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"Dalmatian Darnation," by Kathy Sparling

A greedy dog breeder named Spreckles

Bred puppies with numerous freckles

The Dalmatians he sought

Possessed spot upon spot

The more spots, he thought, the more shekels.

His competitors did not agree

That freckles would increase the fee.

They said, 鈥淪pots are quite nice

But they don't affect price;

One should breed for improved pedigree.鈥

The breeders decided to prove

This strategy was a wrong move.

Breeding only for spots

Would wreak havoc, they thought.

His theory they want to disprove.

They proposed a contest to Spreckles

Comparing dog prices to freckles.

In records they looked up

One hundred one pups:

Dalmatians that fetched the most shekels.

They asked Mr. Spreckles to name

An average spot count he'd claim

To bring in big bucks.

Said Spreckles, 鈥淲ell, shucks,

It's for one hundred one that I aim.鈥

Said an amateur statistician

Who wanted to help with this mission.

鈥淭wenty-one for the sample

Standard deviation's ample:

They examined one hundred and one

Dalmatians that fetched a good sum.

They counted each spot,

Mark, freckle and dot

And tallied up every one.

Instead of one hundred one spots

They averaged ninety six dots

Can they muzzle Spreckles鈥

Obsession with freckles

Based on all the dog data they've got?

Short Answer

Expert verified

The alternate hypothesis states that the mean dots on Dalmatian are less than101remains true.

Step by step solution

01

Given information

The number of pups taken for sample standard deviation is21. Out of101spots on Dalmatian, they got an average of96dots.

02

Explanation

Hypothesis:

The null hypothesis claims that the Dalmatian mean dots are at least 101, while the alternate is the Dalmatian mean dots are less than 101

H0:101Ha:<101

The student's t-distribution is,

tn-1=t101-1=t100

Thez value is calculated as

localid="1649765554909" z=X-/nwheresisthestandarddeviation,andnisthesamplesize.X=96n=101z=96-10021/101=-52.089=-2.393

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Most popular questions from this chapter

Previously, an organization reported that teenagers spent 4.5hours per week, on average, on the phone. The organization thinks that, currently, the mean is higher. Fifteen randomly chosen teenagers were asked how many hours per week they spend on the phone. The sample mean was 4.75hours with a sample standard deviation of 2.0. Conduct a hypothesis test.

At a significance level of a=0.05, what is the correct conclusion?

a. There is enough evidence to conclude that the mean number of hours is more than4.75

b. There is enough evidence to conclude that the mean number of hours is more than 4.5

c. There is not enough evidence to conclude that the mean number of hours is more than 4.5

d. There is not enough evidence to conclude that the mean number of hours is more than 4.75

Instructions: For the following ten exercises,

Hypothesis testing: For the following ten exercises, answer each question.

a. State the null and alternate hypothesis.

b. State the p-value.

c. State alpha.

d. What is your decision?

e. Write a conclusion.

f. Answer any other questions asked in the problem

A sleeping bag is tested to withstand temperatures of-15F. You think the bag cannot stand temperatures that low. State the Type I and Type II errors in complete sentences.

Over the past few decades, public health officials have examined the link between weight concerns and teen girls' smoking. Researchers surveyed a group of 273 randomly selected teen girls living in Massachusetts (between 12 and 15 years old). After four years the girls were surveyed again. Sixty-three said they smoked to stay thin. Is there good evidence that more than thirty percent of teen girls smoke to stay thin? The alternative hypothesis is:

a.p<0.30b.p0.30c.p0.30d.p>0.30

A recent survey in theN.Y. Times Almanac indicated that 48.8%of families own stock. A broker wanted to determine if this survey could be valid. He surveyed a random sample of 250 families and found that142owned some type of stock. At the 0.05 significance level, can the survey be considered to be accurate?

The US Department of Energy reported that 51.7% of homes were heated by natural gas. A random sample of 221homes in Kentucky found that 115 were heated by natural gas. Does the evidence support the claim for Kentucky at the =0.05 level in Kentucky? Are the results applicable across the country? Why?

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