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Make the following tests of hypotheses. 1\. \(H_{0}: \mu=80, H_{1}: \mu \neq 80, n=33, \bar{x}=76.5, \sigma=15, \alpha=.10\) b. \(H_{0}: \mu=32, H_{1}: \mu<32, n=75, \bar{x}=26.5, \sigma=7.4, \alpha=.01\) \& \(H_{0}: \mu=55, H_{1}: \mu>55, n=40, \bar{x}=60.5, \sigma=4, \quad \alpha=.05\)

Short Answer

Expert verified
For problem 1, \(H_{0}\) cannot be rejected. For problem 2 and 3, \(H_{0}\) should be rejected.

Step by step solution

01

Problem 1: Calculation

Given are \(\mu=80\), \(\bar{x}=76.5\), \(n=33\), \(\sigma=15\), and \(\alpha=0.10\). First calculate the standard error (\(SE = \sigma/\sqrt{n}\)) which gives us \(SE\approx2.61\). Next, calculate the test statistic \(Z_{test} = (\bar{x}-\mu)/SE \approx -1.34\). The critical z value at \(\alpha=0.10\) for a two-tailed test (\(H_{1}: \mu \neq 80\)) is ±1.645. Because -1.645 < -1.34 < 1.645, the null hypothesis \(H_{0}\) cannot be rejected.
02

Problem 2: Calculation

Given are \(\mu=32\), \(\bar{x}=26.5\), \(n=75\), \(\sigma=7.4\), and \(\alpha=0.01\). First calculate the standard error (\(SE = \sigma/\sqrt{n}\)) which gives us \(SE\approx0.85\). Next, calculate the test statistic \(Z_{test} = (\bar{x}-\mu)/SE \approx -6.46\). The critical z value at \(\alpha=0.01\) for a left-tailed test (\(H_{1}: \mu < 32\)) is -2.33. Because -6.46 < -2.33, the null hypothesis \(H_{0}\) should be rejected.
03

Problem 3: Calculation

Given are \(\mu=55\), \(\bar{x}=60.5\), \(n=40\), \(\sigma=4\), and \(\alpha=0.05\). First calculate the standard error (\(SE = \sigma/\sqrt{n}\)) which gives us \(SE\approx0.63\). Next, calculate the test statistic \(Z_{test} = (\bar{x}-\mu)/SE \approx 8.75\). The critical z value at \(\alpha=0.05\) for a right-tailed test (\(H_{1}: \mu > 55\)) is 1.645. Because 8.75 > 1.645, the null hypothesis \(H_{0}\) should be rejected.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the z-test
A z-test is a statistical tool used to determine whether there is a significant difference between the sample mean and the population mean. It is most suitable when the population variance is known, and the sample size is large (typically over 30). The test calculates a z-score, which shows how many standard deviations the sample mean is from the population mean.
This method is applied in hypothesis testing to decide whether to reject the null hypothesis. The z-score is compared against critical values from the z-distribution to make this decision. Whether a one-tailed or two-tailed z-test is used depends on the alternate hypothesis.
Some key points to remember are:
  • Applicable when the population standard deviation is known.
  • Ideal for testing hypotheses about the mean.
  • Uses the standard normal distribution to determine probabilities.
Decoding critical value
In the context of a z-test, a critical value is the threshold that the calculated z-score must reach or exceed for the null hypothesis to be rejected. This value depends on the significance level, denoted by \(\alpha\), and the nature of the test (one-tailed or two-tailed).
For a given \(\alpha\) level, the critical value can be found using the standard normal distribution (z-table). For example, in a typical two-tailed test with \(\alpha = 0.10\), the critical values are ±1.645. This means if the calculated z-score falls outside this range, the null hypothesis is rejected.
Key aspects of critical values include:
  • They set the cutoff points for hypothesis tests.
  • Determine the rejection regions for a test.
  • Choose them based on the desired level of confidence and type of test.
Understanding standard error
The standard error (SE) plays a crucial role in hypothesis testing. It represents the variability of the sample mean estimate of a population mean. A smaller standard error indicates that the sample mean is a more accurate reflection of the population mean.
The standard error is calculated as the population standard deviation \(\sigma\) divided by the square root of the sample size \(n\), expressed as \(SE = \sigma / \sqrt{n}\). This formula shows that a larger sample size will result in a smaller standard error, making the sample mean estimate more reliable.
Key points about standard error include:
  • Measures the accuracy with which a sample represents a population.
  • Decreases with an increase in sample size.
  • Used to calculate the test statistic in z-tests.
Exploring the null hypothesis
The null hypothesis (denoted as \(H_0\)) is a foundational concept in hypothesis testing. It represents a statement that there is no effect or no difference, and it serves as the default assumption to be tested against.
In our examples, the null hypothesis generally states that a population parameter (like the mean) is equal to a specific value. Hypothesis testing aims to gather evidence against this null hypothesis.
Its counterpart, the alternative hypothesis \(H_1\), proposes what the research is intended to prove. In the examples, if the test statistic leads us to reject \(H_0\), it suggests the sample provides sufficient evidence that the null hypothesis might not be true.
Crucial aspects of the null hypothesis include:
  • Serves as the starting point for hypothesis testing.
  • Is formulated such that it can be tested mathematically.
  • Rejection of \(H_0\) implies acceptance of \(H_1\), providing evidence for a significant effect or difference.

