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Wechsler IQ tests have a mean of 100 and a standard deviation of \(15 .\) Which is more unusual: an IQ above 110 or an IQ below 80 ?

Short Answer

Expert verified
An IQ score of 80 is more unusual than an IQ score of 110.

Step by step solution

01

calculate the z score for 110

The formula for the Z-score is \(Z = \frac{X - \mu}{\sigma}\) where X is the score, \(\mu\) is the mean, and \(\sigma\) is the standard deviation. Substituting values for the first score: \(Z_{110} = \frac{110 - 100}{15} = 0.67\).
02

calculate the z score for 80

Using the same z-score formula and substituting the values for the second score: \(Z_{80} = \frac{80 - 100}{15} = -1.33\).
03

Compare the z scores

Compare the absolute values of both z-scores. The absolute value of \(|Z_{110}|\) is 0.67 and of \(|Z_{80}|\) is 1.33. As 1.33 > 0.67, the score of 80 is more unusual.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
The concept of normal distribution is essential in understanding many statistical analyses and applies to the Wechsler IQ test data. A normal distribution is a bell-shaped curve that represents the spread of a dataset in which most occurrences take place near the mean. This means that values (in this case IQ scores) are symmetrically distributed on either side of the mean. The mean, median, and mode of a perfectly normal distribution are all the same, contributing to its symmetry. This specific distribution allows for predictions about data. For example, we can expect around 68% of the total data points to fall within one standard deviation from the mean. In the context of the Wechsler IQ test, the mean score is 100. This means most people's IQ scores cluster around this point, forming a normal curve. Understanding this symmetric spread helps us determine how "unusual" a particular score might be.
Standard Deviation
The standard deviation is a critical concept in calculating the Z-score and understanding how spread out scores are in a dataset. In a normal distribution, the standard deviation is a measure of the amount of variation or dispersion of a set of values. In simpler terms, it tells us how much scores typically deviate from the average (mean) score.

For the Wechsler IQ test, the standard deviation is 15. This standard deviation means that most IQ scores tend to fall within 15 points of the mean, which is 100. When computing the Z-score, the standard deviation helps us determine exactly how far away a specific score is from the mean. The greater the standard deviation, the more spread out the data points are from the average, indicating greater variability in the dataset.

With the calculation of an IQ score of 110 having a Z-score of 0.67, and 80 having a Z-score of -1.33, it is clear how standard deviation plays a role in determining the relative usualness of these scores.
Statistical Analysis
Statistical analysis, in the context of this exercise, involves using the Z-score to discover how unusual a score is within a normal distribution. The Z-score is a statistical measure that conveys how many standard deviations an element is from the mean. For instance, a Z-score of 0 indicates the score is precisely on the average, while a positive or negative Z-score indicates above or below the mean, respectively.

Through the calculation steps, we assigned Z-scores of 0.67 for an IQ of 110 and -1.33 for an IQ of 80. The absolute value of these Z-scores tells us how far each value is from the mean in terms of standard deviations. Therefore, an IQ of 80 (with a Z-score of -1.33) is more unusual compared to an IQ of 110 (with a Z-score of 0.67), since it is further away from the mean of 100 in terms of standard deviations.

This analysis shows that statistical methods such as Z-score calculations are beneficial in comparing data points on a common scale, irrespective of the unit of measurement of raw data, thereby unveiling insights about unusual outcomes in a dataset.

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Most popular questions from this chapter

When you are comparing two sets of data and one set is strongly skewed and the other is symmetric, which measures of the center and variation should you choose for the comparison?

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