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Calculate the test statistic and p-value.

Short Answer

Expert verified

The value of test statistics is 5.421and the p-value is 0

Step by step solution

01

Given information

Given following data

02

Simplify 

Finding standard error

SE=s12n1+s22n2=4.26853=2.06604

Test statistics is t=μӬ-μηӬSE=45.3-34.12.06604=5.421

let us determine the number of degrees of freedom using the formula from 10.1:

df=SE4S14+s24n12(n1-1)+n22(n2-1)=2.0660440.12249=148.749

using the above formula we get p-value is0

03

Graphical representation 

Student's t distribution

X~t(df)

μ=E(X)=0α=SD(X)=1.007α2=Var(X)=1.014

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