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91Ó°ÊÓ

Explain when a sample is large enough to use the normal distribution to make a test of hypothesis about the population proportion.

Short Answer

Expert verified
A sample is large enough to use the normal distribution to make a test of hypothesis about the population proportion when the following two conditions are fulfilled: \(n*p > 5\) and \(n*(1-p) > 5\), where \(n\) is the sample size and \(p\) is the population proportion.

Step by step solution

01

Understanding the Central Limit Theorem

The Central Limit Theorem tells us that if we have a big enough sample size, the sampling distribution of the sample mean will be approximately normal, regardless of the population distribution. This principle allows us to perform a hypothesis test using the normal distribution.
02

Understanding the conditions for using the normal distribution

If we plan to use the normal distribution for a hypothesis test about a population proportion, we need to ensure that the sample is random and the following two conditions are met: 1) \(n*p > 5\), where \(n\) is the sample size and \(p\) is the population proportion and 2) \(n*(1-p) > 5\), where \(n\) is the sample size and \(p\) is the population proportion.
03

Deciding if sample size is large enough

In order to determine if a sample size is large enough for use with the normal distribution in a proportion hypothesis test, we will use the conditions listed in step 2. If the sample size \(n\) is such that \(n*p > 5\) and \(n*(1-p) > 5\), we can say that the sample size is large enough, and the sampling distribution of the sample proportion can be approximated with a normal distribution. If neither of these conditions is met, then the sample size is not large enough.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
The normal distribution is a fundamental concept in statistics. It's a symmetric, bell-shaped curve that describes how values of a variable are distributed. The peak of the curve represents the mean of the data set, and the spread or width of the curve indicates the standard deviation. The area under the curve corresponds to the probabilities of different outcomes. This distribution is crucial for conducting statistical tests because it simplifies complex data analysis. Many real-world phenomena naturally conform to this pattern, such as test scores, heights, or measurement errors. This universality makes it a powerful tool for making inferences about a larger population from a sample. When we talk about using normal distribution in hypothesis testing, it's about using this predictable pattern to determine the probability of your observations under the assumed conditions of your test.
Population Proportion
Population proportion is a measure used in statistics to indicate the fraction of the total population that has a particular characteristic. It's denoted by the symbol \( p \). For example, if we are studying a population of students and want to know the proportion who passed an exam, \( p \) would represent the fraction of students who passed.Understanding population proportion is crucial because it helps in estimating attributes of real populations. To estimate \( p \), you need a sample from the population. The representative sample gives us the sample proportion, usually denoted as \( \hat{p} \). The sample proportion is used as an estimate for the actual population proportion.Accurate estimation of the population proportion is essential for hypothesis testing, where we test assumptions about \( p \). The accuracy of a hypothesis test highly depends on how well the sample represents the whole population.
Hypothesis Test
A hypothesis test is a statistical method used to make inferences or draw conclusions about a population. It's essentially a way to test a claim about a population parameter, such as the mean or proportion.The process starts with stating a null hypothesis (\( H_0 \)) that represents no effect or difference, and an alternative hypothesis (\( H_a \)) that indicates the presence of an effect or difference. For instance, you might test whether the proportion of students passing an exam is greater than a certain threshold.Using sample data, hypothesis tests allow us to calculate a test statistic. This statistic is compared against a critical value from the normal distribution to decide whether to reject \( H_0 \). Rejecting the null hypothesis suggests that the data provides enough evidence for \( H_a \). However, it's important to carefully check assumptions such as normality of distribution before performing these tests to ensure valid conclusions.
Sample Size Conditions
Determining the appropriate sample size is critical when conducting hypothesis tests for population proportions. A sufficiently large sample size ensures the accuracy and reliability of statistical tests.The Central Limit Theorem (CLT) helps define when the sample size is large enough. According to the CLT, the sampling distribution of the sample mean will be approximately normal if the sample size is large, regardless of the initial population's distribution. For population proportions, two conditions must be fulfilled:
  • \( n \cdot p > 5 \), where \( n \) is the sample size and \( p \) is the population proportion.
  • \( n \cdot (1-p) > 5 \).
If these conditions are satisfied, the sample size is deemed sufficient for using the normal distribution in hypothesis testing. If not, the results might not be accurate, emphasizing the need for careful planning during experimental design.

