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Chapter 4: Problem 87

A restaurant menu has four kinds of soups, eight kinds of main courses, five kinds of desserts, and six kinds of drinks. If a customer randomly selects one item from each of these four categories, how many different outcomes are possible?

Short Answer

Expert verified
The total number of different meals that can be composed is \(4*8*5*6 = 960\) different combinations possible.

Step by step solution

01

Understand the number of choices

Identify the number of choices in each category. There are: 4 kinds of soups, 8 kinds of main courses, 5 kinds of desserts, and 6 kinds of drinks.
02

Apply the fundamental principle of counting

Since each choice is independent, apply the multiplication rule. This rule states that if there are \(A\) ways of doing something and \(B\) ways of doing another thing, then there are \(A*B\) ways of performing both actions. The total number of combinations possible is therefore \(4*8*5*6\).
03

Calculate the outcome

Multiply the numbers together to get the total number of different outcomes. Doing this calculation will give the final answer.

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