/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 Consider a multiple-choice test ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider a multiple-choice test with a total of four possible options for each question. a. What is the probability of guessing correctly on one question? (Assume that there are three incorrect options and one correct option.) b. What is the probability that a guess on one question will be incorrect?

Short Answer

Expert verified
The probability of guessing correctly on one question is 0.25 or 25%, while the probability of guessing incorrectly on one question is 0.75 or 75%.

Step by step solution

01

Determine the total number of options

For each multiple-choice question, there are a total of four options. This is the total number of outcomes when a single option is chosen at random.
02

Determine the number of correct outcomes for guessing correctly

For each question, there is only one correct option. So, there is only one outcome where the guess is correct.
03

Calculate the probability of guessing correctly

The probability of an event is calculated by dividing the number of desired outcomes (correct guesses in this case) by the total number of outcomes. So, the probability of guessing correctly is 1 out of 4, or \(\frac{1}{4}\), or 0.25 in decimal form.
04

Determine the number of incorrect outcomes

Since there is only one correct option, there must be 3 incorrect options for each question.
05

Calculate the probability of guessing incorrectly

Again, the probability of an event is calculated by dividing the number of desired outcomes (incorrect guesses in this case) by the total number of outcomes. So, the probability of guessing incorrectly is 3 out of 4, or \(\frac{3}{4}\), or 0.75 in decimal form.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Multiple-Choice Questions
Multiple-choice questions are a common type of question used in tests and exams. Each question offers several possible answers – in this exercise, specifically four options. One of these options is the correct answer, while the remaining options are incorrect. This characteristic makes multiple-choice questions a straightforward example of a probability scenario. Since there is only one correct choice among multiple total choices, these questions help illustrate the concept of probability through the dilemma of picking one option out of several possible ones. In many educational settings, this format is favored due to its clarity and the ease with which it can be graded. As students, knowing how to strategically approach these questions can help increase the probability of getting them right, even when unsure of the answer.
Correct and Incorrect Guesses
When facing a multiple-choice question, it's crucial to understand the outcomes of guessing. Each guess will either be correct or incorrect. For example:
  • Correct Guess: Selecting the one correct option from the four provided.
  • Incorrect Guess: Selecting any of the remaining three options.
When discussing outcomes, keep in mind the differences in likelihood. With only one correct answer, the chance of picking wrong is higher when guessing completely at random. Educators use this format to measure knowledge, but understanding the likelihood of each kind of guess can help students approach these questions more strategically when they must guess.
Probability Calculation
Calculating probabilities in multiple-choice questions revolves around the formula for finding the likelihood of an event. This involves dividing the number of ways an event can happen by the total number of possibilities.To find:
  • **Probability of a Correct Guess:** There is 1 desired outcome (the correct guess) out of 4 possible options. Thus, \( ext{Probability} = \frac{1}{4} = 0.25 \)
  • **Probability of an Incorrect Guess:** There are 3 undesired outcomes out of 4 possible options. Therefore, \( ext{Probability} = \frac{3}{4} = 0.75 \)
These calculations allow students to understand and predict the expected results of guessing. They illustrate foundational principles of probability which can be applied in more complex scenarios.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

There are four suits: clubs ( \(\boldsymbol{k}\) ). diamonds ( \(\bullet\) ), hearts ( \(\mathbf{v}\) ), and spades ( \(\boldsymbol{A}\) ), and the following cards appear in each suit: ace, \(2,3,4,5,6,7,8,9,10\), jack, queen, king. The jack, queen, and king are called face cards because they have a drawing of a face on them. Diamonds and hearts are red, and clubs and spades are black. If you draw 1 card randomly from a standard 52 -card playing deck, what is the probability that it will be the following: a. A heart b. A red card c. An ace d. A face card (jack, queen, or king) es A three

Use your general knowledge to label the following pairs of variables as independent or associated. Explain. a. For a sample of adults. gender and shoe size b. For a sample of football teams, win/loss record for the coin toss at the beginning of the game and number of cheerleaders for the team

A jury is supposed to represent the population. We wish to perform a simulation to determine an empirical probability that a jury of 12 people has 5 or fewer women. Assume that about \(50 \%\) of the population is female, so the probability that a person who is chosen for the jury is a woman is \(50 \%\). Using a random number table, we decide that each digit will represent a juror. The digits 0 through 5 , we decide, will represent a female chosen, and 6 through 9 will represent a male. Why this is a bad choice for this simulation?

In California, about \(92 \%\) of teens who take the written driver's exam fail the first time they take it (www.teendrivingcourse.com). Suppose that Sam and Maria are randomly selected teenagers taking the test for the first time. a. What is the probability that they both pass the test? b. What is the probubility that Sam OR Maria passes the test?

Abusy street has three traffic lights in a row. These lights are not synchronized, so they run independently of each other. At any given moment, the probability that a light is green is \(60 \%\). Assuming that there is no traffic, follow the steps below to design a simulation to estimate the probability that you will get three green lights. a. Identify the action with a random outcome, and give the probability that it is a success. b. Explain how you will simulate this action using the random number table in Appendix A. Which digits will represent green, and which nongreen? If you want to get the same results we did, use all the possible one-digit numbers \((0,1,2,3,4,5,6,7,8\), and 9\()\), and let the first few represent the green lights. How many and what numbers would represent green lights, and what numbers would represent nongreen lights? c. Describe the event of interest. d. Explain how you will simulate a single trial. e. Carry out 20 repetitions of your trial, beginning with the first digit on line 11 of the random number table. For each trial, list the random digits, the outcomes they represent, and whether or not the event of interest happened. f. What is the empirical probability that you get three green lights?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.