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The following data give the hourly wage rates of eight employees of a company. \(\$ 22\) $$ \begin{array}{lllllll} 22 & 22 & 22 & 22 & 22 & 22 & 22 \end{array} $$ Calculate the standard deviation. Is its value zero? If yes, why?

Short Answer

Expert verified
The standard deviation is zero. This is because all the numbers in the set are the same (22), so there is no spread or variation in the data. Standard deviation measures this spread, so when there is no variation, the standard deviation equals zero.

Step by step solution

01

Understand the Concept of Standard Deviation

Standard deviation is a measure of how spread out the numbers in a data set are. It is the square root of the variance. In other words, it shows how much variation or dispersion there is from the average (mean). The formula to calculate this is: \[ s = \sqrt{\frac{1}{N-1} \sum_{i=1}^{N} (x_i - \bar{x})^2} \]where:- \(N\) is the number of observations- \(x_i\) is the \(i_{th}\) observation- \(\bar{x}\) is the mean of the observations
02

Calculate the Mean

The mean is the average of the numbers. In this case, since all the numbers are the same (22), the mean is also 22.
03

Apply the Standard Deviation Formula

In this case, every \(x_i\) is equal to the mean, so the term \((x_i - \bar{x})^2\) is zero for every term in the sum. This makes the entire sum zero, and so the square root of this sum also equals zero.
04

Answer the Second Part of the Question

As we calculated, the standard deviation is indeed zero. When all the numbers in a set are the same, there is no spread or variation in the data. That is why the standard deviation, which measures this spread, is zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variance
Variance is a statistical concept often used to indicate the degree of spread in a data set. It measures how much the data points differ from the mean. To calculate variance, you first find the mean of the data. Then, subtract the mean from each data point to find the deviation of each point. Square these deviations and sum them up. Finally, divide by the number of data points minus one (for a sample variance) or by the number of data points (for a population variance). The formula looks like this: \[ \text{Variance} = \frac{1}{N-1} \sum_{i=1}^{N} (x_i - \bar{x})^2 \]where:
  • \( N \) is the number of data points.
  • \( x_i \) is each individual data point.
  • \( \bar{x} \) is the mean of the data.
Variance gives you the average of the squared differences from the mean. Higher variance means greater spread in the data.
Mean
The "mean" refers to the average value of a data set, and it's one of the most fundamental concepts in statistics. To determine the mean, you add up all the values in the data set and divide by the number of values. For example, if the data set includes the numbers \( \{22, 22, 22, 22, 22, 22, 22, 22\} \), you sum them first:
  • Sum = 22 + 22 + 22 + 22 + 22 + 22 + 22 + 22 = 176.
Then, divide by the number of data points, which is 8:
  • Mean = \( \frac{176}{8} = 22 \).
In this example, every value in the data set is the same, leading to a mean that matches each individual data point. Understanding the mean provides the baseline for measuring variance and standard deviation.
Dispersion
Dispersion is all about understanding the spread or the scatter of values within a data set. It tells you how much individual data points are spread out around the mean. Low dispersion means data points are tightly clustered near the mean, while high dispersion indicates they are spread out over a broader range. In statistical terms, dispersion can be measured using several metrics:
  • Variance
  • Standard Deviation
  • Range
These measures give insights into the variability within a data set. For example, a set of identical values, like \( \{22, 22, 22, 22, 22, 22, 22, 22\} \), shows zero dispersion because all values are the same. This also means the standard deviation is zero, because there is no variation from the mean.
Data Set
A data set is simply a collection or group of data points or values. Each value is called a data point or observation. In the context of statistical analysis, a data set forms the basis on which calculations like mean, variance, and standard deviation are performed. For example, consider the data set: \( \{22, 22, 22, 22, 22, 22, 22, 22\} \). This is a set of eight observations, where each observation is an hourly wage rate. In any data set, identifying repeating or unique values and understanding how frequently they occur can provide significant insights. This understanding is crucial for analyzing central tendencies and spread, key in many statistical evaluations.
Statistical Measures
Statistical measures are used to describe and interpret data. They help you summarize or quantify information from a data set. Some common statistical measures include:
  • Mean: Reflects the average of the data.
  • Median: The middle value in an ordered data set.
  • Mode: The most frequently occurring value in the data.
  • Variance and Standard Deviation: These measure the spread of the data points around the mean.
These measures are essential for analyzing the characteristics of a data set. They can tell you a lot about the central tendency, variability, and overall layout of the data. Using these metrics together gives you a comprehensive view of the data's distribution and helps to make informed statistical decisions.

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Most popular questions from this chapter

Explain how the value of the median is determined for a data set that contains an odd number of observations and for a data set that contains an even number of observations.

Jeffrey is serving on a six-person jury for a personal-injury lawsuit. All six jurors want to award damages to the plaintiff but cannot agree on the amount of the award. The jurors have decided that each of them will suggest an amount that he or she thinks should be awarded; then they will use the mean of these six numbers as the recommended amount to be awarded to the plaintiff. a. Jeffrey thinks the plaintiff should receive \(\$ 20,000\), but he thinks the mean of the other five jurors' recommendations will be about \(\$ 12,000 .\) He decides to suggest an inflated amount so that the mean for all six jurors is \(\$ 20,000\). What amount would Jeffrey have to suggest? b. How might this jury revise its procedure to prevent a juror like Jeffrey from having an undue influence on the amount of damages to be awarded to the plaintiff?

The following data give the odometer mileage (rounded to the nearest thousand miles) for all 20 cars that are for sale at a dealership. \(\begin{array}{llllllllll}62 & 86 & 58 & 84 & 72 & 40 & 27 & 38 & 50 & 43 \\\ 27 & 40 & 90 & 43 & 94 & 36 & 28 & 48 & 86 & 77\end{array}\) a. Calculate the values of the three quartiles and the interquartile range. Where does the number 77 fall in relation to these quartiles? b. Find the approximate value of the 18 th percentile. Give a brief interpretation of this percentile. c. Calculate the percentile rank of 72 . Give a brief interpretation of this percentile rank.

Each year the faculty at Metro Business College chooses 10 members from the current graduating class that they feel are most likely to succeed. The data below give the current annual incomes (in thousand dollars) of the 10 members of the class of 2009 who were voted most likely to succeed. \(\begin{array}{llllllllll}59 & 68 & 84 & 78 & 107 & 382 & 56 & 74 & 97 & 60\end{array}\) a. Determine the values of the three quartiles and the interquartile range. Where does the value of 74 fall in relation to these quartiles? b. Calculate the (approximate) value of the 70 th percentile. Give a brief interpretation of this percentile. c. Find the percentile rank of 97 . Give a brief interpretation of this percentile rank.

The following data represent the systolic blood pressure reading (that is, the top number in the standard blood pressure reading) in \(\mathrm{mmHg}\) for each of 20 randomly selected middle-aged males who were taking blood pressure medication. \(\begin{array}{llllllllll}139 & 151 & 138 & 153 & 134 & 136 & 141 & 126 & 109 & 144\end{array}\) \(\begin{array}{llllllllll}111 & 150 & 107 & 132 & 144 & 116 & 159 & 12.1 & 127 & 113\end{array}\) a. Calculate the mean, median, and mode for these data. b. Calculate the \(10 \%\) trimmed mean for these data.

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