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Chapter 9: Q.72 (page 542)

It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per night, on average. A survey of 22 LTCC Intermediate Algebra students generated a mean of 7.24 hours with a standard deviation of 1.93 hours. At a level of significance of 5%, do LTCC Intermediate Algebra students get less than

seven hours of sleep per night, on average? The distribution to be used for this test is X炉~________________

a. N(7.24, 1.9322)

b.N(7.24,1.93)

c. t22

d. t21

Short Answer

Expert verified

The correct option is a. N(7.24,1.9322).

Step by step solution

01

Introduction

Perform tests of a population mean using a normal distribution or a Student's t-distribution.

02

Explanation

Here we have the population mean and population standard deviation and so we may do a normal distribution test. When testing a single population proportion use a normal test for a single population proportion if the data comes from a simple, random sample, fill the requirements for a binomial distribution, and the mean number of successes and the mean number of failures satisfy the conditions: np>5 and nq>5 where n is the sample size, p is the probability of success, and q is the probability of a failure.

03

Conclusion

The correct option is a.

Since we have the values of mean and standard deviation we go for a.

When you perform a hypothesis test of a single population mean 渭 using a normal distribution (often called a z-test), you take a simple random sample from the population.

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Most popular questions from this chapter

"Japanese Girls鈥� Names"

by Kumi Furuichi

It used to be very typical for Japanese girls鈥� names to end with 鈥渒o.鈥� (The trend might have started around my

grandmothers鈥� generation and its peak might have been around my mother鈥檚 generation.) 鈥淜o鈥� means 鈥渃hild鈥� in Chinese characters. Parents would name their daughters with 鈥渒o鈥� attaching to other Chinese characters which have meanings that they want their daughters to become, such as Sachiko鈥攈appy child, Yoshiko鈥攁 good child, Yasuko鈥攁 healthy child, and so on.

However, I noticed recently that only two out of nine of my Japanese girlfriends at this school have names which end with 鈥渒o.鈥� More and more, parents seem to have become creative, modernized, and, sometimes, westernized in naming their children.

I have a feeling that, while 70 percent or more of my mother鈥檚 generation would have names with 鈥渒o鈥� at the end,

the proportion has dropped among my peers. I wrote down all my Japanese friends鈥�, ex-classmates鈥�, co-workers, and

acquaintances鈥� names that I could remember. Following are the names. (Some are repeats.) Test to see if the proportion has

dropped for this generation.

Ai, Akemi, Akiko, Ayumi, Chiaki, Chie, Eiko, Eri, Eriko, Fumiko, Harumi, Hitomi, Hiroko, Hiroko, Hidemi, Hisako,

Hinako, Izumi, Izumi, Junko, Junko, Kana, Kanako, Kanayo, Kayo, Kayoko, Kazumi, Keiko, Keiko, Kei, Kumi, Kumiko,

Kyoko, Kyoko, Madoka, Maho, Mai, Maiko, Maki, Miki, Miki, Mikiko, Mina, Minako, Miyako, Momoko, Nana, Naoko,

Naoko, Naoko, Noriko, Rieko, Rika, Rika, Rumiko, Rei, Reiko, Reiko, Sachiko, Sachiko, Sachiyo, Saki, Sayaka, Sayoko,

Sayuri, Seiko, Shiho, Shizuka, Sumiko, Takako, Takako, Tomoe, Tomoe, Tomoko, Touko, Yasuko, Yasuko, Yasuyo, Yoko, Yoko, Yoko, Yoshiko, Yoshiko, Yoshiko, Yuka, Yuki, Yuki, Yukiko, Yuko, Yuko.

It is believed that a stock price for a particular company will grow at a rate of 5per week with a standard deviation of1. An investor believes the stock won鈥檛 grow as quickly. The changes in stock price are recorded for ten weeks and are as follows: 4,3,2, 3, 1,7, 2,1,1, 2. Perform a hypothesis test using a 5%level of significance. State the null and alternative hypotheses, find the p-value, state your conclusion, and identify the Type Iand Type IIerrors.

A recent survey in the N.Y. Times Almanac indicated that 48.8% of families own stock. A broker wanted to determine if this survey could be valid. He surveyed a random sample of 250 families and found that 142 owned some type of stock. At the 0.05 significance level, can the survey be considered to be accurate?

A report by the Gallup Poll found that a woman visits her doctor, on average, at most5.8times each year. A random sample of 20women results in these yearly visit totals

3;2;1;3;7;2;9;4;6;6;8;0;5;6;4;2;1;3;4;1

At the 伪 = 0.05 level can it be concluded that the sample mean is higher than 5.8visits per year?

Your friend claims that his mean golf score is 63. You want to show that it is higher than that. What type of test would

you use?
See all solutions

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