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The middle value in a set of statistics or data is known as the median.

In graph (a), total frequency of value $1$and $2$and total frequency of value $4$and $5$are approximately equal. Hence the median is $3$.

In graph (b), total frequency of value above and below $3$and frequency around value $3$are approximately equal. Hence the median is $3$.

In the box and whisker plot graph (c), second quartile or median is $3$.

Hence, all three graphs median are same.

A diagram depicting the relationship between two or more variables, each measured along one of a pair of axes at right angles.

It's difficult to figure out the mean values for all three situations because the actual values of the frequency distributions for two histograms aren't given, and the box and whisker plot doesn't convey the frequency distribution of given data. We can't acquire a value for the mean for the graph even if we use estimated frequency values and calculate mean values. As a result, we can't tell if any of the three graphs' means are different.

The standard deviation is a measure that indicates how much variation (such as spread, dispersion, and spread) is there from the mean.

Graph (a) has more higher frequencies around $3$but less deviation from the center of the data values. But graph (b) has higher deviations from the center of data values compared to (a) with the less frequency from the center of data values. But (b) has higher values for standard deviation compared to (a) according to the summation of squared value of deviation. Hence, (b) standard deviation is larger than (a).

Each of four equal groups into which a population might be classified based on a variable's distribution of values:

In graph (a), the third quartile is around value$4$and in graph (b) the third quartile is around value $5$. But in graph (c), the third quartile is around value $6$. Hence, the third quartile for the three graphs are different. Hence, the statement is false.