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Most popular questions from this chapter

PolicyInteractive of Eugene, Oregon conducted a study of American adults in April 2014 for the Center for a New American Dream. Seventy-five percent of the adults included in this study said that having basic needs met is very or extremely important in their vision of the American dream (www.newdream.org). A recent sample of 1500 American adults were asked the same question and \(72 \%\) of them said that having basic needs met is very or extremely important in their vision of the American dream. a. Using the critical-value approach and \(\alpha=.01\), test if the current percentage of American adults who hold the abovementioned opinion is less than \(75 \%\). b. How do you explain the Type I error in part a? What is the probability of making this error in part a? c. Calculate the \(p\) -value for the test of part a. What is your conclusion if \(\alpha=.01 ?\)

According to the National Association of Colleges and Employers, the average starting salary of 2014 college graduates with a bachelor's degree was \(\$ 45,473\) (www.naceweb.org). A random sample of 1000 recent college graduates from a large city showed that their average starting salary was \(\$ 44,930\). Suppose that the population standard deviation for the starting salaries of all recent college graduates from this city is \(\$ 7820\). a. Find the \(p\) -value for the test of hypothesis with the alternative hypothesis that the average starting salary of recent college graduates from this city is less than \(\$ 45,473 .\) Will you reject the null hypothesis at \(\alpha=.01 ?\) Explain. What if \(\alpha=.025 ?\) b. Test the hypothesis of part a using the critical-value approach. Will you reject the null hypothesis at \(\alpha=.01 ?\) What if \(\alpha=.025 ?\)

In each of the following cases, do you think the sample size is large enough to use the normal distribution to make a test of hypothesis about the population proportion? Explain why or why not. a. \(n=40\) and \(\quad p=.11\) b. \(n=100\) and \(p=.73\) c. \(n=80 \quad\) and \(\quad p=.05\) d. \(n=50 \quad\) and \(\quad p=.14\)

A random sample of 18 observations produced a sample mean of \(9.24\). Find the critical and observed values of \(z\) for each of the following tests of hypothesis using \(\alpha=.05 .\) The population standard deviation is known to be \(5.40\) and the population distribution is normal. a. \(H_{0}: \mu=8.5\) versus \(\quad H_{1}: \mu \neq 8.5\) b. \(H_{0}: \mu=8.5\) versus \(\quad H_{1}: \mu>8.5\)

According to the U.S. Bureau of Labor Statistics, all workers in America who had a bachelor's degree and were employed earned an average of \(\$ 1224\) a week in 2014 . A recent sample of 400 American workers who have a bachelor's degree showed that they earn an average of \(\$ 1260\) per week. Suppose that the population standard deviation of such earnings is \(\$ 160\). a. Find the \(p\) -value for the test of hypothesis with the alternative hypothesis that the current mean weekly earning of American workers who have a bachelor's degree is higher than \(\$ 1224\). Will you reject the null hypothesis at \(\alpha=.025 ?\) b. Test the hypothesis of part a using the critical-value approach and \(\alpha=.025\).

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