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94. Parents of teenage boys often complain that auto insurance costs more, on average, for teenage boys than for teenage girls. A group of concerned parents examines a random sample of insurance bills. The mean annual cost for 36 teenage boys was \(679. For 23 teenage girls, it was \)559. From past years, it is known that the population standard deviation for each group is $180. Determine whether or not you believe that the mean cost for auto insurance for teenage boys is greater than that for teenage girls.

Short Answer

Expert verified

Subscripts:1=boys, 2=girls
(a) The null hypothesis: H0:μ1≤μ2
(b) The alternate hypothesis:Ha:μ1>μ2
(c) The difference in the mean auto insurance costs for boys and girls is the random variable.
(d) Normal distribution.
(e) The test statistic: z=2.50
(f) Thep-value: 0.0062
(g) Check student's solution.
(h) (i) Alpha: 0.05
(ii) Decision: Reject the null hypothesis.
(iii) Reason for Decision: p-value <α.
(iv) As a result, there is sufficient evidence to conclude that the mean cost of auto insurance for teenage boys is greater than that for girls at the 5%significance level.

Step by step solution

01

Given information

To determine the mean cost for auto insurance for teenage boys is greater than that for teenage girls. Then to conduct a hypothesis test to evaluate the manufacturers claim.

02

Explanation

Subscripts : 1=boys, 2=girls
(a) The null hypothesis is described as follows:
H0:μ1≤μ2
(b) The alternate hypothesis is described as follows:
Ha:μ1>μ2
(c) The difference in the mean auto insurance costs for boys and girls is the random variable.
(d) Normal distribution.
(e) To determine the test static as:
To access the stat list editor, click STAT and then 1.

Then ENTER all the values the OUTPUT will be:

Hence, the test statistics is 2.497.

03

Explanation

(f) The p-value from the output is determined as 0.00625.
(g) Obtain a clear picture of the situation using the information from the last task.
The horizontal axis should be named and measured, and the region(s) on the graph that correlate to the p-value should be shaded.

(h)

(i) α=0.05
(ii) Decision: reject the null hypothesis.
(iii) Reason for Decision: p-value <α.
(iv) As a result, there is enough proof to conclude that the mean cost of auto insurance for teenage boys is more than that for girls, at the 5%level of significance.

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