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Construct two sets of numbers with at least five numbers in each set with the following characteristics: The means are the same, but the standard deviation of one of the sets is larger than that of the other. Report the mean and both standard deviations.

Short Answer

Expert verified
Datasets Set A: {8, 9, 10, 11, 12} and Set B: {5,7,10,13,15} both have a mean of 10. However, their standard deviations differ. The standard deviation for Set A is approximately 1.58 and the standard deviation for Set B is approximately 3.54.

Step by step solution

01

Defining the datasets

First, define two datasets with the same mean. As an example, let's say both set A and set B each have a mean of 10. The sets could look like this: \n Set A: {8, 9, 10, 11, 12} \n Set B: {5,7,10,13,15}
02

Calculating Standard Deviation for Set A

Calculate the standard deviation for set A: \nStep 1: Find the mean = 10:\nStep 2: Subtract the mean and square the result for each number then sum up: \n(8 - 10)²+ (9 - 10)²+ (10 - 10)² + (11 - 10)² + (12-10)²= 10 \nStep 3: Divide the result by the number of data points minus 1 (n - 1): \n10 / 4 = 2.5 \nStep 4: Take the square root of the result: \n √2.5 = 1.58.\nSo, the Standard Deviation for Set A is approximately 1.58.
03

Calculating Standard Deviation for Set B

Calculate the standard deviation for set B: \nStep 1: Find the mean=10 \nStep 2: Subtract the mean and square the result for each number then sum up: \n(5 - 10)² + (7 - 10)² + (10 - 10)² + (13 - 10)² + (15 - 10)²= 50 \nStep 3: Divide the result by the number of data points minus 1 (n - 1): \n50 / 4 = 12.5 \nStep 4: Take the square root of the result: \n√12.5 = 3.54.\nSo, the Standard Deviation for Set B is approximately 3.54.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
Understanding the mean, often referred to as the average, is critical for comparing datasets. The mean is a measure of the central tendency of a set of numbers, indicating where the middle point of the data lies. To calculate it, you sum all the numbers in your dataset and then divide by the number of data points present. For example, if you have a set of numbers {3, 5, 7, 9, 11}, you would calculate the mean by adding them up (3+5+7+9+11=35) and then dividing by the number of entries (35/5), resulting in a mean of 7.

This calculation is the foundation in the construction of the sets in the exercise. Both Set A and Set B have an established mean of 10, which means regardless of how spaced out or close together the numbers are within each set, the average equals 10. This similarity in means is where dataset comparison begins, yet it does not reflect the dispersion or spread of the numbers, which is where variance and standard deviation come into play.
Variance
Variance is a statistical measure that tells us how much the numbers in a dataset differ from the mean and from each other. It is essentially the average of the squared differences from the mean. To calculate the variance, you follow these steps:
  • Calculate the mean of the dataset.
  • Subtract the mean from each number to find the deviation of each number from the mean.
  • Square each deviation to make it positive.
  • Add all the squared deviations together.
  • Divide by the number of data points minus one (N-1 for a sample variance).
In the exercise solution, the variance for Set A was found to be 2.5, while for Set B it was significantly higher at 12.5, indicating a greater spread of values in Set B.

It's important to note that we divide by N-1 rather than by N because we're working with a sample of the whole population, and this adjustment, known as Bessel's correction, aims to reduce the bias in the estimation of the population variance.
Dataset Comparison
Comparing datasets involves looking at several parameters, including mean, variance, and standard deviation. While the exercise specifically focuses on the mean and standard deviation, comparing these datasets can reveal much about their characteristics. With the same mean, we know the data centers around the same point, but it's the variance and standard deviation that show us how spread out the data is.

The larger the standard deviation, the more spread out the numbers in the set are, which can indicate greater variability in the data. In the contextualized exercise, Set B with a standard deviation of 3.54 compared to Set A's 1.58 implies that Set B's numbers are more spread out around the mean. This information is essential when comparing datasets as it provides insight into the reliability of the mean as a measure of central tendency and the consistency within the data points themselves.

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Most popular questions from this chapter

Construct two sets of numbers with at least five numbers in each set with the following characteristics: The means are different, but the standard deviations are the same. Report the standard deviation and both means.

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College students Diane Glover and Esmeralda Olguin asked 25 men and 25 women how many speeding tickets they had received in the last three years. Men: 14 men said they had 0 tickets, 9 said they had 1 ticket, 1 had 2 tickets, and 1 had 5 tickets. Women: 18 said they had 0 tickets, 6 said they had 1 ticket, and I said she had 2 tickets. Is there evidence that the men and women differed? Answer by making appropriate plots and comparing appropriate summary statistics. Be sure to comment on the shape of the distributions and to mention any unusual features you observe.

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