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For each situation, identify the sample size \(n\), the probability of a success \(p\), and the number of success \(x\). When asked for the probability, state the answer in the form \(b(n, p, x)\). There is no need to give the numerical value of the probability. Assume the conditions for a binomial experiment are satisfied. A 2017 Gallup poll found that \(53 \%\) of college students were very confident that their major will lead to a good job. a. If 20 college students are chosen at random, what's the probability that 12 of them were very confident their major would lead to a good job? b. If 20 college students are chosen at random, what's the probability that 10 of them are not confident that their major would lead to a good job? a. If 20 college students are chosen at random, what's the probability that 12 of them were very confident their major would lead to a good job? b. If 20 college students are chosen at random, what's the probability that 10 of them are not confident that their major would lead to a good job?

Short Answer

Expert verified
a. The probability that 12 of the 20 students chosen at random are very confident that their major will lead to a good job is \(b(20, 0.53, 12)\). b. The probability that 10 of the chosen 20 students are not confident their major will lead to a good job is \(b(20, 0.47, 10)\).

Step by step solution

01

Identify Parameters for Question a

From the problem statement, the probability of success in a single trial (i.e., a college student is confident their major will lead to a good job) is \(p = 0.53\). The number of trials or sample size is 20 students being chosen at random (\(n = 20\)). The number of successes we are interested in (i.e., students being confident their major will lead to a good job) is 12 (\(x = 12\)).
02

Express the Probability for Question a

The binomial probability \(b(n, p, x)\) is the probability of \(x\) successes in \(n\) trials for event with probability \(p\). So for this case, the answer is \(b(20, 0.53, 12)\).
03

Identify Parameters for Question b

The probability of success in a single trial for this part is a student is not confident their major will lead to a good job. Since there's a 53% chance a student is confident, thus \(p = 1 - 0.53 = 0.47\) for a student to be not confident. Again, the number of trials is 20 students being chosen at random (\(n = 20\)), and the number of successes we are interested in (i.e., students being not confident their major will lead to a good job) is 10 (\(x = 10\)).
04

Express the Probability for Question b

Following the same logic as before, our binomial probability for the second question becomes \(b(20, 0.47, 10)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size
Understanding sample size is critical when analyzing binomial probability. The sample size, denoted as n, refers to the total number of trials or subjects being considered in an experiment or a survey.

For instance, in the given exercise, when addressing the confidence of college students in their major leading to a good job, the sample size is defined as 20 students. This means that 20 different occurrences or trials are examined, each being an opportunity for the event (student confident in their major leading to a good job) to succeed or fail.

The importance of sample size cannot be overstated as it not only determines the scale of the study but also impacts the reliability of the results. A larger sample size typically leads to more precise estimations of the probability of success, as it tends to represent the population more accurately. However, it is crucial to ensure that the sample is random and representative to avoid bias.
Probability of Success
The probability of success, often symbolized as p, is a key element when discussing binomial distributions. It represents the chance of a single trial resulting in a success.

In our example about college students' confidence in their major, the probability of success for one student being confident is 53%, or 0.53 when expressed as a decimal. Conversely, the probability of a student not being confident can be deduced by taking one minus the probability of confidence, leading to a probability of 47%, or 0.47.

Understanding this probability is vital, as it remains consistent across each trial and is the foundation upon which the binomial distribution is based. When multiple probabilities are involved, such as the probability of confidence and the probability of not being confident, it is essential to define each clearly to avoid confusion while calculating binomial probabilities.
Binomial Distribution
The binomial distribution is a discrete probability distribution that describes the number of successes in a fixed number of independent trials, with only two possible outcomes: success or failure. This distribution is governed by two parameters: the number of trials n, and the probability of success in each trial p.

Returning to our problem, considering 20 college students and looking to determine how many are confident or not confident about their major leading to a good job, we illustrate the binomial distribution with two key scenarios corresponding to both levels of confidence. The expressions b(20, 0.53, 12) and b(20, 0.47, 10) showcase the potential outcome scenarios.

To calculate the exact probabilities, one would use the binomial probability formula, which incorporates factorial calculations and powers of probabilities. The expression b(n, p, x) serves as a shorthand reference to represent the probability without delving into intricate calculations, making it easier to communicate results concisely.

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Most popular questions from this chapter

The Empirical Rule applies rough approximations to probabilities for any unimodal, symmetric distribution. But for the Normal distribution we can be more precise. Use the figure and the fact that the Normal curve is symmetric to answer the questions. Do not use a Normal table or technology. According to the Empirical Rule, a. Roughly what percentage of \(z\) -scores are between \(-2\) and 2 ? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) b. Roughly what percentage of \(z\) -scores are between \(-3\) and 3 ? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) c. Roughly what percentage of \(z\) -scores are between \(-1\) and 1 . i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) d. Roughly what percentage of \(z\) -scores are greater than 0 ? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) e. Roughly what percentage of \(z\) -scores are between 1 and 2 ? i. almost all iii. \(50 \%\) ii. \(13.5 \%\) iv. \(2 \%\)

For each situation, identify the sample size \(n\), the probability of a success \(p\), and the number of success \(x\). When asked for the probability, state the answer in the form \(b(n, p, x)\). There is no need to give the numerical value of the probability. Assume the conditions for a binomial experiment are satisfied. Since the Surgeon General's Report on Smoking and Health in 1964 linked smoking to adverse health effects, the rate of smoking the United States have been falling. According to the Centers for Disease Control and Prevention in 2016, \(15 \%\) of U.S. adults smoked cigarettes (down from \(42 \%\) in the \(1960 \mathrm{~s}\) ). a. If 30 Americans are randomly selected, what is the probability that exactly 10 are smokers? b. If 30 Americans are randomly selected, what is the probability that exactly 25 are not smokers?

Toss a fair six-sided die. The probability density function (pdf) in table form is given. Make a graph of the pdf for the die.

Use technology or a Normal table to find each of the following. Include an appropriately labeled sketch of the Normal curve for each part with the appropriate area shaded. a. Find the probability that a \(z\) -score will be \(2.12\) or greater. b. Find the probability that a \(z\) -score will be less than \(-0.74\). c. Find the probability that a \(z\) -score will between \(1.25\) and \(2.37\).

Length of Pregnancy Assume that the lengths of pregnancy for humans is approximately Normally distributed, with a mean of 267 days and a standard deviation of 10 days. Use the Empirical Rule to answer the following questions. Do not use the technology or the Normal table. Begin by labeling the horizontal axis of the graph with lengths, using the given mean and standard deviation. Three of the entries are done for you. a. Roughly what percentage of pregnancies last more than 267 days? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) b. Roughly what percentage of pregnancies last between 267 and 277 days? i. \(34 \%\) iii. \(2.5 \%\) ii. \(17 \%\) iv. \(50 \%\) c. Roughly what percentage of pregnancies last less than 237 days? i. almost all iii. \(34 \%\) ii. \(50 \%\) iv. about \(0 \%\) d. Roughly what percentage of pregnancies last between 247 and 287 days? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) e. Roughly what percentage of pregnancies last longer than 287 days? i. \(34 \%\) iii. \(2.5 \%\) ii. \(17 \%\) iv. \(50 \%\) f. Roughly what percentage of pregnancies last longer than 297 days? i. almost all iii. \(34 \%\) ii. \(50 \%\) iv. about \(0 \%\)

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