/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 43 One hundred eight Americans were... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

One hundred eight Americans were surveyed to determine the number of hours they spend watching television each month. It was revealed that they watched an average of 151hours each month with a standard deviation of 32hours. Assume that the underlying population distribution is normal.

Identify the following:

a. x=_______

b. sx=_______

c. n =_______

d. n – 1 =_______

Short Answer

Expert verified

(a) x=151hours

(b) sx=32hours

(c) n=151

(d)n-1=107

Step by step solution

01

Part (a) Step 1: Given information

No. of patients surveyed =108

Sample Mean =151hours

Sample Standard Deviation =32hours

02

Part (b) Step 2: Explanation

From the given values

The sample mean xis computed by adding all of the sample's observations and then dividing it by the number of observations in the sample.

It is stated explicitly in the question that the sample mean is151 hours.

03

Part (b) Step 1: Given information

No. of patients surveyed =108

Sample Mean =151hours

Sample Standard Deviation =32hours

04

Part (b) Step 2: Explanation

sxDefines the sample standard deviation, which shows us how far your data has drifted or strayed from the mean.

The sample standard deviation describes how far your sample deviates from the mean. It is stated explicitly in this question that the sample standard deviation is32 hours.

05

Part (c) Step 1: Given information

No. of patients surveyed =108

Sample Mean =151hours

Sample Standard Deviation =32hours

06

Part (c) Step 2: Explanation

The sample size is denoted by n, which means the total number of observations in the sample is denoted by n.

It is stated explicitly in this question that the sample size is151.

07

Part (d) Step 1: Given information

No. of patients surveyed =108

Sample Mean =151hours

Sample Standard Deviation =32hours

08

Part (d) Step 2: Explanation

The degree of freedom is defined by n.

In this question, it is stated that 108Americans were polled, which means that nequals 108and

n-1=108-1

=107.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The data in the Table are the result of a random survey of 39national flags (with replacement between picks) from various countries. We are interested in finding a confidence interval for the true mean number of colors on a national flag. Let X=the number of colors on a national flag.

xFreq.11273184756

Calculate the following:

(a) x¯=_____

(b) sx=_____

(c) n=_____

The Ice Chalet offers dozens of different beginning iceskating classes. All of the class names are put into a bucket. The 5 P.M., Monday night, ages 8 to 12, beginning ice-skating class was picked. In that class were 64 girls and 16 boys. Suppose that we are interested in the true proportion of girls, ages 8 to 12, in all beginning ice-skating classes at the Ice Chalet. Assume that the children in the selected class are a random sample of the population.

Calculate the following:

a. x = _______

b. n = _______

c. p′ = _______

When designing a study to determine this population proportion, what is the minimum number you would need to survey to be 90% confident that the population proportion is estimated to within 0.05 ?

Suppose we know that a confidence interval is (42.12,47.88). Find the error bound and the sample mean.

Of 1,050 randomly selected adults, 360 identified themselves as manual laborers, 280 identified themselves as non-manual wage earners, 250 identified themselves as midlevel managers, and 160 identified themselves as executives. In the survey, 82% of manual laborers preferred trucks, 62% of non-manual wage earners preferred trucks, 54% of mid-level managers preferred trucks, and 26% of executives preferred trucks.

We are interested in finding the 95% confidence interval for the percent of executives who prefer trucks. Define random variables X and P′ in words.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.