Q. 12. 7 For a given line of best fit, yo... [FREE SOLUTION]

91影视

Introductory Statistics

Barbara Illowsky, Susan Dean

$Math Studyset 91影视 Explanations$ Math

OER 2018 Edition 路 902 pages

ISBN: 9781938168208

Chapter 12: Q. 12. 7 (page 694)

For a given line of best fit, you computed that $r = 0.6501$ using $n = 12$ data points and the critical value is $0.576$ . Can the line be used for prediction? Why or why not?

Short Answer

Expert verified

Yes. the line can be used for the prediction because $r > c r i t i c a l v a l u e$

Step by step solution

Given information

For a given line of best fit, we computed that $r = 0.6501$ using $n = 12$ data points and the critical value is $0.576$ .

Explanation

Suppose you computed $r = 0.6501$ using $n = 12$ data points.

$d f = n - 2 = 12 - 2 = 10 .$

The critical values associated with $d f = 12$ are $- 0.576$ and $+ 0.576$ . If $r <$ negative critical value or $r >$ positive critical value, then $r$ is significant.

Since $r = 0.6501$ and $0.6501 > 0.576$ , $r$ is significant and the line may be used for prediction.

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91影视

For a given line of best fit, you computed that $r = 0.6501$ using $n = 12$ data points and the critical value is $0.576$ . Can the line be used for prediction? Why or why not?

Short Answer

Step by step solution

Given information

Explanation

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91影视

For a given line of best fit, you computed that r=0.6501using n=12data points and the critical value is 0.576. Can the line be used for prediction? Why or why not?

Short Answer

Step by step solution

Given information

Explanation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Probability and Statistics

Geometry

Theoretical and Mathematical Physics

Decision Maths

Mechanics Maths

Statistics

Study anywhere. Anytime. Across all devices.

For a given line of best fit, you computed that $r = 0.6501$ using $n = 12$ data points and the critical value is $0.576$ . Can the line be used for prediction? Why or why not?