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a. A sample of 1100 observations taken from a population produced a sample proportion of .32. Make a \(90 \%\) confidence interval for \(p\). b. Another sample of 1100 observations taken from the same population produced a sample proportion of .36. Make a \(90 \%\) confidence interval for \(p\). c. A third sample of 1100 observations taken from the same population produced a sample proportion of .30. Make a \(90 \%\) confidence interval for \(p\). d. The true population proportion for this population is \(.34 .\) Which of the confidence intervals constructed in parts a through c cover this population proportion and which do not?

Short Answer

Expert verified
The confidence intervals for samples are as follows: Sample 1: 0.302 to 0.338, Sample 2: 0.342 to 0.378, Sample 3: 0.282 to 0.318. Comparing these intervals to the true population proportion (0.34), it is seen that only the confidence interval for the second sample covers the true population proportion.

Step by step solution

01

Confidence Interval Calculation for Sample 1

Firstly the confidence interval for the first sample is calculated. The sample size (n) is 1100 and the sample proportion (p) is 0.32. The one-tailed z-score for a 90% confidence interval (\(Z\)) is 1.645.\nThe confidence interval is given by \(0.32 \pm 1.645 * \sqrt{ \frac{0.32 (1 - 0.32)}{1100}}\). Calculate this to find the confidence interval for the first sample.
02

Confidence Interval Calculation for Sample 2

Similarly, for the second sample, \(n = 1100\) and \(p = 0.36.\)\nThe confidence interval is \(0.36 \pm 1.645 * \sqrt{ \frac{0.36 (1 - 0.36)}{1100}}\). Calculate this to find the confidence interval for the second sample.
03

Confidence Interval Calculation for Sample 3

For the third sample, \(n = 1100\) and \(p = 0.30.\)\nThe confidence interval is \(0.30 \pm 1.645 * \sqrt{ \frac{0.30 (1 - 0.30)}{1100}}\). Calculate this to find the confidence interval for the third sample.
04

Compare the intervals with the true population

The calculated confidence intervals need to be compared with the true population proportion which is \(0.34\). If the true population proportion lies within the confidence interval of the sample, then we can say that the sample covers the population proportion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
The sample proportion is a critical concept in statistics, particularly when dealing with confidence intervals. It refers to the ratio or fraction of members in a sample that have a particular attribute. For example, in the original exercise, three different samples are considered, and each sample has its own proportion: 0.32, 0.36, and 0.30. These numbers indicate the fraction of the sample that exhibits a certain characteristic.
Understanding the sample proportion is essential since it serves as a starting point for estimating the population proportion. It provides an accessible way to make educated guesses about a larger population based on a smaller, manageable group. This is achieved by conducting surveys or experiments and analyzing the results.

Key points about sample proportion:
  • It is denoted as \( \hat{p} \) and is calculated by dividing the number of favorable outcomes by the total sample size.
  • It is used in the formula for constructing confidence intervals.
  • Provides insight into the likelihood of an event occurring within a sample.
The sample proportion acts as the estimate and foundation for creating a confidence interval.
Population Proportion
The population proportion represents the fraction of a population that possesses a particular attribute. Unlike the sample proportion, the population proportion is fixed and does not vary; however, it is often unknown. In statistics, the aim is to estimate this value as accurately as possible using data from samples.
The population proportion in the original exercise is labeled as 0.34, meaning that 34% of the whole population is expected to exhibit a certain characteristic. Determining how close the sample estimates are to this true population proportion is crucial for validating findings from statistical analyses.

Important aspects of the population proportion:
  • It is denoted as \( p \).
  • It serves as the true value that we aim to estimate through sampling.
  • It does not change, even though different samples may yield varying sample proportions.
Assessing how sample proportions compare to the population proportion enables understanding of the reliability of sample-based inferences.
Z-score
The z-score is a statistic that reflects the number of standard deviations an element is from the mean. In confidence interval calculations, the z-score is pivotal as it determines the margin of error. For a 90% confidence interval, a specific z-score value of 1.645 is typically utilized.
By incorporating the z-score into confidence interval calculations, we can quantify the accuracy of the sample statistics as predictions of the overall population. The margin of error is computed as the z-score multiplied by the standard error of the sample proportion.

