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91Ó°ÊÓ

A large city with chronic economic problems is considering legalizing casino gambling. The city council wants to estimate the proportion of all adults in the city who favor legalized casino gambling. Assume that a preliminary sample has shown that \(63 \%\) of the adults in this city favor legalized casino gambling. How large should the sample size be so that the \(95 \%\) confidence interval for the population proportion has a margin of error of \(.05 ?\)

Short Answer

Expert verified
To achieve a \( 95 \% \) confidence interval with a margin of error of \( .05 \), the sample size should be least 346 people when rounded up to the nearest whole number. Note that a larger sample size may provide a more accurate estimate.

Step by step solution

01

Identify the given values

We have \( p = 0.63 \) as the preliminary sample shows that \( 63 \% \) of adults favor legalized gambling. The margin of error \( E = 0.05 \). The Z-value for a \( 95 \% \) confidence level is \( 1.96 \), which can be found in a z-table or z-score calculator.
02

Substitute the values in the formula

Substituting these values into the sample size formula, we get \( n = \frac{1.96^2 * 0.63 * (1-0.63)}{0.05^2} \).
03

Calculate the sample size

Computing this expression will give us the required sample size. The result might not be a round number, but we need to round it up because the sample size can't be a fraction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval is a range of values used to estimate an unknown population parameter. It gives you an idea about how certain you can be in your estimate. In statistics, the confidence interval provides a way to quantify uncertainty in measurement or prediction.
A confidence interval is defined by its "boundaries". For instance, if we have a confidence interval of 95%, it means that in 95 out of 100 cases, the interval will contain the true population parameter you're estimating. It's a handy way to understand the reliability of the parameter you're measuring.
  • To calculate a confidence interval: you need an estimated population parameter (like a proportion) and its associated standard error.
  • A common confidence interval level is 95%, but it can be adjusted to higher or lower levels depending on the required precision.
Calculation of the confidence interval uses the formula:\[ \text{CI} = \text{Point Estimate} \pm Z * \text{Standard Error} \]Where "Z" is the z-score corresponding to the desired confidence level. In the problem at hand, the calculation attempts to determine the confidence interval for the proportion of adults favoring casino gambling.
Population Proportion
The population proportion is a measure that represents the fraction of the population with a certain characteristic. In our situation, it's the ratio of adults who favor legalized casino gambling in the city. Population proportions are key in statistical sampling and inference as they help make predictions on the broader population based on a sample.
Knowing the population proportion allows us to compute other valuable statistics, like the confidence interval or sample size needed for the study:
  • Using sample data helps make inferences about a population proportion when a complete census is not possible.
  • Accurate initial estimates, like knowing that 63% favor gambling, are crucial to further calculations.
In this example, knowing that 63% of adults in a preliminary sample favor legalized gambling directs us to accurately calculate the necessary sample size for robust statistical conclusions later.
Sample Size Calculation
The sample size calculation is an important part of planning any survey or study as it impacts the study’s validity and cost. The aim is to capture a portion of the population that's large enough to accurately mirror the population's traits with minimum error. Larger sample sizes usually provide more accurate estimations, but they also require more resources.
The formula used to determine the sample size needed for a given margin of error in estimating a proportion is:\[ n = \frac{Z^2 \cdot p \cdot (1-p)}{E^2} \]where:
  • \(Z\) is the z-score related to the chosen confidence level (1.96 for 95%).
  • \(p\) is the estimated proportional value (0.63 in this scenario).
  • \(E\) is the margin of error (0.05).
Using the above formula, we estimate the sample size required to ensure the confidence interval's precision remains within acceptable limits. Here, rounding up the sample size is essential as it needs to account for full individuals; partial population counts don't apply in practice.
Margin of Error
The margin of error represents the degree of error in a sample statistic. Simply put, it's the "wiggle room" you might have in your estimate of a population parameter. In our example, the margin of error is set at 0.05, meaning that the estimated proportion could range above or below the estimated value by this amount.
When the margin of error is smaller, you have greater confidence that your estimate is close to the actual population parameter:
  • A smaller margin often requires a larger sample size, as it implies more precision.
  • The desired level of precision (margin of error) affects the confidence interval and directly ties into sample size calculations.
Mathematically, the margin of error for a proportion can be calculated as:\[ E = Z \times \sqrt{\frac{p(1-p)}{n}} \]The formula explains the margin of error depends on the z-score (confidence level), the estimated proportion, and the sample size in question. For meaningful conclusions, balancing the size of the sample against practical constraints like cost, time, and resources is prudent.

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Most popular questions from this chapter

You want to estimate the percentage of students at your college or university who are satisfied with the campus food services. Briefly explain how you will make such an estimate. Select a sample of 30 students and ask them whether or not they are satisfied with the campus food services. Then calculate the percentage of students in the sample who are satisfied. Using this information, find the confidence interval for the corresponding population percentage. Select your own confidence level.

A hospital administration wants to estimate the mean time spent by patients waiting for treatment at the emergency room. The waiting times (in minutes) recorded for a random sample of 35 such patients are given below. The population standard deviation is not known. \(\begin{array}{rrrrrrr}30 & 7 & 68 & 76 & 47 & 60 & 51 \\ 64 & 25 & 35 & 29 & 30 & 35 & 62 \\ 96 & 104 & 58 & 32 & 32 & 102 & 27 \\ 45 & 11 & 64 & 62 & 72 & 39 & 92 \\ 84 & 47 & 12 & 33 & 55 & 84 & 36\end{array}\) Construct a \(99 \%\) confidence interval for the corresponding population mean.

You are working for a bank. The bank manager wants to know the mean waiting time for all customers who visit this bank. She has asked you to estimate this mean by taking a sample. Briefly explain how you will conduct this study. Collect data on the waiting times for 45 customers who visit a bank. Then estimate the population mean. Choose your own confidence level.

A consumer agency wants to estimate the proportion of all drivers who wear seat belts while driving. What is the most conservative estimate of the minimum sample size that would limit the margin of error to within \(.03\) of the population proportion for a \(99 \%\) confidence interval?

Explain the various alternatives for decreasing the width of a confidence interval. Which is the best alternative

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