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Use the following information to answer the next two exercises. The percent of licensed U.S. drivers (from a recent year) that are female is 48.60. Of the females, 5.03% are age 19 and under; 81.36% are age 20–64; 13.61% are age 65 or over. Of

the licensed U.S. male drivers, 5.04% are age 19 and under; 81.43% are age 20–64; 13.53% are age 65 or over.

Suppose that 10,000 U.S. licensed drivers are randomly selected.

a. How many would you expect to be male?

b. Using the table or tree diagram, construct a contingency table of gender versus age group.

c. Using the contingency table, find the probability that out of the age 20–64 group, a randomly selected driver is female.

Short Answer

Expert verified

a. P(M)=0.514

b.


<2020–64>64Totals
Female0.02440.39540.06610.486
Male0.02590.41860.06950.514
Totals0.05030.8140.13561

c.P(F20-64)=0.4857

Step by step solution

01

Given information

The percent of licensed U.S. drivers (from a recent year) that are female is 48.60.

Of the females, 5.03% are age 19 and under; 81.36% are age 20–64; 13.61% are age 65 or over.

Of the licensed U.S. male drivers, 5.04% are age 19 and under; 81.43% are age 20–64; 13.53% are age 65 or over.

02

(part a)

The male drivers are randomly selected and the probability is given by

P(M)=0.514

03

Explanation (part b)

a contingency table of gender versus age group is given by


<2020–64>64Totals
Female0.02440.39540.06610.486
Male0.02590.41860.06950.514
Totals0.05030.8140.13561
04

Explanation (part c)

Using the contingency table, find the probability that out of the age 20–64 group, a randomly selected driver is female.


<2020–64>64Totals
Female0.02440.39540.06610.486
Male0.02590.41860.06950.514
Totals0.05030.8140.13561

P(F20-64)=Totalnumberoffemaledriversinage20-64totalnumberofdriversinage20-64P(F20-64)=0.39540.814P(F20-64)=0.4857

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