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For the standard normal distribution, find the area within one standard deviation of the mean - that is, the area between \(\mu-\sigma\) and \(\mu+\sigma .\)

Short Answer

Expert verified
The area within one standard deviation of the mean in a standard normal distribution is approximately 0.6826.

Step by step solution

01

Identify the area to calculate

In a standard normal distribution, the mean( \( \mu \) ) is 0 and the standard deviation( \( \sigma \) ) is 1. So, we need to calculate the area under the curve from \( \mu - \sigma = 0 - 1 = -1 \) to \( \mu + \sigma = 0 + 1 = 1 \).
02

Refer to the standard normal distribution table

A standard normal distribution table, also known as z-table, provides the area under the curve to the left of a value. So, to find the area from -1 to 1, we need to find the cumulative area to the left of 1 and subtract from it the cumulative area to the left of -1.
03

Find the cumulative area to the left of 1 and -1

By looking up in the z-table, the cumulative area to the left of 1 is approximately 0.8413 and the cumulative area to the left of -1 is approximately 0.1587.
04

Subtraction for final area

To find the area between -1 and 1, subtract the cumulative area to the left of -1 from the cumulative area to the left of 1. So the area is \( 0.8413 - 0.1587 \approx 0.6826 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean
The mean, often denoted by the symbol \( \mu \), is the average or central value of a set of data in probability and statistics. In the context of a standard normal distribution, the mean is always 0. This zero-mean feature of the standard normal distribution allows for simplified computations and is a cornerstone when using the normal distribution for statistical analyses.

Think of the mean as a balance point. If you were to spread out all the values from a data set along a number line, the mean would be the point where this line is perfectly balanced. For a standard normal distribution, everything revolves around zero. This is crucial because it means that 50% of the data lies below the mean and 50% lies above. It helps us in calculating probabilities using the z-table as we'll see in later sections.
Standard Deviation
The standard deviation, denoted by \( \sigma \), measures the amount of variation or dispersion in a set of values. Specifically, it tells you how spread out the data points are from the mean. In a standard normal distribution, the standard deviation is not just any number - it is precisely 1.

A standard deviation of 1 in a standard normal distribution indicates that data points typically fall within one unit of distance from the mean, or zero. This gives a nice, clean measure of spread which can be used intuitively. When considering areas within a standard deviation of the mean, you are essentially measuring how much of your data is close to the average value. In our example case, it asks for the area between -1 and 1, which represents one standard deviation away from the mean in both directions.
Z-Table
The z-table, or standard normal distribution table, is a mathematical table that allows you to find the cumulative probability of a standard normal distribution below a particular z-score. It serves as a reference to locate areas under the standard normal curve. The value in a z-table corresponds to the area under the standard normal probability curve to the left of any given z-score.

For example, when you look up a z-score of 1 in the z-table, you find a value of about 0.8413. This value indicates that approximately 84.13% of the data in a standard normal distribution lies below a z-score of 1. Without the z-table, calculations of probabilities involving the normal distribution would be much more complex. It is particularly useful in our problem to determine the area between two z-scores by finding the cumulative areas for each and subtracting them.
Cumulative Area
Cumulative area under the normal distribution curve is the probability that a randomly selected value from the distribution is less than or equal to a particular value. In terms of a standard normal distribution, it tells us how much area, as a proportion of the total, lies to the left of a given z-score.

To find the area between two z-scores, such as in our problem, you need to calculate the cumulative area up to the rightmost z-score and subtract from it the cumulative area up to the leftmost z-score. In our example, the cumulative area to the left of z = 1 is approximately 0.8413, and to the left of z = -1 is approximately 0.1587. Subtracting these values, as shown in the step-by-step solution, gives us the total probability or cumulative area between these two scores, which is approximately 68.26%.

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Most popular questions from this chapter

A company that has a large number of supermarket grocery stores claims that customers who pay by personal checks spend an average of $$\$ 87$$ on groceries at these stores with a standard deviation of $$\$ 22 .$$ Assume that the expenses incurred on groceries by all such customers at these stores are normally distributed. a. Find the probability that a randomly selected customer who pays by check spends more than $$\$ 114$$ on groceries. b. What percentage of customers paying by check spend between $$\$ 40$$ and $$\$ 60$$ on groceries? c. What percentage of customers paying by check spend between $$\$ 70$$ and $$\$ 105 ?$$ d. Is it possible for a customer paying by check to spend more than $$\$ 185$$ ? Explain.

Jenn Bard, who lives in the San Francisco Bay area, commutes by car from home to work. She knows that it takes her an average of 28 minutes for this commute in the morning. However, due to the variability in the traffic situation every morning, the standard deviation of these commutes is 5 minutes. Suppose the population of her morning commute times has a normal distribution with a mean of 28 minutes and a standard deviation of 5 minutes. Jenn has to be at work by \(8: 30\) A.M. every morning. By what time must she leave home in the morning so that she is late for work at most \(1 \%\) of the time?

For the standard normal distribution, what does \(z\) represent?

Tommy Wait, a minor league baseball pitcher, is notorious for taking an excessive amount of time between pitches. In fact, his times between pitches are normally distributed with a mean of 36 seconds and a standard deviation of \(2.5\) seconds. What percentage of his times between pitches are a. longer than 39 seconds? b. between 29 and 34 seconds?

Fast Auto Service provides oil and lube service for cars. It is known that the mean time taken for oil and lube service at this garage is 15 minutes per car and the standard deviation is \(2.4\) minutes. The management wants to promote the business by guaranteeing a maximum waiting time for its customers. If a customer’s car is not serviced within that period, the customer will receive a 50% discount on the charges. The company wants to limit this discount to at most 5% of the customers. What should the maximum guaranteed waiting time be? Assume that the times taken for oil and lube service for all cars have a normal distribution.

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