/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.102 Registered nurses earned an aver... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 9: Q.102 (page 554)

Registered nurses earned an average annual salary of \(69,110. For that same year, a survey was conducted of 41 California registered nurses to determine if the annual salary is higher than \)69,110 for California nurses. The sample average was \(71,121 with a sample standard deviation of \)7,489. Conduct a hypothesis test.

Short Answer

Expert verified

CI: ($68,757, $73,485)

Step by step solution

01

Find H0 and Ha: We want to test if California registered nurses earned greater than $69,110 of an average annual salary, on average.

H0:渭=69,110;Ha:渭>69,110

02

Determine the distribution needed: In words, CLEARLY state what your random variable x represents.Let x = the mean salary in dollars for California registered nurses.

Normal:N69110,748941localid="1649503125769" N69110,748941

Test Statistic:t=1.719localid="1649503135603" t=1.719

03

Calculate the p-value using the normal distribution for mean RV

p-value=0.0466

In one to two complete sentences, explain what the p-value means for this problem.

If the null hypothesis is true (the mean salary is 69110), then there is a 0.0466 probability that the sample (estimated) mean salary is 71121 or more.

04

Compare α and the p-value:Indicate the correct decision (“reject” or “do not reject” the null hypothesis), the reason for it, and write an appropriate conclusion, using complete sentences.

alphadecisionreason for decision
0.05Reject the null hypothesis.
p-value<0.05

Conclusion: At the 5% significance level, there is sufficient evidence to conclude that the mean salary of California registered nurses exceeds $69,110.

05

Confidence Interval

CI: ($68,757, $73,485)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A recent survey in the N.Y. Times Almanac indicated that 48.8% of families own stock. A broker wanted to determine if this survey could be valid. He surveyed a random sample of 250 families and found that 142 owned some type of stock. At the 0.05 significance level, can the survey be considered to be accurate?

According to the Center for Disease Control website, in 2011 at least18%of high school students have smoked a cigarette. An Introduction to Statistics class in Davies County,KY conducted a hypothesis test at the local high school (a medium sized鈥揳pproximately 1,200 students鈥搒mall city demographic) to determine if the local high school鈥檚 percentage was lower. One hundred fifty students were chosen at random and surveyed. Of the150 students surveyed, 82have smoked. Use a significance level of 0.05 and using appropriate statistical evidence, conduct a hypothesis test and state the conclusions.

"The Problem with Angels," by Cyndy Dowling although this problem is wholly mine, the catalyst came from the magazine, Time. On the magazine cover I did find the realm of angels tickling my mind. Inside, 69%I found to be in angels, Americans do believe.

Then, it was time to rise to the task, ninety-five high school and college students I did ask. Viewing all as one group, random sampling to get the scoop. So, I asked each to be true, "Do you believe in angels?" Tell me, do! Hypothesizing at the start, totally believing in my heart that the proportion who said yes would be equal on this test. Lo and behold, seventy-three did arrive, out of the sample of ninety-five. Now your job has just begun, Solve this problem and have some fun.

Over the past few decades, public health officials have examined the link between weight concerns and teen girls' smoking. Researchers surveyed a group of 273 randomly selected teen girls living in Massachusetts (between 12 and 15 years old). After four years the girls were surveyed again. Sixty-three said they smoked to stay thin. Is there good evidence that more than thirty percent of teen girls smoke to stay thin? The alternative hypothesis is:

a.p<0.30b.p鈮�0.30c.p鈮�0.30d.p>0.30

Previously, an organization reported that teenagers spent 4.5 hours per week, on average, on the phone. The organization thinks that, currently, the mean is higher. Fifteen randomly chosen teenagers were asked how many hours per week they spend on the phone. The sample mean was 4.75 hours with a sample standard deviation of 2.0. Conduct a hypothesis test. At a significance level of a = 0.05, what is the correct conclusion?

a. There is enough evidence to conclude that the mean number of hours is more than 4.75

b. There is enough evidence to conclude that the mean number of hours is more than 4.5

c. There is not enough evidence to conclude that the mean number of hours is more than 4.5

d. There is not enough evidence to conclude that the mean number of hours is more than 4.75
See all solutions

Recommended explanations on Math Textbooks

Discrete Mathematics

Read Explanation

Calculus

Read Explanation

Applied Mathematics

Read Explanation

Probability and Statistics

Read Explanation

Decision Maths

Read Explanation

Geometry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.