/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 80 At Rachel’s \(11th\) birthday ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

At Rachel’s \(11th\) birthday party, eight girls were timed to see how long (in seconds) they could hold their breath in a relaxed position. After a two-minute rest, they timed themselves while jumping. The girls thought that the mean difference between their jumping and relaxed times would be zero. Test their hypothesis.

Short Answer

Expert verified

Considering the table 10.24 the data consists of matched samples,

1. The null hypothesis is given by, \(H_{0}:\mu_{d}=0\)

2. Alternate hypothesis is given by, \(H_{a}:\mu_{d}\neq 0\)

3. The random variable \(X_{d}\) is the average difference between jumping and relaxed times.

4. Student’s t distribution with \(7\) degree of freedom

5. The paired test static for the mean difference is,

After ENTER all values the OUTPUT shown below,

6. The \(p-value\) from the output is \(0.175\)

7. Using the information from previous exercise to sketch a picture of this situation.

Clearly label and scale the horizontal axis, and shade the graph the region(s) corresponding to the \(p-\)value.

8. \(\alpha=0.05\)

Decision: Null hypothesis is not rejected.

\(p-value>alpha\)

Conclusion: At the \(5%\) level of significance, there is insufficient evidence to conclude that the average difference is not zero.

Step by step solution

01

Step 1. Given information

Given table,

02

Step 2. Calculation

Considering the table 10.24 the data consists of matched samples,

1. The null hypothesis is given by, \(H_{0}:\mu_{d}=0\)

2. Alternate hypothesis is given by, \(H_{a}:\mu_{d}\neq 0\)

3. The random variable \(X_{d}\) is the average difference between jumping and relaxed times.

4. Student’s t distribution with \(7\) degree of freedom

5. The paired test static for the mean difference is,

After ENTER all values the OUTPUT shown below,

6. The \(p-value\) from the output is \(0.175\)

7. Using the information from previous exercise to sketch a picture of this situation.

Clearly label and scale the horizontal axis, and shade the graph the region(s) corresponding to the \(p-\)value.

8. \(\alpha=0.05\)

Decision: Null hypothesis is not rejected.

\(p-value>alpha\)

Conclusion: At the \(5%\) level of significance, there is insufficient evidence to conclude that the average difference is not zero.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two samples are shown in Table 10.2. Both have normal distributions. The means for the two populations are thought to be the same. Is there a difference in the means? Test at the 5% level of significance.

Two types of valves are being tested to determine if there is a difference in pressure tolerances. Fifteen out of a random sample of 100of Valve Acracked under 4500psi.Six out of a random sample of 100of Valve Bcracked under 4500psi.Test at a5% level of significance.

Use the following information to answer the next 12 exercises: The U.S. Center for Disease Control reports that the mean life expectancy was 47.6 years for whites born in 1900 and 33.0 years for nonwhites. Suppose that you randomly survey death records for people born in 1900 in a certain county. Of the 124 whites, the mean life span was 45.3 years with a standard deviation of 12.7 years. Of the 82 nonwhites, the mean life span was 34.1 years with a standard deviation of 15.6 years. Conduct a hypothesis test to see if the mean life spans in the county were the same for whites and nonwhites.

Is this a right-tailed, left-tailed, or two-tailed test?

Use the following information to answer the next five exercises. A doctor wants to know if a blood pressure medication is effective. Six subjects have their blood pressures recorded. After twelve weeks on the medication, the same six subjects have their blood pressure recorded again. For this test, only systolic pressure is of concern. Test at the 1%significance level.

What is the conclusion?

A study is done to determine if Company A retains its workers longer than Company B. Company A samples 15workers, and their average time with the company is five years with a standard deviation of 1.2.Company B samples 20workers, and their average time with the company is 4.5yearswith a standard deviation of 0.8.The populations are normally distributed.

a. Are the population standard deviations known?

b. Conduct an appropriate hypothesis test. At the 5%significance level, what is your conclusion?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.