/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 Gamma Corporation is considering... [FREE SOLUTION] | 91Ó°ÊÓ

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Gamma Corporation is considering the installation of governors on cars driven by its sales staff. These devices would limit the car speeds to a preset level, which is expected to improve fuel economy. The company is planning to test several cars for fuel consumption without governors for 1 week. Then governors would be installed in the same cars, and fuel consumption will be monitored for another week. Gamma Corporation wants to estimate the mean difference in fuel consumption with a margin of error of estimate of \(2 \mathrm{mpg}\) with a \(90 \%\) confidence level. Assume that the differences in fuel consumption are normally distributed and that previous studies suggest that an estimate of \(s_{d}=3 \mathrm{mpg}\) is reasonable. How many cars should be tested? (Note that the critical value of \(t\) will depend on \(n\), so it will be necessary to use trial and error.)

Short Answer

Expert verified
Gamma Corporation should test a minimum of 10 cars.

Step by step solution

01

Identify the Margin of Error, Confidence Level and Standard Deviation

The margin of error stated in the problem is 2 mpg, the set confidence level is 90%, and the assumed standard deviation from previous studies is 3 mpg.
02

Identify the t-value for the Chosen Confidence Level

This value can be found in a standard t-distribution table. The degree of freedom will be the tentative number of sample size -1. As the value depends on the number of cars, you need to use trial and error. Starting with a tentative sample size (for instance 15), df = 15 - 1 = 14. For a 90% confidence level, we usually use two-tail test, hence the cumulative probability is 0.95. Look for df = 14 and cumulative probability = 0.95 from t-distribution table which gives a t-value of approximately 1.761.
03

Use the margin of error formula for t-distribution

The formula can be written as: Margin Of Error = t * (s / sqrt(n)), where s = standard deviation, n = sample size, and t = t-value. Rearranging for n, we have: n = ((t * s) / Margin Of Error)^2.
04

Calculate the Sample Size

Substitute into the formula: n = ((1.761 * 3) / 2)^2 = approximately 9.9.
05

Round Up the Sample Size

Since we can't have a fraction of a car, we round up the resulting value to the next integer. In this case, rounding up 9.9 gives us a minimum of 10 cars that should be tested.
06

Verify the sample size

Iterate the calculation by updating the degree of freedom df = n - 1 = 9 which gives a t-value of approximately 1.833. And recalculate the sample size: n = ((1.833 * 3) / 2)^2 = approximately 9.3. As it is less than the initial estimate (10), the selected sample size of 10 is considered satisfactory.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
When we talk about confidence intervals, we refer to a range in which we are reasonably sure a parameter lies. Imagine you have a box of marbles but can only see a handful at a time. If you calculate the average size of these marbles several times, you'll get varying results. The confidence interval helps to say, "I am___% sure that the actual average marble size lies within these two numbers." In this exercise, Gamma Corporation is 90% confident about the average fuel consumption difference falling within a certain range. The wider the interval, the more cautious we are. Hence, choosing a confidence level like 90% indicates a balance between being reasonably sure and not having too large an interval.
The confidence level directly affects the t-value, which we use to pinpoint where our estimates fall within this range. It's crucial for deciding how large our sample—number of cars in this case—should be.
t-distribution
In statistics, a t-distribution resembles a normal distribution but with thicker tails. This means it reflects more variation expected when dealing with smaller samples. If you have a larger sample, these tails get "thinner," making the t-distribution more like a normal one. For smaller sample sizes, we rely on this distribution to ensure accurate results.
In the exercise with Gamma Corporation, we need the t-distribution because we don't know exactly how many cars will be enough beforehand. After estimating, you adjust your sample size using trial and error to match the required t-value for a 90% confidence level.
  • The t-distribution is essential when sample sizes are small or when population standard deviations are unknown.
  • As the sample size increases, the t-distribution resembles the normal distribution more closely.
Standard Deviation
Think of standard deviation as a measure of how spread out values are in a set of data. That means, in our case, how much variation there is in fuel consumption differences. If you picture a banana bunch, standard deviation can tell you whether most bananas are nearly the same size or very different. In terms of Gamma Corporation's problem, a standard deviation of 3 mpg indicates the average difference in fuel consumption varies by 3 miles per gallon from the mean.
Understanding this helps in determining how many cars need testing to achieve a desired accuracy in measurement. That number is critical because more variation usually requires a larger sample to maintain the confidence level.
Margin of Error
The margin of error represents the "wiggle room" allowed in results, which gives us an understanding of the range around an estimated value. For Gamma Corporation, a margin of error of 2 mpg means that the true average difference in fuel consumption will likely be within 2 mpg of our estimate.
  • The smaller the margin of error, the more precise the estimation, yet this requires a larger sample size.
  • Calculating the sample size involves balancing this margin with the desired confidence level, standard deviation, and the chosen t-value.
You'll notice in calculations, a smaller margin results in need for more cars to meet confidence standards. Also, it's vital when interpreting results because understanding if two variations are practically different hinges on the margin of error.

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Most popular questions from this chapter

Briefly explain the meaning of independent and dependent samples. Give one example of each.

The following information was obtained from two independent samples selected from two populations with unknown but equal standard deviations. $$ \begin{array}{lll} n_{1}=55 & \bar{x}_{1}=90.40 & s_{1}=11.60 \\ n_{2}=50 & \bar{x}_{2}=86.30 & s_{2}=10.25 \end{array} $$ Test at a \(1 \%\) significance level if the two population means are different.

The following information is obtained from two independent samples selected from two normally distributed populations. $$ \begin{array}{lll} n_{1}=18 & \bar{x}_{1}=7.82 & \sigma_{1}=2.35 \\ n_{2}=15 & \bar{x}_{2}=5.99 & \sigma_{2}=3.17 \end{array} $$ Test at a \(5 \%\) significance level if the two population means are different.

A local college cafeteria has a self-service soft ice cream machine. The cafeteria provides bowls that can hold up to 16 ounces of ice cream. The food service manager is interested in comparing the average amount of ice cream dispensed by male students to the average amount dispensed by female students. A measurement device was placed on the ice cream machine to determine the amounts dispensed. Random samples of 85 male and 78 female students who got ice cream were selected. The sample averages were \(7.23\) and \(6.49\) ounces for the male and female students, respectively. Assume that the population standard deviations are \(1.22\) and \(1.17\) ounces, respectively. a. Let \(\mu_{1}\) and \(\mu_{2}\) be the population means of ice cream amounts dispensed by all male and all female students at this college, respectively. What is the point estimate of \(\mu_{1}-\mu_{2} ?\) b. Construct a \(95 \%\) confidence interval for \(\mu_{1}-\mu_{2}\). c. Using a \(1 \%\) significance level, can you conclude that the average amount of ice cream dispensed by all male college students is larger than the average amount dispensed by all female college students? Use both approaches to make this test.

The lottery commissioner's office in a state wanted to find if the percentages of men and women who play the lottery often are different. A sample of 500 men taken by the commissioner's office showed that 160 of them play the lottery often. Another sample of 300 women showed that 66 of them play the lottery often. a. What is the point estimate of the difference between the two population proportions? b. Construct a 99\% confidence interval for the difference between the proportions of all men and all women who play the lottery often. c. Testing at a \(1 \%\) significance level, can you conclude that the proportions of all men and all women who play the lottery often are different?

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