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An office supply company conducted a survey before marketing a new paper shredder designed for home use. In the survey, \(80 \%\) of the people who tried the shredder were satisfied with it. Because of this high satisfaction rate, the company decided to market the new shredder. Assume that \(80 \%\) of all people are satisfied with this shredder. During a certain month, 100 customers bought this shredder. Find the probability that of these 100 customers, the number who are satisfied is a. exactly 75 b. 73 or fewer c. 74 to 85

Short Answer

Expert verified
The probabilities for a, b, and c can be calculated using the binomial probability formula and summing as needed.

Step by step solution

01

Understand the Problem

We need to calculate binomial probabilities. For a binomial distribution, the formula is \(P(x)= \binom{n}{x}*(p^x)*(q^{n-x})\) where n is the number of trials, p is the probability of success, q is the probability of failure, and x is the number of successful outcomes.
02

Define the variables

In this case, n=100 (number of customers), p=0.8 (satisfaction rate), q=0.2 (unsatisfaction rate), and x varies depending on the scenario.
03

Calculate for a

For a, we need to find the probability of exactly 75 satisfied customers: \(P(75)= \binom{100}{75}*(0.8^{75})*(0.2^{25}) \)
04

Calculate for b

For b, we need P(x <= 73), which is the sum of probabilities from x=0 to x=73.
05

Calculate for c

For c, we need P(74 <= x <= 85), which we can calculate by subtracting the sum of the probabilities from x=0 to x=73 and the sum of the probabilities from x=86 to x=100 from 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
In any statistical problem, the crucial first step is determining the probability you need to calculate. Probability quantifies the likelihood of a certain event occurring in a defined range of outcomes. In our exercise, we are dealing with the probability of customer satisfaction, where we have three specific questions — probability of exactly 75 satisfied customers, probability of 73 or fewer satisfied customers, and probability of having between 74 to 85 satisfied customers.

- **Exactly 75 satisfied**: This asks for the probability of an outcome happening in one specific way. - **73 or fewer satisfied**: This is a cumulative probability scenario, meaning we add up probabilities from 0 to 73. - **Between 74 to 85 satisfied**: This requires understanding how to add and subtract probabilities effectively to isolate the desired range.
Breaking down the problem into each part and using consistent terminology (like probability of success) helps streamline the calculation process.
Binomial Probability Formula
The binomial probability formula allows us to calculate the probability of achieving exactly x number of "successes" in n trials. The formula is given by:\[P(x) = \binom{n}{x} (p^x)(q^{n-x})\]In this formula, \(\binom{n}{x}\) represents the binomial coefficient, a mathematical way of determining the number of combinations in which x successes can occur in n trials. "p" is the probability of success (in this case, 0.8 or 80% satisfaction rate), while "q" is the probability of failure (20% here, calculated as 1 - p).

For instance, to find out the probability that exactly 75 out of 100 customers are satisfied, plug the values into the formula:\[ P(75) = \binom{100}{75} (0.8^{75})(0.2^{25})\]This approach assumes each customer acts independently regarding their satisfaction, which aligns with the conditions for using a binomial model.
Statistical Analysis
Statistical Analysis in the context of our exercise involves using the Binomial Distribution to make predictions and decisions about a population or process. It’s not just about crunching numbers — it involves making informed judgments based on statistical data.

With binomial distributions, statistical analysis can help determine things like how likely certain numbers of satisfied customers are, and whether that's significant for business decisions. In practical terms, if we find during our analysis that less than a desired number of customers is satisfied, it might lead the company to investigate further or take action to improve the product.

Understanding variability is also key in analysis. It's essential to consider how much deviation or variance there is in customer satisfaction, which plays into how confident we are in the predictions our binomial distribution gives us. More generally, statistical analysis helps a business fine-tune its approaches based on the information received from the data, ensuring they cater to customer satisfaction more effectively.

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Most popular questions from this chapter

How do the width and height of a normal distribution change when its mean remains the same but its standard deviation decreases?

Johnson Electronics makes calculators. Consumer satisfaction is one of the top priorities of the company's management. The company guarantees the refund of money or a replacement for any calculator that malfunctions within two years from the date of purchase. It is known from past data that despite all efforts, \(5 \%\) of the calculators manufactured by this company malfunction within a 2-year period. The company recently mailed 500 such calculators to its customers. a. Find the probability that exactly 29 of the 500 calculators will be returned for refund or replacement within a 2 -year period. b. What is the probability that 27 or more of the 500 calculators will be returned for refund or replacement within a 2 -year period? c. What is the probability that 15 to 22 of the 500 calculators will be returned for refund or replacement within a 2 -year period?

The management of a supermarket wants to adopt a new promotional policy of giving a free gift to every customer who spends more than a certain amount per visit at this supermarket. The expectation of the management is that after this promotional policy is advertised, the expenditures for all customers at this supermarket will be normally distributed with a mean of $$\$ 95$$ and a standard deviation of $$\$ 20.$$ If the management wants to give free gifts to at most \(10 \%\) of the customers, what should the amount be above which a customer would receive a free gift?

Obtain the following probabilities for the standard normal distribution. a. \(P(z>-.98)\) b. \(P(-2.47 \leq z \leq 1.29)\) c. \(P(0 \leq z \leq 4.25)\) d. \(P(-5.36 \leq z \leq 0)\) e. \(P(z>6.07)\) f. \(P(z<-5.27)\)

Let \(x\) denote the time taken to run a road race. Suppose \(x\) is approximately normally distributed with a mean of 190 minutes and a standard deviation of 21 minutes. If one runner is selected at random, what is the probability that this runner will complete this road race a. in less than 160 minutes? b. in 215 to 245 minutes?

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