred completely determines the probability of the other event, which is zero in this case. Thus, both events cannot occur at the same time, and therefore the events are dependent on each other.