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Suppose a group is interested in determining whether teenagers obtain their driver's licenses at approximately the same average age across the country. Suppose that the following data are randomly collected from five teenagers in each region of the country. The numbers represent the age at which teenagers obtained their driver's licenses.

NortheastSouthWestCentralEast16.316.916.416.217.116.116.516.516.617.216.416.416.616.516.616.516.216.116.416.8x¯=s2=

α=0.05

a) Decision: _____

b) Conclusion: _____

Short Answer

Expert verified

a. Thus, p-value is 0.017which indicates at 5%level of significance null hypothesis of no difference between the means of five regions are same, will be rejected.

b. The rejection of the null hypothesis indicates that the driver's licenses are not the same average age across the country.

Step by step solution

01

Given Information

Consider the data of five teenagers in each region of the country to state decision and conclusions:

NortheastSouthWestCentralEast16.316.916.416.217.116.116.516.516.617.216.416.416.616.516.616.516.216.116.416.8

02

Explanation

Use Ti-83calculator to state decisions and conclusions. For this, click on START →press 1→EDIT, then put the above given weights of different groups data into the list L1,L2, and L3. The screenshot is given as below:

Now Again press START →arrow over the TESTS →arrow down to ANOVA →Press var then select 1, press var then select 2, press var then select 3, press var then select 4and press var then select 5to fill the values of L1,L2,L3,L4and L5. The screen shot is given as below:

03

Final Answer

Press ENTER. The screenshot of the obtained output of calculated p-value is given as below:

Thus thep-value is0.017.

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