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Most popular questions from this chapter

According to the analysis of Federal Reserve statistics and other government data, American households with credit card debts owed an average of \(\$ 15,706\) on their credit cards in August 2015 (www.nerdwallet.com). A recent random sample of 500 American households with credit card debts produced a mean credit card debt of \(\$ 16,377\) with a standard deviation of \(\$ 3800 .\) Do these data provide significant evidence at a \(1 \%\) significance level to conclude that the current mean credit card debt of American households with credit card debts is higher than \(\$ 15,706 ?\) Use both the \(p\) -value approach and the critical-value approach.

Acme Bicycle Company makes derailleurs for mountain bikes. Usually no more than \(4 \%\) of these parts are defective, but occasionally the machines that make them get out of adjustment and the rate of defectives exceeds \(4 \%\). To guard against this, the chief quality control inspector takes a random sample of 130 derailleurs each week and checks each one for defects. If too many of these parts are defective, the machines are shut down and adjusted. To decide how many parts must be defective to shut down the machines, the company's statistician has set up the hypothesis test $$ H_{0}: p \leq .04 \text { versus } H_{1}: p>.04 $$ where \(p\) is the proportion of defectives among all derailleurs being made currently. Rejection of \(H_{0}\) would call for shutting down the machines. For the inspector's convenience, the statistician would like the rejection region to have the form, "Reject \(H_{0}\) if the number of defective parts is \(C\) or more." Find the value of \(C\) that will make the significance level (approximately) \(.05\).

The manufacturer of a certain brand of auto batteries claims that the mean life of these batteries is 45 months. A consumer protection agency that wants to check this claim took a random sample of 24 such batteries and found that the mean life for this sample is \(43.05\) months. The lives of all such batteries have a normal distribution with the population standard deviation of \(4.5\) months. a. Find the \(p\) -value for the test of hypothesis with the alternative hypothesis that the mean life of these batteries is less than 45 months. Will you reject the null hypothesis at \(\alpha=.025\) ? b. Test the hypothesis of part a using the critical-value approach and \(\alpha=.025\).

At Farmer's Dairy, a machine is set to fill 32 -ounce milk cartons. However, this machine does not put exactly 32 ounces of milk into each carton; the amount varies slightly from carton to carton but has an approximate normal distribution. It is known that when the machine is working properly, the mean net weight of these cartons is 32 ounces. The standard deviation of the milk in all such cartons is always equal to 15 ounce. The quality control inspector at this company takes a sample of 25 such cartons every week, calculates the mean net weight of these cartons, and tests the null hypothesis, \(\mu=32\) ounces, against the altemative hypothesis, \(\mu \neq 32\) ounces. If the null hypothesis is rejected, the machine is stopped and adjusted. A recent sample of 25 such cartons produced a mean net weight of \(31.93\) ounces. a. Calculate the \(p\) -value for this test of hypothesis. Based on this \(p\) -value, will the quality control inspector decide to stop the machine and adjust it if she chooses the maximum probability of a Type I error to be .01? What if the maximum probability of a Type I error is 05 ? b. Test the hypothesis of part a using the critical-value approach and \(\alpha=.01\). Does the machine need to be adjusted? What if \(a=.05 ?\)

Consider the following null and alternative hypotheses: $$ H_{0}=p=.44 \text { versus } H_{1}: p<.44 $$ A random sample of 450 observations taken from this population produced a sample proportion of \(.39 .\) a. If this test is made at a \(2 \%\) significance level, would you reject the null hypothesis? Use the critical-value approach. b. What is the probability of making a Type I error in part a? c. Calculate the \(p\) -value for the test. Based on this \(p\) -value, would you reject the null hypothesis if \(\alpha=.01 ?\) What if \(\alpha=.025\) ?

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