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A city planner wants to estimate the average monthly residential water usage in the city at a \(97 \%\) confidence level. Based on earlier data, the population standard deviation of the monthly residential water usage in this city is \(389.60\) gallons. How large a sample should be selected so that the estimate for the average monthly residential water usage in this city is within 100 gallons of the population mean?

Short Answer

Expert verified
Since we cannot have a fraction of a person participating in the sample, we need to round up to the next whole number. Thus, a sample of 68 residents should be selected to estimate the average monthly residential water usage in the city within 100 gallons of the population mean at a 97% confidence level.

Step by step solution

01

Identify the given values

From the problem, we know the following: population standard deviation, \(\sigma = 389.60\) gallons, the desired margin of error, \(E = 100\) gallons, and the confidence level is \(97\%\).
02

Find the Z-value

To find the Z-value corresponding to a \(97\%\) confidence level, we look up the value in a Standard Normal (Z) Table or use an online Z-score calculator. A \(97\%\) confidence level corresponds to an alpha level of \(0.03\), so we need to look up \(1 - 0.03/2 = 0.985\) in the Z table, which gives us a Z-value is approximately \(2.17\). So, \(Z = 2.17\).
03

Substitute the values into the formula and solve for n

After identifying all needed statistics, plug them into the formula \(n = {Z^2 * \sigma^2}/{E^2}\). Substituting the values, we get \(n = {(2.17)^2 * (389.60)^2}/{(100)^2}\). Simplifying further, we find that \(n \approx 67.97\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Level
The confidence level is a measure of how certain we can be that our sample accurately reflects the population. When we say a result is at a 97% confidence level, it means if we were to take 100 different samples, about 97 of them would contain the true population mean.

This level of confidence is crucial in research, especially when estimating population parameters like average water usage. Higher confidence levels result in wider intervals, which means more certainty, but at the cost of precision.

When deciding on a confidence level, the choice depends on how precise we want our estimate to be and how much uncertainty we are willing to accept. For the city planner in this task, a rather high confidence level of 97% is chosen, indicating the need for a very reliable estimate.
Margin of Error
The margin of error (MOE) is the range within which we expect the true population parameter to lie. It gives us an idea about the extent of error we may encounter from our sampling. In the context of the water usage estimation, the MOE is set at 100 gallons.

A larger margin of error means a less precise estimate. Conversely, a smaller margin of error means we expect our sample to be more precise.

Here's how it impacts the calculation:
  • Smaller MOE requires a larger sample size to achieve the same confidence level.
  • Higher MOE allows for a smaller sample because you're accepting more potential error.
This knowledge helps in planning the size of the study sample effectively.
Population Standard Deviation
Population standard deviation (\(\sigma\)) measures how much the data in a population varies from the population mean. It is a critical element in determining sample size because it tells us how spread out the data points are.

In this exercise, the standard deviation is already provided as 389.60 gallons.

This value indicates significant fluctuation in monthly water usage among residents, which directly influences how many samples are needed to achieve a reliable estimate. A higher standard deviation means more variability and typically requires a larger sample to ensure that our sample mean reflects the population accurately. The formula for calculating sample size incorporates standard deviation as it ensures our results are representative of the population's variability.
Z-value
The Z-value, also known as the Z-score, is a statistical metric that expresses the distance of a data point from the mean in terms of standard deviations. It is used in the context of sample size calculation to translate a desired confidence level into a numeric value.

The Z-value is derived from the standard normal distribution table and is specific to the chosen confidence level.
  • For a 97% confidence level, like in this exercise, the Z-value is approximately 2.17.
  • This means we are looking for a data point that is 2.17 standard deviations away from the mean, reflecting our chosen level of confidence.
The role of the Z-value is crucial as it affects the width of the confidence interval. Using our Z-value with the standard deviation and margin of error, we determine how many samples are necessary to attain our desired level of accuracy and reliability.

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Most popular questions from this chapter

The standard deviation for a population is \(\sigma=14.8\). A random sample of 25 observations selected from this population gave a mean equal to \(143.72\). The population is known to have a normal distribution. a. Make a \(99 \%\) confidence interval for \(\mu\). b. Construct a \(95 \%\) confidence interval for \(\mu\). c. Determine a \(90 \%\) confidence interval for \(\mu\). d. Does the width of the confidence intervals constructed in parts a through \(\mathrm{c}\) decrease as the confidence level decreases? Explain your answer.

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When one is attempting to determine the required sample size for estimating a population mean, and the information on the population standard deviation is not available, it may be feasible to take a small preliminary sample and use the sample standard deviation to estimate the required sample size, \(n .\) Suppose that we want to estimate \(\mu\), the mean commuting distance for students at a community college, to a margin of error within 1 mile with a confidence level of \(95 \%\). A random sample of 20 students yields a standard deviation of \(4.1\) miles. Use this value of the sample standard deviation, \(s\), to estimate the required sample size, \(n .\) Assume that the corresponding population has an approximate normal distribution.

A random sample of 200 observations selected from a population produced a sample proportion equal to \(.91\). a. Make a \(90 \%\) confidence interval for \(p\). b. Construct a \(95 \%\) confidence interval for \(p\). c. Make a \(99 \%\) confidence interval for \(p\). d. Does the width of the confidence intervals constructed in parts a through \(\mathrm{c}\) increase as the confidence level increases? If yes, explain why.

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