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What is the point estimator of the population mean, \(\mu\) ? How would you calculate the margin of error for an estimate of \(\mu\) ?

Short Answer

Expert verified
The point estimator of the population mean, \(\mu\), is the sample mean, \(\overline{X}\). The margin of error for an estimate of \(\mu\) is calculated with the formula \(E = Z \cdot SE_{\overline{X}}\), then added and subtracted from \(\overline{X}\) to provide a range for \(\mu\).

Step by step solution

01

Define Point Estimator

A point estimator of a population parameter is a single value of a statistic. For the population mean, \(\mu\), the point estimator is the sample mean, \(\overline{X}\), which is calculated by summing up all the values of a sample and dividing by the number of observations in the sample.
02

Calculate Margin of Error

The next step is to calculate the margin of error. The margin of error for an estimate of \(\mu\) represents the range in which we expect the population mean to lie and is a direct multiplication of the standard deviation of the sample mean (standard error), \(SE_{\overline{X}}\), and the z-score for the desired confidence level (calculated from a normal distribution table). The formula is: \(E = Z \cdot SE_{\overline{X}}\), where \(E\) is the margin of error, \(Z\) is the standard score or z-value (retrieved from z-table based on desired confidence level), and \(SE_{\overline{X}} = \frac{s}{\sqrt{n}}\), where \(s\) denotes sample standard deviation and \(n\) denotes sample size.
03

Conclude

Once calculated, this margin of error can be added and subtracted from the sample mean to provide a range within which the population mean is likely to lie. It's a measure of the precision of the point estimation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Mean
The population mean, denoted as \( \mu \), is the average of a set of values for the entire group being studied. It's a fundamental concept in statistics that represents the central tendency of a population. Think of the population mean as a way to summarize everything about a group into a single number.

In practice, determining the exact population mean can be quite challenging. This is often because collecting data from every member of a large population is not feasible. Instead, statisticians use samples, which are smaller groups selected from the population. Using these samples, we can estimate the population mean's value, making it an effective tool for large data analysis.

Most importantly, when we calculate or estimate the population mean, it provides a concise summary of the data. It helps us understand the average scenario or behavior of the group we are interested in.
Margin of Error
The margin of error is a statistical concept that tells us how much we can expect our sample estimate, like the sample mean, to differ from the true population mean.

When we say a population mean is estimated to be a certain value with a margin of error, we're providing a range in which we expect the actual population mean to fall. This range is essentially the sample mean plus and minus the margin of error.
  • Understanding Margin of Error: It's a way to express the uncertainty of our estimate. A smaller margin means more confidence that the sample mean is close to the population mean.
  • Calculating Margin of Error: The formula is \( E = Z \cdot SE_{\overline{X}} \), where \( Z \) is the z-score from standard normal distribution associated with our confidence level, and \( SE_{\overline{X}} \) is the standard error of the sample mean.
  • Purpose: The margin of error helps us understand the reliability and precision of our population mean estimate.
Choose an appropriate confidence level to balance between precision and risk. For instance, a 95% confidence level is typically used, but higher or lower levels might be suitable depending on the situation.
Sample Mean
The sample mean, represented as \( \overline{X} \), serves as a point estimator for the population mean, \( \mu \). This means that we use the sample mean to make educated guesses about the population mean when direct calculation isn't possible.

Computing the sample mean is straightforward. You add up all the individual observations within your sample and then divide by the number of observations. Here's the formula: \( \overline{X} = \frac{1}{n} \sum_{i=1}^{n} X_i \), where \( n \) is the number of observations, and \( X_i \) are the individual sample data points.
  • Why use the Sample Mean: It's easier to calculate since you only need data from a sample rather than the whole population.
  • Advantage of Sample Mean: It provides a simple yet powerful way to summarize your sample data's central tendency.
  • Limitation: Depending on the sample size and variation, the sample mean might not always closely reflect the actual population mean.
The sample mean is highly valued as a statistical tool because, with a well-chosen sample, it effectively estimates the population mean, enabling decision-making and analysis without requiring full data collection.

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Most popular questions from this chapter

The standard deviation for a population is \(\sigma=7.14\). A random sample selected from this population gave a mean equal to \(48.52\). a. Make a \(95 \%\) confidence interval for \(\mu\) assuming \(n=196\). b. Construct a \(95 \%\) confidence interval for \(\mu\) assuming \(n=100\). c. Determine a \(95 \%\) confidence interval for \(\mu\) assuming \(n=49\). d. Does the width of the confidence intervals constructed in parts a through c increase as the sample size decreases? Explain.

The high price of medicines is a source of major expense for those seniors in the United States who have to pay for these medicines themselves. A random sample of 2000 seniors who pay for thein medicines showed that they spent an average of \(\$ 4600\) last year on medicines with a standard deviation of \(\$ 800\). Make a \(98 \%\) confidence interval for the corresponding population mean.

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You want to estimate the proportion of students at your college who hold off- campus (part-time or full-time) jobs. Briefly explain how you will make such an estimate. Collect data from 40 students at your college on whether or not they hold off-campus jobs. Then calculate the proportion of students in this sample who hold offcampus jobs. Using this information, estimate the population proportion. Select your own confidence level.

It is said that happy and healthy workers are efficient and productive. A company that manufactures exercising machines wanted to know the percentage of large companies that provide on-site health club facilities. A random sample of 240 such companies showed that 96 of them provide such facilities on site. a. What is the point estimate of the percentage of all such companies that provide such facilities on site? b. Construct a \(97 \%\) confidence interval for the percentage of all such companies that provide such facilities on site. What is the margin of error for this estimate?

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