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According to the Centers of Disease Control and Prevention, \(52 \%\) of U.S. households had no landline and only had cell phone service. Suppose a random sample of 40 U.S. households is taken. a. Find the probability that exactly 20 the households sampled only have cell phone service. b. Find the probability that fewer than 20 households only have cell phone service. c. Find the probability that at most 20 households only have cell phone service. d. Find the probability that between 20 and 23 households only have cell phone service.

Short Answer

Expert verified
The detailed calculations will give the exact values, but it can be observed that the probability will be highest for 'exactly 20 households', as this is around the expected number for a sample of 40, given a 'success' rate of 52%.

Step by step solution

01

Define The Variables for Binomial Distribution

Firstly, let's define our variables for the binomial distribution; the probability of success on a single trial \(p = 0.52\), the number of trials \(n = 40\), and the number of successes \(x\) will change for each problem. We will also use the formula for binomial distribution, \(P(x) = C(n, x) \cdot p^x \cdot (1-p)^{n-x}\), where \(C(n, x) = n! / [x!(n-x)!]\) is the combination formula.
02

Calculate Probability for Case a

For question a, we need to calculate the probability that exactly 20 of the households in the sample only have cell phone service. Here, \(x = 20\). Insert these values into the formula and calculate the probability.
03

Calculate Probability for Case b

For question b, we need to calculate the probability that fewer than 20 households only have cell phone service. In this case, we will need to calculate the probability for each number from 0 to 19, and add these probabilities up.
04

Calculate Probability for Case c

For question c, we need to calculate the probability that at most 20 households only have cell phone service, which means from 0 to 20. This is similar to step 3, but now we calculate the probabilities up to 20.
05

Calculate Probability for Case d

For question d, we calculate the probability between 20 and 23 households. Here, calculate the probabilities for 20, 21, 22 and 23 and then add these up.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability calculation
Calculating probability in a binomial distribution scenario involves understanding how likely it is for a given number of outcomes ("successes") to occur in a fixed number of trials. In our exercise, we are interested in various probabilities related to households having only cell phone service. To compute these probabilities, we utilize a mathematical formula from the binomial distribution model:
  • First, determine the probability of success in a single trial, noted as \( p \). In this case, \( p = 0.52 \) or 52%.
  • The number of trials is \( n = 40 \) households.
  • For each specific question, we focus on a particular number of successes \( x \), such as exactly 20 or fewer than 20, etc.
  • Use the probability formula: \( P(x) = C(n, x) \cdot p^x \cdot (1-p)^{n-x} \).
Substitute \( n \), \( p \), and \( x \) into the formula to find the specific probability. This formula helps involve each potential combination of successes among the trials, by using the probability of success powered by the number of desired successes and multiplied by the probability of failure accordingly.
Statistical distribution
A statistical distribution is a method to describe all the potential outcomes of a random variable. In this exercise, we focus on the binomial distribution, which is a common type of statistical distribution ideal for scenarios involving multiple trials with two possible outcomes - success or failure.The binomial distribution is characterized by two main parameters: the number of trials \( n \) and the probability of success in a single trial \( p \). It models the number of successes \( x \) in \( n \) trials.
  • In our problem, the trials are the number of different households sampled. Each trial represents one household.
  • The outcomes concern whether each household only has cell phone service (success) or not (failure).
  • The binomial distribution accurately helps us predict the likelihood of observing a certain number of successes within our sample.
This kind of distribution is widely used when dealing with probabilities across different scenarios ranging from scientific studies to business modeling, wherever decisions rely on understanding frequencies and magnitudes of discrete events.
Combination formula
The combination formula is a key component in calculating probabilities for binomial distributions. It helps determine how many different ways a specific outcome can occur.The formula for combinations, represented as \( C(n, x) \), calculates the total number of ways \( x \) successes can be achieved in \( n \) trials. The formula is given by:\[C(n, x) = \frac{n!}{x!(n-x)!}\]
  • Here, \( n! \) ("n factorial") means multiplying all whole numbers from \( n \) down to 1.
  • For the specific number of successes \( x \), \( x! \) works similarly, and \((n-x)!\) accounts for the rest of the trials.
  • This formula is crucial as it ensures all combinations of outcomes are considered, making the probability calculation complete.
In practical terms, the combination formula lets you see how many different ways you can pick \( x \) successful trials from \( n \), which is foundational for applying these results in the broader probability equation for your binomial distribution exercise.

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Most popular questions from this chapter

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