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The living spaces of all homes in a city have a mean of 2300 square feet and a standard deviation of 500 square feet. Let \(\bar{x}\) be the mean living space for a random sample of 25 homes selected from this city. Find the mean and standard deviation of the sampling distribution of \(\bar{x}\).

Short Answer

Expert verified
The mean of the sampling distribution of \( \bar{x} \) is 2300 square feet, and the standard deviation is 100 square feet.

Step by step solution

01

Find Mean of Sampling Distribution

The mean of a sampling distribution, often denoted as \( \mu_{\bar{x}} \), is equal to the mean of the population. So in this case, \( \mu_{\bar{x}} \) would be equal to 2300 square feet.
02

Find Standard Deviation of Sampling Distribution

The standard deviation of a sampling distribution, also known as the standard error, is calculated by dividing the standard deviation of the population by the square root of the sample size. This can be represented as \( \sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \), where \( \sigma \) is the standard deviation of the population and \( n \) is the sample size. Plugging in the given values, we get \( \sigma_{\bar{x}} = \frac{500}{\sqrt{25}} = 100 \) square feet.

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