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A box has two balls, one white and one red. We select one ball, put it back in the box, and select a second ball (sampling with replacement). Let T be the event of getting the white ball twice, F the event of picking the white ball first, S the event of picking the white ball in the second drawing.

a. Compute P(T).

b. Compute P(T|F).

c. Are T and F independent?.

d. Are F and S mutually exclusive?

e. Are F and S independent?

Short Answer

Expert verified

P(T) = 1/4; P (T | F) =1/4

T & F are not independent ; F & S are not mutually exclusive ; F & S are independent.

Step by step solution

01

Probabilities calculation 

  • Pr(T)= P (getting white ball twice)

Pr (getting white ball once) = 1/2; P (get white ball again, with replacement) = 1/2

So, P(T)= 1/2x1/2=1/4

  • Pr(TIF)= Pr getting white ball twice, given first ball is white

= P(T∩F)/P(F)

= ( 1 /4 ) / ( 1 / 2 )

= 1 / 2

02

Independent & mutually exclusive events 

Independent Events are those where occurrence of one event doesn't effect the occurrence of other event. Mutually Exclusive events are those which cannot happen simultaneously.

  • Events T & F are not independent, as event F ie getting first white ball effects event T ie getting the white ball twice.
  • Events F & S are not mutually exclusive, as event F ie getting first white ball & event S picking the second white ball - can happen together
  • Events F & S are independent, as event F ie getting first white ball & event S picking the second white ball - do not effect each other.

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