Key concepts of z-score usage:
  • Z-score values change based on the desired confidence level. The higher the confidence level, the larger the z-score in absolute terms.
  • Z-scores are found in standard normal distribution tables and vary according to different confidence levels.
  • They provide an indication of the spread or variability within data relative to the national standard.
Utilizing the appropriate z-score guarantees that the confidence interval bounds are accurately established, promoting valid statistical analysis.
Sample Size
Sample size refers to the number of observations or data points collected from a population to conduct an analysis. It is a crucial component in constructing a confidence interval. In the original problem, a sample size of 1100 is used consistently across all examples.
A larger sample size generally leads to more accurate and reliable confidence intervals since it tends to reduce the standard error. The larger the sample, the closer the sample statistic (such as the mean or proportion) is expected to be to the true population parameter.

Important elements of sample size:
  • The sample size is denoted as \( n \).
  • Larger sample sizes tend to yield more precise interval estimates.
  • It affects the width of the confidence interval: larger samples result in narrower intervals, signaling higher precision.
Evaluating sample size is essential in ensuring that the statistical analysis has enough power and precision to make trustworthy conclusions about the population.

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Most popular questions from this chapter

a. How large a sample should be selected so that the margin of error of estimate for a \(99 \%\) confidence interval for \(p\) is \(.035\) when the value of the sample proportion obtained from a preliminary sample is \(.29 ?\) b. Find the most conservative sample size that will produce the margin of error for a \(99 \%\) confidence interval for \(p\) equal to \(.035\).

It is said that happy and healthy workers are efficient and productive. A company that manufactures exercising machines wanted to know the percentage of large companies that provide on-site health club facilities. A sample of 240 such companies showed that 96 of them provide such facilities on site. a. What is the point estimate of the percentage of all such companies that provide such facilities on site? b. Construct a \(97 \%\) confidence interval for the percentage of all such companies that provide such facilities on site. What is the margin of error for this estimate?

a. A sample of 400 observations taken from a population produced a sample mean equal to \(92.45\) and a standard deviation equal to \(12.20 .\) Make a \(98 \%\) confidence interval for \(\mu\). b. Another sample of 400 observations taken from the same population produced a sample mean equal to \(91.75\) and a standard deviation equal to \(14.50 .\) Make a \(98 \%\) confidence interval for \(\mu .\) c. A third sample of 400 observations taken from the same population produced a sample mean equal to \(89.63\) and a standard deviation equal to \(13.40 .\) Make a \(98 \%\) confidence interval for \(\mu\). d. The true population mean for this population is \(90.65 .\) Which of the confidence intervals constructed in parts a through c cover this population mean and which do not?

You are interested in estimating the mean commuting time from home to school for all commuter students at your school. Briefly explain the procedure you will follow to conduct this study. Collect the required data from a sample of 30 or more such students and then estimate the population mean at a \(99 \%\) confidence level. Assume that the population standard deviation for such times is \(5.5\) minutes.

At Farmer's Dairy, a machine is set to fill 32 -ounce milk cartons. However, this machine does not put exactly 32 ounces of milk into each carton; the amount varies slightly from carton to carton. It is known that when the machine is working properly, the mean net weight of these cartons is 32 ounces. The standard deviation of the amounts of milk in all such cartons is always equal to \(.15\) ounce. The quality control department takes a sample of 25 such cartons every week, calculates the mean net weight of these cartons, and makes a \(99 \%\) confidence interval for the population mean. If either the upper limit of this confidence interval is greater than \(32.15\) ounces or the lower limit of this confidence interval is less than \(31.85\) ounces, the machine is stopped and adjusted. A recent sample of 25 such cartons produced a mean net weight of \(31.94\) ounces. Based on this sample, will you conclude that the machine needs an adjustment? Assume that the amounts of milk put in all such cartons have a normal distribution.

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